Normal Distribution (Gaussian Distribution)
Probability and Statistics · FE Reference Handbook section
Handbook notes for this section
Definitions and conditions exactly as the handbook states them.
- of the mode). The averages of n observations tend to become normally distributed as n increases. The variate x is said to be
- normally distributed if its density function f (x) is given by an expression of the form
- A unit normal distribution table is included at the end of this section. In the table, the following notations are utilized:
- distribution can be used by utilizing the following transformation:
- The Central Limit Theorem
- Let X1, X2, ..., Xn be a sequence of independent and identically distributed random variables each having mean µ and variance
- and the standard deviation
- Engineering Probability and Statistics
- Student's t-distribution has the probability density function given by:
- If Z1, Z2, ..., Zn are independent unit normal random variables, then
Core formulas for this FE topic
Definitions, applicability, units, assumptions and worked examples for each relation.
Worked exam-style examples
The four ways this section is written on the real exam — thoughts first, then equations, then substitution.
A probability and statistics problem uses z-score. Given mean (mu) = 3,420 psi; std deviation (sigma) = 150.0 psi; value (x) = 6,300 psi, determine the z-score (z).
Given
Find
z-score (z)
Start with the thinking
- The governing relation printed in this handbook section is z-score.
- Everything except z is given, so isolate z symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Probability and Statistics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that z stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning z = 19.2000 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 38.4000 — kept a factor of two that cancels in the correct rearrangement.
- 9.6000 — dropped that same factor in the other direction.
- 21.1200 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Probability and Statistics → Normal Distribution (Gaussian Distribution)
A quality analyst uses the Gaussian distribution to find a z-score for a measurement. Given mean (mu) = 53.0000; std deviation (sigma) = 16.0000; value (x) = 112.0, determine the z-score (z).
Given
Find
z-score (z)
Start with the thinking
- The governing relation printed in this handbook section is Normal (Gaussian) distribution z-transform.
- Everything except z is given, so isolate z symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- The normal distribution (Gaussian distribution) standardizes a value x using its mean and standard deviation.
Figure 2 — schematic for Normal (Gaussian) distribution z-transform — solve for z-score — Normal Distribution (Gaussian Distribution) (2)
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for z:
Step 3
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning z = 3.6875 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 7.3750 — kept a factor of two that cancels in the correct rearrangement.
- 1.8438 — dropped that same factor in the other direction.
- 4.0563 — rounded an intermediate value before the final step.
Reference: FE Handbook — Normal Distribution (Gaussian Distribution)
A probability and statistics problem uses z-score. Given mean (mu) = 5,570 psi; std deviation (sigma) = 300.0 psi; z-score (z) = -2.1000, determine the value (x) in psi.
Given
Find
value (x), in psi
Start with the thinking
- The governing relation printed in this handbook section is z-score.
- Everything except x is given, so isolate x symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Probability and Statistics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that x stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning x = 4,940 psi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 9,880 — kept a factor of two that cancels in the correct rearrangement.
- 2,470 — dropped that same factor in the other direction.
- 5,434 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Probability and Statistics → Normal Distribution (Gaussian Distribution)
The normal distribution model is applied to a batch of dimensional readings. Given mean (mu) = 87.0000; std deviation (sigma) = 5.0000; z-score (z) = -2.9800, determine the value (x).
Given
Find
value (x)
Start with the thinking
- The governing relation printed in this handbook section is Normal (Gaussian) distribution z-transform.
- Everything except x is given, so isolate x symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- The normal distribution (Gaussian distribution) standardizes a value x using its mean and standard deviation.
Figure 4 — schematic for Normal (Gaussian) distribution z-transform — solve for value — Normal Distribution (Gaussian Distribution) (4)
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for x:
Step 3
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning x = 72.1000 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 144.2 — kept a factor of two that cancels in the correct rearrangement.
- 36.0500 — dropped that same factor in the other direction.
- 79.3100 — rounded an intermediate value before the final step.
Reference: FE Handbook — Normal Distribution (Gaussian Distribution)
A probability and statistics problem uses z-score. Given std deviation (sigma) = 430.0 psi; value (x) = 4,120 psi; z-score (z) = 1.1100, determine the mean (mu) in psi.
Given
Find
mean (mu), in psi
Start with the thinking
- The governing relation printed in this handbook section is z-score.
- Everything except mu is given, so isolate mu symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Probability and Statistics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that mu stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning mu = 3,643 psi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 7,285 — kept a factor of two that cancels in the correct rearrangement.
- 1,821 — dropped that same factor in the other direction.
- 4,007 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Probability and Statistics → Normal Distribution (Gaussian Distribution)
An engineer standardizes a strength test result assuming a normal distribution. Given std deviation (sigma) = 12.5000; value (x) = 157.5; z-score (z) = 1.4800, determine the mean (mu).
Given
Find
mean (mu)
Start with the thinking
- The governing relation printed in this handbook section is Normal (Gaussian) distribution z-transform.
- Everything except mu is given, so isolate mu symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- The normal distribution (Gaussian distribution) standardizes a value x using its mean and standard deviation.
Figure 6 — schematic for Normal (Gaussian) distribution z-transform — solve for mean — Normal Distribution (Gaussian Distribution) (6)
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for mu:
Step 3
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning mu = 139.0 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 278.0 — kept a factor of two that cancels in the correct rearrangement.
- 69.5000 — dropped that same factor in the other direction.
- 152.9 — rounded an intermediate value before the final step.
Reference: FE Handbook — Normal Distribution (Gaussian Distribution)
A probability and statistics problem uses z-score. Given mean (mu) = 3,940 psi; value (x) = 4,150 psi; z-score (z) = 1.5600, determine the std deviation (sigma) in psi.
Given
Find
std deviation (sigma), in psi
Start with the thinking
- The governing relation printed in this handbook section is z-score.
- Everything except sigma is given, so isolate sigma symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Probability and Statistics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that sigma stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning sigma = 134.6 psi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 269.2 — kept a factor of two that cancels in the correct rearrangement.
- 67.3077 — dropped that same factor in the other direction.
- 148.1 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Probability and Statistics → Normal Distribution (Gaussian Distribution)
A quality analyst uses the Gaussian distribution to find a z-score for a measurement. Given mean (mu) = 191.0; std deviation (sigma) = 11.0000; value (x) = 71.0000, determine the z-score (z).
Given
Find
z-score (z)
Start with the thinking
- The governing relation printed in this handbook section is Normal (Gaussian) distribution z-transform.
- Everything except z is given, so isolate z symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- The normal distribution (Gaussian distribution) standardizes a value x using its mean and standard deviation.
Figure 8 — schematic for Normal (Gaussian) distribution z-transform — solve for z-score (case 2) — Normal Distribution (Gaussian Distribution) (8)
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for z:
Step 3
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning z = -10.9091 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- -21.8182 — kept a factor of two that cancels in the correct rearrangement.
- -5.4545 — dropped that same factor in the other direction.
- -12.0000 — rounded an intermediate value before the final step.
Reference: FE Handbook — Normal Distribution (Gaussian Distribution)
A probability and statistics problem uses z-score. Given mean (mu) = 5,560 psi; std deviation (sigma) = 180.0 psi; value (x) = 3,000 psi, determine the z-score (z).
Given
Find
z-score (z)
Start with the thinking
- The governing relation printed in this handbook section is z-score.
- Everything except z is given, so isolate z symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Probability and Statistics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that z stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning z = -14.2222 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- -28.4444 — kept a factor of two that cancels in the correct rearrangement.
- -7.1111 — dropped that same factor in the other direction.
- -15.6444 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Probability and Statistics → Normal Distribution (Gaussian Distribution)
The normal distribution model is applied to a batch of dimensional readings. Given mean (mu) = 194.0; std deviation (sigma) = 11.5000; z-score (z) = 1.3300, determine the value (x).
Given
Find
value (x)
Start with the thinking
- The governing relation printed in this handbook section is Normal (Gaussian) distribution z-transform.
- Everything except x is given, so isolate x symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- The normal distribution (Gaussian distribution) standardizes a value x using its mean and standard deviation.
Figure 10 — schematic for Normal (Gaussian) distribution z-transform — solve for value (case 2) — Normal Distribution (Gaussian Distribution) (10)
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for x:
Step 3
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning x = 209.3 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 418.6 — kept a factor of two that cancels in the correct rearrangement.
- 104.6 — dropped that same factor in the other direction.
- 230.2 — rounded an intermediate value before the final step.
Reference: FE Handbook — Normal Distribution (Gaussian Distribution)