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Sample Size

Probability and Statistics · FE Reference Handbook section

Probability and Statistics
1 formulas
10 exam-style examples
~47 min
All Probability and Statistics lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Sample size required for a target margin of error — Sample Size

Concrete strength has a known standard deviation of 185.0 psi. How many cylinders must be tested so that the mean is estimated within ±11 psi at a z of 2.576?

Given

  • σ=185.0psi\sigma = 185.0 psi
  • E=11psiE = 11 psi
  • z=2.576z = 2.576

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(2.576×185.0/11)2n = (2.576 \times 185.0 / 11)^{2}
  3. Inside the bracket — 43.3236

  4. Evaluate

    n=1,877→1877specimensn = 1,877 \to 1877 specimens
Answer:
n=1877specimensn = 1877 specimens

Why the other options are there

  • 44 (forgot to square)
  • 939 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 2
Sample size required for a target margin of error — Sample Size (2)

Concrete strength has a known standard deviation of 210.0 psi. How many cylinders must be tested so that the mean is estimated within ±42 psi at a z of 1.645?

Given

  • σ=210.0psi\sigma = 210.0 psi
  • E=42psiE = 42 psi
  • z=1.645z = 1.645

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(1.645×210.0/42)2n = (1.645 \times 210.0 / 42)^{2}
  3. Inside the bracket — 8.2250

  4. Evaluate

    n=67.65→68specimensn = 67.65 \to 68 specimens
Answer:
n=68specimensn = 68 specimens

Why the other options are there

  • 9 (forgot to square)
  • 34 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 3
Sample size required for a target margin of error — Sample Size (3)

Concrete strength has a known standard deviation of 165.0 psi. How many cylinders must be tested so that the mean is estimated within ±21 psi at a z of 1.645?

Given

  • σ=165.0psi\sigma = 165.0 psi
  • E=21psiE = 21 psi
  • z=1.645z = 1.645

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(1.645×165.0/21)2n = (1.645 \times 165.0 / 21)^{2}
  3. Inside the bracket — 12.9250

  4. Evaluate

    n=167.1→168specimensn = 167.1 \to 168 specimens
Answer:
n=168specimensn = 168 specimens

Why the other options are there

  • 13 (forgot to square)
  • 84 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 4
Sample size required for a target margin of error — Sample Size (4)

Concrete strength has a known standard deviation of 185.0 psi. How many cylinders must be tested so that the mean is estimated within ±46 psi at a z of 1.96?

Given

  • σ=185.0psi\sigma = 185.0 psi
  • E=46psiE = 46 psi
  • z=1.96z = 1.96

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(1.96×185.0/46)2n = (1.96 \times 185.0 / 46)^{2}
  3. Inside the bracket — 7.8826

  4. Evaluate

    n=62.14→63specimensn = 62.14 \to 63 specimens
Answer:
n=63specimensn = 63 specimens

Why the other options are there

  • 8 (forgot to square)
  • 32 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 5
Sample size required for a target margin of error — Sample Size (5)

Concrete strength has a known standard deviation of 270.0 psi. How many cylinders must be tested so that the mean is estimated within ±49 psi at a z of 2.576?

Given

  • σ=270.0psi\sigma = 270.0 psi
  • E=49psiE = 49 psi
  • z=2.576z = 2.576

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(2.576×270.0/49)2n = (2.576 \times 270.0 / 49)^{2}
  3. Inside the bracket — 14.1943

  4. Evaluate

    n=201.5→202specimensn = 201.5 \to 202 specimens
Answer:
n=202specimensn = 202 specimens

Why the other options are there

  • 15 (forgot to square)
  • 101 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 6
Sample size required for a target margin of error — Sample Size (6)

Concrete strength has a known standard deviation of 305.0 psi. How many cylinders must be tested so that the mean is estimated within ±19 psi at a z of 2.576?

Given

  • σ=305.0psi\sigma = 305.0 psi
  • E=19psiE = 19 psi
  • z=2.576z = 2.576

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(2.576×305.0/19)2n = (2.576 \times 305.0 / 19)^{2}
  3. Inside the bracket — 41.3516

  4. Evaluate

    n=1,710→1710specimensn = 1,710 \to 1710 specimens
Answer:
n=1710specimensn = 1710 specimens

Why the other options are there

  • 42 (forgot to square)
  • 855 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 7
Sample size required for a target margin of error — Sample Size (7)

Concrete strength has a known standard deviation of 385.0 psi. How many cylinders must be tested so that the mean is estimated within ±46 psi at a z of 1.96?

Given

  • σ=385.0psi\sigma = 385.0 psi
  • E=46psiE = 46 psi
  • z=1.96z = 1.96

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(1.96×385.0/46)2n = (1.96 \times 385.0 / 46)^{2}
  3. Inside the bracket — 16.4043

  4. Evaluate

    n=269.1→270specimensn = 269.1 \to 270 specimens
Answer:
n=270specimensn = 270 specimens

Why the other options are there

  • 17 (forgot to square)
  • 135 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 8
Sample size required for a target margin of error — Sample Size (8)

Concrete strength has a known standard deviation of 295.0 psi. How many cylinders must be tested so that the mean is estimated within ±49 psi at a z of 1.645?

Given

  • σ=295.0psi\sigma = 295.0 psi
  • E=49psiE = 49 psi
  • z=1.645z = 1.645

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(1.645×295.0/49)2n = (1.645 \times 295.0 / 49)^{2}
  3. Inside the bracket — 9.9036

  4. Evaluate

    n=98.08→99specimensn = 98.08 \to 99 specimens
Answer:
n=99specimensn = 99 specimens

Why the other options are there

  • 10 (forgot to square)
  • 50 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 9
Sample size required for a target margin of error — Sample Size (9)

Concrete strength has a known standard deviation of 295.0 psi. How many cylinders must be tested so that the mean is estimated within ±41 psi at a z of 1.645?

Given

  • σ=295.0psi\sigma = 295.0 psi
  • E=41psiE = 41 psi
  • z=1.645z = 1.645

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(1.645×295.0/41)2n = (1.645 \times 295.0 / 41)^{2}
  3. Inside the bracket — 11.8360

  4. Evaluate

    n=140.1→141specimensn = 140.1 \to 141 specimens
Answer:
n=141specimensn = 141 specimens

Why the other options are there

  • 12 (forgot to square)
  • 71 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

Example 10
Sample size required for a target margin of error — Sample Size (10)

Concrete strength has a known standard deviation of 335.0 psi. How many cylinders must be tested so that the mean is estimated within ±21 psi at a z of 1.96?

Given

  • σ=335.0psi\sigma = 335.0 psi
  • E=21psiE = 21 psi
  • z=1.96z = 1.96

Find

Required sample size n

Start with the thinking

  • Sample size scales with the square of the ratio σ/E — halving the margin quadruples the testing.
  • Always round the computed sample size up to the next whole specimen.

Step-by-step solution

  1. Formula

    n=(zσ/E)2n = (z \sigma / E)^{2}
  2. Substituting

    n=(1.96×335.0/21)2n = (1.96 \times 335.0 / 21)^{2}
  3. Inside the bracket — 31.2667

  4. Evaluate

    n=977.6→978specimensn = 977.6 \to 978 specimens
Answer:
n=978specimensn = 978 specimens

Why the other options are there

  • 32 (forgot to square)
  • 489 (halved the requirement)

Reference: FE Reference Handbook — Probability and Statistics → Sample Size

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