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Average and Range Charts

Probability and Statistics · FE Reference Handbook section

Probability and Statistics
12 formulas
10 exam-style examples
~60 min
All Probability and Statistics lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Average and range control chart limits — solve for upper control limit — Average and Range Charts

A quality engineer sets up an average and range chart for a machining process. Given grand average (xbb) = 70.1000; control chart factor A2 (A2) = 0.6500; average range (Rbar) = 3.6000, determine the upper control limit (UCL).

Given

  • grandaverage(xbb)=70.1000grand average (xbb) = 70.1000
  • controlchartfactorA2(A2)=0.6500control chart factor A_{2} (A_{2}) = 0.6500
  • averagerange(Rbar)=3.6000average range (Rbar) = 3.6000

Find

upper control limit (UCL)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except UCL is given, so isolate UCL symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 1 — schematic for Average and range control chart limits — solve for upper control limit — Average and Range Charts

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for UCL:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  3. Step 3 — List the givens: grand average (xbb) = 70.1000, control chart factor A2 (A2) = 0.6500, average range (Rbar) = 3.6000.

  4. Step 4 — Substitute the given values:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  5. Step 5 — Evaluate:

    UCL=72.4400UCL = 72.4400
  6. Step 6 — Check: returning UCL = 72.4400 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
UCL=72.4400UCL = 72.4400

Why the other options are there

  • 144.9 — kept a factor of two that cancels in the correct rearrangement.
  • 36.2200 — dropped that same factor in the other direction.
  • 79.6840 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 2
Average and range control chart limits — solve for grand average — Average and Range Charts (2)

An analyst computes the upper control limit for an average and range chart. Given control chart factor A2 (A2) = 0.7300; average range (Rbar) = 15.5000; upper control limit (UCL) = 62.2000, determine the grand average (xbb).

Given

  • controlchartfactorA2(A2)=0.7300control chart factor A_{2} (A_{2}) = 0.7300
  • averagerange(Rbar)=15.5000average range (Rbar) = 15.5000
  • uppercontrollimit(UCL)=62.2000upper control limit (UCL) = 62.2000

Find

grand average (xbb)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except xbb is given, so isolate xbb symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 2 — schematic for Average and range control chart limits — solve for grand average — Average and Range Charts (2)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for xbb:

    xbb=UCL−A2Rˉxbb = UCL - A_2\bar{R}
  3. Step 3 — List the givens: control chart factor A2 (A2) = 0.7300, average range (Rbar) = 15.5000, upper control limit (UCL) = 62.2000.

  4. Step 4 — Substitute the given values:

    xbb=62.2000−A2Rˉxbb = 62.2000 - A_2\bar{R}
  5. Step 5 — Evaluate:

    xbb=50.8850xbb = 50.8850
  6. Step 6 — Check: returning xbb = 50.8850 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
xbb=50.8850xbb = 50.8850

Why the other options are there

  • 101.8 — kept a factor of two that cancels in the correct rearrangement.
  • 25.4425 — dropped that same factor in the other direction.
  • 55.9735 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 3
Average and range control chart limits — solve for average range — Average and Range Charts (3)

The average and range chart signals a process shift beyond the control limit. Given grand average (xbb) = 85.7000; control chart factor A2 (A2) = 0.6600; upper control limit (UCL) = 92.0000, determine the average range (Rbar).

Given

  • grandaverage(xbb)=85.7000grand average (xbb) = 85.7000
  • controlchartfactorA2(A2)=0.6600control chart factor A_{2} (A_{2}) = 0.6600
  • uppercontrollimit(UCL)=92.0000upper control limit (UCL) = 92.0000

Find

average range (Rbar)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except Rbar is given, so isolate Rbar symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 3 — schematic for Average and range control chart limits — solve for average range — Average and Range Charts (3)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for Rbar:

    Rbar=UCL−xˉˉA2Rbar = \dfrac{UCL - \bar{\bar{x}}}{A_2}
  3. Step 3 — List the givens: grand average (xbb) = 85.7000, control chart factor A2 (A2) = 0.6600, upper control limit (UCL) = 92.0000.

  4. Step 4 — Substitute the given values:

    Rbar=92.0000−xˉˉA2Rbar = \dfrac{92.0000 - \bar{\bar{x}}}{A_2}
  5. Step 5 — Evaluate:

    Rbar=9.5455Rbar = 9.5455
  6. Step 6 — Check: returning Rbar = 9.5455 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Rbar=9.5455Rbar = 9.5455

Why the other options are there

  • 19.0909 — kept a factor of two that cancels in the correct rearrangement.
  • 4.7727 — dropped that same factor in the other direction.
  • 10.5000 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 4
Average and range control chart limits — solve for upper control limit (case 2) — Average and Range Charts (4)

A quality engineer sets up an average and range chart for a machining process. Given grand average (xbb) = 56.5000; control chart factor A2 (A2) = 0.7000; average range (Rbar) = 5.9000, determine the upper control limit (UCL).

Given

  • grandaverage(xbb)=56.5000grand average (xbb) = 56.5000
  • controlchartfactorA2(A2)=0.7000control chart factor A_{2} (A_{2}) = 0.7000
  • averagerange(Rbar)=5.9000average range (Rbar) = 5.9000

Find

upper control limit (UCL)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except UCL is given, so isolate UCL symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 4 — schematic for Average and range control chart limits — solve for upper control limit (case 2) — Average and Range Charts (4)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for UCL:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  3. Step 3 — List the givens: grand average (xbb) = 56.5000, control chart factor A2 (A2) = 0.7000, average range (Rbar) = 5.9000.

  4. Step 4 — Substitute the given values:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  5. Step 5 — Evaluate:

    UCL=60.6300UCL = 60.6300
  6. Step 6 — Check: returning UCL = 60.6300 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
UCL=60.6300UCL = 60.6300

Why the other options are there

  • 121.3 — kept a factor of two that cancels in the correct rearrangement.
  • 30.3150 — dropped that same factor in the other direction.
  • 66.6930 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 5
Average and range control chart limits — solve for grand average (case 2) — Average and Range Charts (5)

An analyst computes the upper control limit for an average and range chart. Given control chart factor A2 (A2) = 0.4100; average range (Rbar) = 8.6000; upper control limit (UCL) = 72.5000, determine the grand average (xbb).

Given

  • controlchartfactorA2(A2)=0.4100control chart factor A_{2} (A_{2}) = 0.4100
  • averagerange(Rbar)=8.6000average range (Rbar) = 8.6000
  • uppercontrollimit(UCL)=72.5000upper control limit (UCL) = 72.5000

Find

grand average (xbb)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except xbb is given, so isolate xbb symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 5 — schematic for Average and range control chart limits — solve for grand average (case 2) — Average and Range Charts (5)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for xbb:

    xbb=UCL−A2Rˉxbb = UCL - A_2\bar{R}
  3. Step 3 — List the givens: control chart factor A2 (A2) = 0.4100, average range (Rbar) = 8.6000, upper control limit (UCL) = 72.5000.

  4. Step 4 — Substitute the given values:

    xbb=72.5000−A2Rˉxbb = 72.5000 - A_2\bar{R}
  5. Step 5 — Evaluate:

    xbb=68.9740xbb = 68.9740
  6. Step 6 — Check: returning xbb = 68.9740 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
xbb=68.9740xbb = 68.9740

Why the other options are there

  • 137.9 — kept a factor of two that cancels in the correct rearrangement.
  • 34.4870 — dropped that same factor in the other direction.
  • 75.8714 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 6
Average and range control chart limits — solve for average range (case 2) — Average and Range Charts (6)

The average and range chart signals a process shift beyond the control limit. Given grand average (xbb) = 53.9000; control chart factor A2 (A2) = 0.3200; upper control limit (UCL) = 82.7300, determine the average range (Rbar).

Given

  • grandaverage(xbb)=53.9000grand average (xbb) = 53.9000
  • controlchartfactorA2(A2)=0.3200control chart factor A_{2} (A_{2}) = 0.3200
  • uppercontrollimit(UCL)=82.7300upper control limit (UCL) = 82.7300

Find

average range (Rbar)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except Rbar is given, so isolate Rbar symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 6 — schematic for Average and range control chart limits — solve for average range (case 2) — Average and Range Charts (6)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for Rbar:

    Rbar=UCL−xˉˉA2Rbar = \dfrac{UCL - \bar{\bar{x}}}{A_2}
  3. Step 3 — List the givens: grand average (xbb) = 53.9000, control chart factor A2 (A2) = 0.3200, upper control limit (UCL) = 82.7300.

  4. Step 4 — Substitute the given values:

    Rbar=82.7300−xˉˉA2Rbar = \dfrac{82.7300 - \bar{\bar{x}}}{A_2}
  5. Step 5 — Evaluate:

    Rbar=90.0938Rbar = 90.0938
  6. Step 6 — Check: returning Rbar = 90.0938 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Rbar=90.0938Rbar = 90.0938

Why the other options are there

  • 180.2 — kept a factor of two that cancels in the correct rearrangement.
  • 45.0469 — dropped that same factor in the other direction.
  • 99.1031 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 7
Average and range control chart limits — solve for upper control limit (case 3) — Average and Range Charts (7)

A quality engineer sets up an average and range chart for a machining process. Given grand average (xbb) = 78.5000; control chart factor A2 (A2) = 0.3400; average range (Rbar) = 4.0000, determine the upper control limit (UCL).

Given

  • grandaverage(xbb)=78.5000grand average (xbb) = 78.5000
  • controlchartfactorA2(A2)=0.3400control chart factor A_{2} (A_{2}) = 0.3400
  • averagerange(Rbar)=4.0000average range (Rbar) = 4.0000

Find

upper control limit (UCL)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except UCL is given, so isolate UCL symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 7 — schematic for Average and range control chart limits — solve for upper control limit (case 3) — Average and Range Charts (7)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for UCL:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  3. Step 3 — List the givens: grand average (xbb) = 78.5000, control chart factor A2 (A2) = 0.3400, average range (Rbar) = 4.0000.

  4. Step 4 — Substitute the given values:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  5. Step 5 — Evaluate:

    UCL=79.8600UCL = 79.8600
  6. Step 6 — Check: returning UCL = 79.8600 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
UCL=79.8600UCL = 79.8600

Why the other options are there

  • 159.7 — kept a factor of two that cancels in the correct rearrangement.
  • 39.9300 — dropped that same factor in the other direction.
  • 87.8460 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 8
Average and range control chart limits — solve for grand average (case 3) — Average and Range Charts (8)

An analyst computes the upper control limit for an average and range chart. Given control chart factor A2 (A2) = 0.4300; average range (Rbar) = 16.0000; upper control limit (UCL) = 60.4000, determine the grand average (xbb).

Given

  • controlchartfactorA2(A2)=0.4300control chart factor A_{2} (A_{2}) = 0.4300
  • averagerange(Rbar)=16.0000average range (Rbar) = 16.0000
  • uppercontrollimit(UCL)=60.4000upper control limit (UCL) = 60.4000

Find

grand average (xbb)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except xbb is given, so isolate xbb symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 8 — schematic for Average and range control chart limits — solve for grand average (case 3) — Average and Range Charts (8)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for xbb:

    xbb=UCL−A2Rˉxbb = UCL - A_2\bar{R}
  3. Step 3 — List the givens: control chart factor A2 (A2) = 0.4300, average range (Rbar) = 16.0000, upper control limit (UCL) = 60.4000.

  4. Step 4 — Substitute the given values:

    xbb=60.4000−A2Rˉxbb = 60.4000 - A_2\bar{R}
  5. Step 5 — Evaluate:

    xbb=53.5200xbb = 53.5200
  6. Step 6 — Check: returning xbb = 53.5200 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
xbb=53.5200xbb = 53.5200

Why the other options are there

  • 107.0 — kept a factor of two that cancels in the correct rearrangement.
  • 26.7600 — dropped that same factor in the other direction.
  • 58.8720 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 9
Average and range control chart limits — solve for average range (case 3) — Average and Range Charts (9)

The average and range chart signals a process shift beyond the control limit. Given grand average (xbb) = 67.3000; control chart factor A2 (A2) = 0.7400; upper control limit (UCL) = 98.5200, determine the average range (Rbar).

Given

  • grandaverage(xbb)=67.3000grand average (xbb) = 67.3000
  • controlchartfactorA2(A2)=0.7400control chart factor A_{2} (A_{2}) = 0.7400
  • uppercontrollimit(UCL)=98.5200upper control limit (UCL) = 98.5200

Find

average range (Rbar)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except Rbar is given, so isolate Rbar symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 9 — schematic for Average and range control chart limits — solve for average range (case 3) — Average and Range Charts (9)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for Rbar:

    Rbar=UCL−xˉˉA2Rbar = \dfrac{UCL - \bar{\bar{x}}}{A_2}
  3. Step 3 — List the givens: grand average (xbb) = 67.3000, control chart factor A2 (A2) = 0.7400, upper control limit (UCL) = 98.5200.

  4. Step 4 — Substitute the given values:

    Rbar=98.5200−xˉˉA2Rbar = \dfrac{98.5200 - \bar{\bar{x}}}{A_2}
  5. Step 5 — Evaluate:

    Rbar=42.1892Rbar = 42.1892
  6. Step 6 — Check: returning Rbar = 42.1892 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Rbar=42.1892Rbar = 42.1892

Why the other options are there

  • 84.3784 — kept a factor of two that cancels in the correct rearrangement.
  • 21.0946 — dropped that same factor in the other direction.
  • 46.4081 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

Example 10
Average and range control chart limits — solve for upper control limit (case 4) — Average and Range Charts (10)

A quality engineer sets up an average and range chart for a machining process. Given grand average (xbb) = 53.5000; control chart factor A2 (A2) = 0.7100; average range (Rbar) = 4.1000, determine the upper control limit (UCL).

Given

  • grandaverage(xbb)=53.5000grand average (xbb) = 53.5000
  • controlchartfactorA2(A2)=0.7100control chart factor A_{2} (A_{2}) = 0.7100
  • averagerange(Rbar)=4.1000average range (Rbar) = 4.1000

Find

upper control limit (UCL)

Start with the thinking

  • The governing relation printed in this handbook section is Average and range control chart limits.
  • Everything except UCL is given, so isolate UCL symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Average and range charts set control limits on the process mean using the grand average and average range.
Average and range chart016334965621582653604635sample average

Figure 10 — schematic for Average and range control chart limits — solve for upper control limit (case 4) — Average and Range Charts (10)

Step-by-step solution

  1. Step 1 — State the governing relation:

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}
  2. Step 2 — Rearrange symbolically for UCL:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  3. Step 3 — List the givens: grand average (xbb) = 53.5000, control chart factor A2 (A2) = 0.7100, average range (Rbar) = 4.1000.

  4. Step 4 — Substitute the given values:

    UCL=xˉˉ+A2RˉUCL = \bar{\bar{x}} + A_2\bar{R}
  5. Step 5 — Evaluate:

    UCL=56.4110UCL = 56.4110
  6. Step 6 — Check: returning UCL = 56.4110 to

    UCLxˉ=xˉˉ+A2RˉUCL_{\bar{x}} = \bar{\bar{x}} + A_2 \bar{R}

    reproduces the given quantities, and both sides carry the same units.

Answer:
UCL=56.4110UCL = 56.4110

Why the other options are there

  • 112.8 — kept a factor of two that cancels in the correct rearrangement.
  • 28.2055 — dropped that same factor in the other direction.
  • 62.0521 — rounded an intermediate value before the final step.

Reference: FE Handbook — Average and Range Charts

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