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Latitudes and Departures

Surveying · FE Reference Handbook section

Surveying
0 formulas
10 exam-style examples
~45 min
All Surveying lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

This section is conceptual; there are no equations to memorise.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Traverse closure and precision

A closed traverse has ΣLatitudes = +0.084 m and ΣDepartures = −0.112 m over a total length of 1,240 m. Find the linear misclosure and the precision.

Given

  • ΣLat = +0.084 m

  • ΣDep = −0.112 m

  • Perimeter=1,240mPerimeter = 1,240 m

Find

Misclosure and precision ratio

Start with the thinking

  • Misclosure is the vector sum of the two errors.
  • Precision is expressed as 1 in N.

Step-by-step solution

  1. Misclosure

    e=(0.0842+0.1122)=(0.00706+0.01254)e = \sqrt(0.084^{2} + 0.112^{2}) = \sqrt(0.00706 + 0.01254)
  2. Evaluate

    e=0.01960=0.140me = \sqrt0.01960 = 0.140 m
  3. Precision

    P=e/perimeter=0.140/1,240=1.13×10−4P = e/perimeter = 0.140/1,240 = 1.13\times10^{-4}
  4. Express

    1:1/1.13×10−4=1:8,8601 : 1/1.13\times10^{-4} = 1 : 8,860
Answer:
e=0.140m;precision≈1:8,900e = 0.140 m; precision \approx 1:8,900

Why the other options are there

  • e = 0.196 m (errors added directly)
  • 1:1,240 (perimeter reported as precision)

Reference: FE Reference Handbook — Surveying — Traverse computations

Example 2
Traverse latitude — solve for latitude — Latitudes and Departures

A surveying problem uses Traverse latitude. Given course length (L) = 438.0 ft; bearing angle (theta) = 38.0000 deg, determine the latitude (Lat) in ft.

Given

  • courselength(L)=438.0ftcourse length (L) = 438.0 ft
  • bearingangle(theta)=38.0000degbearing angle (theta) = 38.0000 deg

Find

latitude (Lat), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except Lat is given, so isolate Lat symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that Lat stands alone on the left-hand side.

  3. Step 3

    Listthegivens:courselength(L)=438.0ft,bearingangle(theta)=38.0000degList the givens: course length (L) = 438.0 ft, bearing angle (theta) = 38.0000 deg
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lat=345.1 ftLat = 345.1\ \text{ft}
  6. Step 6 — Check: returning Lat = 345.1 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lat=345.1 ftLat = 345.1\ \text{ft}

Why the other options are there

  • 690.3 — kept a factor of two that cancels in the correct rearrangement.
  • 172.6 — dropped that same factor in the other direction.
  • 379.7 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 3
Traverse latitude — solve for course length — Latitudes and Departures (2)

A surveying problem uses Traverse latitude. Given bearing angle (theta) = 6.0000 deg; latitude (Lat) = 697.9 ft, determine the course length (L) in ft.

Given

  • bearingangle(theta)=6.0000degbearing angle (theta) = 6.0000 deg
  • latitude(Lat)=697.9ftlatitude (Lat) = 697.9 ft

Find

course length (L), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except L is given, so isolate L symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that L stands alone on the left-hand side.

  3. Step 3

    Listthegivens:bearingangle(theta)=6.0000deg,latitude(Lat)=697.9ftList the givens: bearing angle (theta) = 6.0000 deg, latitude (Lat) = 697.9 ft
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L=701.7 ftL = 701.7\ \text{ft}
  6. Step 6 — Check: returning L = 701.7 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
L=701.7 ftL = 701.7\ \text{ft}

Why the other options are there

  • 1,403 — kept a factor of two that cancels in the correct rearrangement.
  • 350.9 — dropped that same factor in the other direction.
  • 771.9 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 4
Traverse latitude — solve for latitude (case 2) — Latitudes and Departures (3)

A surveying problem uses Traverse latitude. Given course length (L) = 426.0 ft; bearing angle (theta) = 74.0000 deg, determine the latitude (Lat) in ft.

Given

  • courselength(L)=426.0ftcourse length (L) = 426.0 ft
  • bearingangle(theta)=74.0000degbearing angle (theta) = 74.0000 deg

Find

latitude (Lat), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except Lat is given, so isolate Lat symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that Lat stands alone on the left-hand side.

  3. Step 3

    Listthegivens:courselength(L)=426.0ft,bearingangle(theta)=74.0000degList the givens: course length (L) = 426.0 ft, bearing angle (theta) = 74.0000 deg
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lat=117.4 ftLat = 117.4\ \text{ft}
  6. Step 6 — Check: returning Lat = 117.4 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lat=117.4 ftLat = 117.4\ \text{ft}

Why the other options are there

  • 234.8 — kept a factor of two that cancels in the correct rearrangement.
  • 58.7108 — dropped that same factor in the other direction.
  • 129.2 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 5
Traverse latitude — solve for course length (case 2) — Latitudes and Departures (4)

A surveying problem uses Traverse latitude. Given bearing angle (theta) = 6.0000 deg; latitude (Lat) = 294.1 ft, determine the course length (L) in ft.

Given

  • bearingangle(theta)=6.0000degbearing angle (theta) = 6.0000 deg
  • latitude(Lat)=294.1ftlatitude (Lat) = 294.1 ft

Find

course length (L), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except L is given, so isolate L symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that L stands alone on the left-hand side.

  3. Step 3

    Listthegivens:bearingangle(theta)=6.0000deg,latitude(Lat)=294.1ftList the givens: bearing angle (theta) = 6.0000 deg, latitude (Lat) = 294.1 ft
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L=295.7 ftL = 295.7\ \text{ft}
  6. Step 6 — Check: returning L = 295.7 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
L=295.7 ftL = 295.7\ \text{ft}

Why the other options are there

  • 591.4 — kept a factor of two that cancels in the correct rearrangement.
  • 147.9 — dropped that same factor in the other direction.
  • 325.3 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 6
Traverse latitude — solve for latitude (case 3) — Latitudes and Departures (5)

A surveying problem uses Traverse latitude. Given course length (L) = 60.0000 ft; bearing angle (theta) = 41.0000 deg, determine the latitude (Lat) in ft.

Given

  • courselength(L)=60.0000ftcourse length (L) = 60.0000 ft
  • bearingangle(theta)=41.0000degbearing angle (theta) = 41.0000 deg

Find

latitude (Lat), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except Lat is given, so isolate Lat symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that Lat stands alone on the left-hand side.

  3. Step 3

    Listthegivens:courselength(L)=60.0000ft,bearingangle(theta)=41.0000degList the givens: course length (L) = 60.0000 ft, bearing angle (theta) = 41.0000 deg
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lat=45.2826 ftLat = 45.2826\ \text{ft}
  6. Step 6 — Check: returning Lat = 45.2826 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lat=45.2826 ftLat = 45.2826\ \text{ft}

Why the other options are there

  • 90.5651 — kept a factor of two that cancels in the correct rearrangement.
  • 22.6413 — dropped that same factor in the other direction.
  • 49.8108 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 7
Traverse latitude — solve for course length (case 3) — Latitudes and Departures (6)

A surveying problem uses Traverse latitude. Given bearing angle (theta) = 54.0000 deg; latitude (Lat) = 542.1 ft, determine the course length (L) in ft.

Given

  • bearingangle(theta)=54.0000degbearing angle (theta) = 54.0000 deg
  • latitude(Lat)=542.1ftlatitude (Lat) = 542.1 ft

Find

course length (L), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except L is given, so isolate L symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that L stands alone on the left-hand side.

  3. Step 3

    Listthegivens:bearingangle(theta)=54.0000deg,latitude(Lat)=542.1ftList the givens: bearing angle (theta) = 54.0000 deg, latitude (Lat) = 542.1 ft
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L=922.3 ftL = 922.3\ \text{ft}
  6. Step 6 — Check: returning L = 922.3 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
L=922.3 ftL = 922.3\ \text{ft}

Why the other options are there

  • 1,845 — kept a factor of two that cancels in the correct rearrangement.
  • 461.1 — dropped that same factor in the other direction.
  • 1,015 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 8
Traverse latitude — solve for latitude (case 4) — Latitudes and Departures (7)

A surveying problem uses Traverse latitude. Given course length (L) = 138.0 ft; bearing angle (theta) = 73.0000 deg, determine the latitude (Lat) in ft.

Given

  • courselength(L)=138.0ftcourse length (L) = 138.0 ft
  • bearingangle(theta)=73.0000degbearing angle (theta) = 73.0000 deg

Find

latitude (Lat), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except Lat is given, so isolate Lat symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that Lat stands alone on the left-hand side.

  3. Step 3

    Listthegivens:courselength(L)=138.0ft,bearingangle(theta)=73.0000degList the givens: course length (L) = 138.0 ft, bearing angle (theta) = 73.0000 deg
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lat=40.3473 ftLat = 40.3473\ \text{ft}
  6. Step 6 — Check: returning Lat = 40.3473 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lat=40.3473 ftLat = 40.3473\ \text{ft}

Why the other options are there

  • 80.6946 — kept a factor of two that cancels in the correct rearrangement.
  • 20.1736 — dropped that same factor in the other direction.
  • 44.3820 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 9
Traverse latitude — solve for course length (case 4) — Latitudes and Departures (8)

A surveying problem uses Traverse latitude. Given bearing angle (theta) = 65.0000 deg; latitude (Lat) = 279.1 ft, determine the course length (L) in ft.

Given

  • bearingangle(theta)=65.0000degbearing angle (theta) = 65.0000 deg
  • latitude(Lat)=279.1ftlatitude (Lat) = 279.1 ft

Find

course length (L), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except L is given, so isolate L symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that L stands alone on the left-hand side.

  3. Step 3

    Listthegivens:bearingangle(theta)=65.0000deg,latitude(Lat)=279.1ftList the givens: bearing angle (theta) = 65.0000 deg, latitude (Lat) = 279.1 ft
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L=660.4 ftL = 660.4\ \text{ft}
  6. Step 6 — Check: returning L = 660.4 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
L=660.4 ftL = 660.4\ \text{ft}

Why the other options are there

  • 1,321 — kept a factor of two that cancels in the correct rearrangement.
  • 330.2 — dropped that same factor in the other direction.
  • 726.4 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

Example 10
Traverse latitude — solve for latitude (case 5) — Latitudes and Departures (9)

A surveying problem uses Traverse latitude. Given course length (L) = 262.0 ft; bearing angle (theta) = 22.0000 deg, determine the latitude (Lat) in ft.

Given

  • courselength(L)=262.0ftcourse length (L) = 262.0 ft
  • bearingangle(theta)=22.0000degbearing angle (theta) = 22.0000 deg

Find

latitude (Lat), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Traverse latitude.
  • Everything except Lat is given, so isolate Lat symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Surveying items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)
  2. Step 2 — Rearrange the relation so that Lat stands alone on the left-hand side.

  3. Step 3

    Listthegivens:courselength(L)=262.0ft,bearingangle(theta)=22.0000degList the givens: course length (L) = 262.0 ft, bearing angle (theta) = 22.0000 deg
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lat=242.9 ftLat = 242.9\ \text{ft}
  6. Step 6 — Check: returning Lat = 242.9 ft to

    Lat=Lcos⁡(θ)Lat = L \cos(\theta)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lat=242.9 ftLat = 242.9\ \text{ft}

Why the other options are there

  • 485.8 — kept a factor of two that cancels in the correct rearrangement.
  • 121.5 — dropped that same factor in the other direction.
  • 267.2 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Surveying → Latitudes and Departures

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