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Moving Concentrated Load Sets

Structural Analysis · FE Reference Handbook section

Structural Analysis
0 formulas
10 exam-style examples
~45 min
All Structural Analysis lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • The absolute maximum moment produced in a beam by a set of "n" moving loads occurs when the resultant "R" of the load
  • set and an adjacent load are equal distance from the centerline of the beam. In general, two possible load set positions must be
  • considered, one for each adjacent load.

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

This section is conceptual; there are no equations to memorise.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets

A simple span of 55 ft carries a moving load set of 28 kips and 23 kips spaced 8 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=55ftL = 55 ft
  • P1=28kips,P2=23kipsP_{1} = 28 kips, P_{2} = 23 kips
  • Spacing=8ftSpacing = 8 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=28+23=51kipsR = 28 + 23 = 51 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=23(8)/51=3.608ftx̄ = 23(8)/51 = 3.608 ft
  4. Critical offset

    e=xˉ/2=1.804ftfrommidspane = x̄/2 = 1.804 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (51/55)(27.5 − 1.804)² = 612.3 kip·ft

Answer:

M_abs,max ≈ 612.3 kip·ft

Why the other options are there

  • 701.3 kip·ft (single load at midspan)
  • 350.6 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 2
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (2)

A simple span of 80 ft carries a moving load set of 11 kips and 16 kips spaced 10 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=80ftL = 80 ft
  • P1=11kips,P2=16kipsP_{1} = 11 kips, P_{2} = 16 kips
  • Spacing=10ftSpacing = 10 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=11+16=27kipsR = 11 + 16 = 27 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=16(10)/27=5.926ftx̄ = 16(10)/27 = 5.926 ft
  4. Critical offset

    e=xˉ/2=2.963ftfrommidspane = x̄/2 = 2.963 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (27/80)(40 − 2.963)² = 463.0 kip·ft

Answer:

M_abs,max ≈ 463.0 kip·ft

Why the other options are there

  • 540.0 kip·ft (single load at midspan)
  • 270.0 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 3
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (3)

A simple span of 73 ft carries a moving load set of 14 kips and 21 kips spaced 13 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=73ftL = 73 ft
  • P1=14kips,P2=21kipsP_{1} = 14 kips, P_{2} = 21 kips
  • Spacing=13ftSpacing = 13 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=14+21=35kipsR = 14 + 21 = 35 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=21(13)/35=7.800ftx̄ = 21(13)/35 = 7.800 ft
  4. Critical offset

    e=xˉ/2=3.900ftfrommidspane = x̄/2 = 3.900 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (35/73)(36.5 − 3.900)² = 509.5 kip·ft

Answer:

M_abs,max ≈ 509.5 kip·ft

Why the other options are there

  • 638.8 kip·ft (single load at midspan)
  • 319.4 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 4
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (4)

A simple span of 81 ft carries a moving load set of 11 kips and 16 kips spaced 12 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=81ftL = 81 ft
  • P1=11kips,P2=16kipsP_{1} = 11 kips, P_{2} = 16 kips
  • Spacing=12ftSpacing = 12 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=11+16=27kipsR = 11 + 16 = 27 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=16(12)/27=7.111ftx̄ = 16(12)/27 = 7.111 ft
  4. Critical offset

    e=xˉ/2=3.556ftfrommidspane = x̄/2 = 3.556 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (27/81)(40.5 − 3.556)² = 455.0 kip·ft

Answer:

M_abs,max ≈ 455.0 kip·ft

Why the other options are there

  • 546.8 kip·ft (single load at midspan)
  • 273.4 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 5
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (5)

A simple span of 62 ft carries a moving load set of 21 kips and 16 kips spaced 16 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=62ftL = 62 ft
  • P1=21kips,P2=16kipsP_{1} = 21 kips, P_{2} = 16 kips
  • Spacing=16ftSpacing = 16 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=21+16=37kipsR = 21 + 16 = 37 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=16(16)/37=6.919ftx̄ = 16(16)/37 = 6.919 ft
  4. Critical offset

    e=xˉ/2=3.459ftfrommidspane = x̄/2 = 3.459 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (37/62)(31 − 3.459)² = 452.6 kip·ft

Answer:

M_abs,max ≈ 452.6 kip·ft

Why the other options are there

  • 573.5 kip·ft (single load at midspan)
  • 286.8 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 6
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (6)

A simple span of 40 ft carries a moving load set of 26 kips and 12 kips spaced 8 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=40ftL = 40 ft
  • P1=26kips,P2=12kipsP_{1} = 26 kips, P_{2} = 12 kips
  • Spacing=8ftSpacing = 8 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=26+12=38kipsR = 26 + 12 = 38 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=12(8)/38=2.526ftx̄ = 12(8)/38 = 2.526 ft
  4. Critical offset

    e=xˉ/2=1.263ftfrommidspane = x̄/2 = 1.263 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (38/40)(20 − 1.263)² = 333.5 kip·ft

Answer:

M_abs,max ≈ 333.5 kip·ft

Why the other options are there

  • 380.0 kip·ft (single load at midspan)
  • 190.0 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 7
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (7)

A simple span of 54 ft carries a moving load set of 22 kips and 26 kips spaced 7 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=54ftL = 54 ft
  • P1=22kips,P2=26kipsP_{1} = 22 kips, P_{2} = 26 kips
  • Spacing=7ftSpacing = 7 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=22+26=48kipsR = 22 + 26 = 48 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=26(7)/48=3.792ftx̄ = 26(7)/48 = 3.792 ft
  4. Critical offset

    e=xˉ/2=1.896ftfrommidspane = x̄/2 = 1.896 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (48/54)(27 − 1.896)² = 560.2 kip·ft

Answer:

M_abs,max ≈ 560.2 kip·ft

Why the other options are there

  • 648.0 kip·ft (single load at midspan)
  • 324.0 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 8
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (8)

A simple span of 88 ft carries a moving load set of 15 kips and 29 kips spaced 9 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=88ftL = 88 ft
  • P1=15kips,P2=29kipsP_{1} = 15 kips, P_{2} = 29 kips
  • Spacing=9ftSpacing = 9 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=15+29=44kipsR = 15 + 29 = 44 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=29(9)/44=5.932ftx̄ = 29(9)/44 = 5.932 ft
  4. Critical offset

    e=xˉ/2=2.966ftfrommidspane = x̄/2 = 2.966 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (44/88)(44 − 2.966)² = 841.9 kip·ft

Answer:

M_abs,max ≈ 841.9 kip·ft

Why the other options are there

  • 968.0 kip·ft (single load at midspan)
  • 484.0 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 9
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (9)

A simple span of 41 ft carries a moving load set of 21 kips and 26 kips spaced 9 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=41ftL = 41 ft
  • P1=21kips,P2=26kipsP_{1} = 21 kips, P_{2} = 26 kips
  • Spacing=9ftSpacing = 9 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=21+26=47kipsR = 21 + 26 = 47 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=26(9)/47=4.979ftx̄ = 26(9)/47 = 4.979 ft
  4. Critical offset

    e=xˉ/2=2.489ftfrommidspane = x̄/2 = 2.489 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (47/41)(20.5 − 2.489)² = 371.9 kip·ft

Answer:

M_abs,max ≈ 371.9 kip·ft

Why the other options are there

  • 481.8 kip·ft (single load at midspan)
  • 240.9 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

Example 10
Absolute maximum moment from a moving concentrated load set — Moving Concentrated Load Sets (10)

A simple span of 49 ft carries a moving load set of 22 kips and 24 kips spaced 7 ft apart. Locate the resultant, then compute the absolute maximum moment under the heavier wheel.

Given

  • L=49ftL = 49 ft
  • P1=22kips,P2=24kipsP_{1} = 22 kips, P_{2} = 24 kips
  • Spacing=7ftSpacing = 7 ft

Find

Resultant position and absolute maximum moment

Start with the thinking

  • For a moving concentrated load set, the absolute maximum moment occurs when the span centreline bisects the distance between the resultant and the wheel considered.
  • Influence-line reasoning locates the critical position before any statics is done.

Step-by-step solution

  1. Resultant

    R=22+24=46kipsR = 22 + 24 = 46 kips
  2. Formula — x̄ = ΣP d / ΣP (measured from P₁)

  3. Substituting

    xˉ=24(7)/46=3.652ftx̄ = 24(7)/46 = 3.652 ft
  4. Critical offset

    e=xˉ/2=1.826ftfrommidspane = x̄/2 = 1.826 ft from midspan
  5. Formula

    Mmax=(R/L)(L/2−e)2M_max = (R/L)(L/2 - e)^{2}
  6. Substituting — M = (46/49)(24.5 − 1.826)² = 482.6 kip·ft

Answer:

M_abs,max ≈ 482.6 kip·ft

Why the other options are there

  • 563.5 kip·ft (single load at midspan)
  • 281.8 kip·ft (uniform-load formula)

Reference: FE Reference Handbook — Structural Analysis → Moving Concentrated Load Sets

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