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Quadratic Equation

Mathematics · FE Reference Handbook section

Mathematics
2 formulas
10 exam-style examples
~49 min
All Mathematics lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Quadratic from a hydraulics balance

Depth y in a channel balance satisfies 3y² − 11y + 6 = 0. Which positive root is physically meaningful if the channel is 1.5 m deep?

Given

  • a=3,b=−11,c=6a = 3, b = -11, c = 6
  • Channeldepthlimit=1.5mChannel depth limit = 1.5 m

Find

The admissible root y

Start with the thinking

  • Both algebraic roots are real; physics rejects one.
  • Compute the discriminant before the roots.

Step-by-step solution

  1. Quadratic formula

    y=[−b±(b2−4ac)]/(2a)y = [-b \pm \sqrt(b^{2} - 4ac)]/(2a)
  2. Discriminant

    b2−4ac=121−72=49b^{2} - 4ac = 121 - 72 = 49
  3. Root term

    49=7\sqrt49 = 7
  4. Roots

    y=(11±7)/6,soy1=3.00mandy2=0.667my = (11 \pm 7)/6, so y_{1} = 3.00 m and y_{2} = 0.667 m
  5. Physical check

    y1=3.00mexceedsthe1.5mchannel,soy=0.667my_{1} = 3.00 m exceeds the 1.5 m channel, so y = 0.667 m
Answer:
y=0.667my = 0.667 m

Why the other options are there

  • 3.00 m (geometry limit ignored)
  • 1.83 m (average of the roots)

Reference: FE Reference Handbook — Mathematics — Algebra, quadratic equation

Example 2
Parabola vertex form — solve for y-value — Quadratic Equation

A mathematics problem uses Parabola vertex form. Given coefficient (a) = 2.0000; x-value (x) = 3.5000; vertex x (h) = -2.0000; vertex y (k) = 1.0000, determine the y-value (y).

Given

  • coefficient(a)=2.0000coefficient (a) = 2.0000
  • x−value(x)=3.5000x-value (x) = 3.5000
  • vertexx(h)=−2.0000vertex x (h) = -2.0000
  • vertexy(k)=1.0000vertex y (k) = 1.0000

Find

y-value (y)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:coefficient(a)=2.0000,x−value(x)=3.5000,vertexx(h)=−2.0000,vertexy(k)=1.0000List the givens: coefficient (a) = 2.0000, x-value (x) = 3.5000, vertex x (h) = -2.0000, vertex y (k) = 1.0000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=61.5000y = 61.5000
  6. Step 6 — Check: returning y = 61.5000 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=61.5000y = 61.5000

Why the other options are there

  • 123.0 — kept a factor of two that cancels in the correct rearrangement.
  • 30.7500 — dropped that same factor in the other direction.
  • 67.6500 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 3
Parabola vertex form — solve for coefficient — Quadratic Equation (2)

A mathematics problem uses Parabola vertex form. Given x-value (x) = -4.5000; vertex x (h) = 1.0000; vertex y (k) = -0.5000; y-value (y) = 43.2000, determine the coefficient (a).

Given

  • x−value(x)=−4.5000x-value (x) = -4.5000
  • vertexx(h)=1.0000vertex x (h) = 1.0000
  • vertexy(k)=−0.5000vertex y (k) = -0.5000
  • y−value(y)=43.2000y-value (y) = 43.2000

Find

coefficient (a)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except a is given, so isolate a symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that a stands alone on the left-hand side.

  3. Step 3

    Listthegivens:x−value(x)=−4.5000,vertexx(h)=1.0000,vertexy(k)=−0.5000,y−value(y)=43.2000List the givens: x-value (x) = -4.5000, vertex x (h) = 1.0000, vertex y (k) = -0.5000, y-value (y) = 43.2000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    a=1.4446a = 1.4446
  6. Step 6 — Check: returning a = 1.4446 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
a=1.4446a = 1.4446

Why the other options are there

  • 2.8893 — kept a factor of two that cancels in the correct rearrangement.
  • 0.7223 — dropped that same factor in the other direction.
  • 1.5891 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 4
Parabola vertex form — solve for vertex y — Quadratic Equation (3)

A mathematics problem uses Parabola vertex form. Given coefficient (a) = 1.0000; x-value (x) = -2.5000; vertex x (h) = -3.0000; y-value (y) = 22.1000, determine the vertex y (k).

Given

  • coefficient(a)=1.0000coefficient (a) = 1.0000
  • x−value(x)=−2.5000x-value (x) = -2.5000
  • vertexx(h)=−3.0000vertex x (h) = -3.0000
  • y−value(y)=22.1000y-value (y) = 22.1000

Find

vertex y (k)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3 — List the givens: coefficient (a) = 1.0000, x-value (x) = -2.5000, vertex x (h) = -3.0000, y-value (y) = 22.1000.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=21.8500k = 21.8500
  6. Step 6 — Check: returning k = 21.8500 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=21.8500k = 21.8500

Why the other options are there

  • 43.7000 — kept a factor of two that cancels in the correct rearrangement.
  • 10.9250 — dropped that same factor in the other direction.
  • 24.0350 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 5
Parabola vertex form — solve for y-value (case 2) — Quadratic Equation (4)

A mathematics problem uses Parabola vertex form. Given coefficient (a) = 1.9000; x-value (x) = 1.5000; vertex x (h) = -1.0000; vertex y (k) = 1.5000, determine the y-value (y).

Given

  • coefficient(a)=1.9000coefficient (a) = 1.9000
  • x−value(x)=1.5000x-value (x) = 1.5000
  • vertexx(h)=−1.0000vertex x (h) = -1.0000
  • vertexy(k)=1.5000vertex y (k) = 1.5000

Find

y-value (y)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:coefficient(a)=1.9000,x−value(x)=1.5000,vertexx(h)=−1.0000,vertexy(k)=1.5000List the givens: coefficient (a) = 1.9000, x-value (x) = 1.5000, vertex x (h) = -1.0000, vertex y (k) = 1.5000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=13.3750y = 13.3750
  6. Step 6 — Check: returning y = 13.3750 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=13.3750y = 13.3750

Why the other options are there

  • 26.7500 — kept a factor of two that cancels in the correct rearrangement.
  • 6.6875 — dropped that same factor in the other direction.
  • 14.7125 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 6
Parabola vertex form — solve for coefficient (case 2) — Quadratic Equation (5)

A mathematics problem uses Parabola vertex form. Given x-value (x) = 3.5000; vertex x (h) = -1.5000; vertex y (k) = 2.0000; y-value (y) = -41.1000, determine the coefficient (a).

Given

  • x−value(x)=3.5000x-value (x) = 3.5000
  • vertexx(h)=−1.5000vertex x (h) = -1.5000
  • vertexy(k)=2.0000vertex y (k) = 2.0000
  • y−value(y)=−41.1000y-value (y) = -41.1000

Find

coefficient (a)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except a is given, so isolate a symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that a stands alone on the left-hand side.

  3. Step 3

    Listthegivens:x−value(x)=3.5000,vertexx(h)=−1.5000,vertexy(k)=2.0000,y−value(y)=−41.1000List the givens: x-value (x) = 3.5000, vertex x (h) = -1.5000, vertex y (k) = 2.0000, y-value (y) = -41.1000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    a=−1.7240a = -1.7240
  6. Step 6 — Check: returning a = -1.7240 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
a=−1.7240a = -1.7240

Why the other options are there

  • -3.4480 — kept a factor of two that cancels in the correct rearrangement.
  • -0.8620 — dropped that same factor in the other direction.
  • -1.8964 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 7
Parabola vertex form — solve for vertex y (case 2) — Quadratic Equation (6)

A mathematics problem uses Parabola vertex form. Given coefficient (a) = 1.9000; x-value (x) = -3.5000; vertex x (h) = 2.5000; y-value (y) = 13.5000, determine the vertex y (k).

Given

  • coefficient(a)=1.9000coefficient (a) = 1.9000
  • x−value(x)=−3.5000x-value (x) = -3.5000
  • vertexx(h)=2.5000vertex x (h) = 2.5000
  • y−value(y)=13.5000y-value (y) = 13.5000

Find

vertex y (k)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:coefficient(a)=1.9000,x−value(x)=−3.5000,vertexx(h)=2.5000,y−value(y)=13.5000List the givens: coefficient (a) = 1.9000, x-value (x) = -3.5000, vertex x (h) = 2.5000, y-value (y) = 13.5000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−54.9000k = -54.9000
  6. Step 6 — Check: returning k = -54.9000 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−54.9000k = -54.9000

Why the other options are there

  • -109.8 — kept a factor of two that cancels in the correct rearrangement.
  • -27.4500 — dropped that same factor in the other direction.
  • -60.3900 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 8
Parabola vertex form — solve for y-value (case 3) — Quadratic Equation (7)

A mathematics problem uses Parabola vertex form. Given coefficient (a) = 1.0000; x-value (x) = 1.0000; vertex x (h) = 2.5000; vertex y (k) = 3.0000, determine the y-value (y).

Given

  • coefficient(a)=1.0000coefficient (a) = 1.0000
  • x−value(x)=1.0000x-value (x) = 1.0000
  • vertexx(h)=2.5000vertex x (h) = 2.5000
  • vertexy(k)=3.0000vertex y (k) = 3.0000

Find

y-value (y)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:coefficient(a)=1.0000,x−value(x)=1.0000,vertexx(h)=2.5000,vertexy(k)=3.0000List the givens: coefficient (a) = 1.0000, x-value (x) = 1.0000, vertex x (h) = 2.5000, vertex y (k) = 3.0000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=5.2500y = 5.2500
  6. Step 6 — Check: returning y = 5.2500 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=5.2500y = 5.2500

Why the other options are there

  • 10.5000 — kept a factor of two that cancels in the correct rearrangement.
  • 2.6250 — dropped that same factor in the other direction.
  • 5.7750 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 9
Parabola vertex form — solve for coefficient (case 3) — Quadratic Equation (8)

A mathematics problem uses Parabola vertex form. Given x-value (x) = -4.0000; vertex x (h) = 1.5000; vertex y (k) = -2.5000; y-value (y) = -23.0000, determine the coefficient (a).

Given

  • x−value(x)=−4.0000x-value (x) = -4.0000
  • vertexx(h)=1.5000vertex x (h) = 1.5000
  • vertexy(k)=−2.5000vertex y (k) = -2.5000
  • y−value(y)=−23.0000y-value (y) = -23.0000

Find

coefficient (a)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except a is given, so isolate a symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that a stands alone on the left-hand side.

  3. Step 3

    Listthegivens:x−value(x)=−4.0000,vertexx(h)=1.5000,vertexy(k)=−2.5000,y−value(y)=−23.0000List the givens: x-value (x) = -4.0000, vertex x (h) = 1.5000, vertex y (k) = -2.5000, y-value (y) = -23.0000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    a=−0.6777a = -0.6777
  6. Step 6 — Check: returning a = -0.6777 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
a=−0.6777a = -0.6777

Why the other options are there

  • -1.3554 — kept a factor of two that cancels in the correct rearrangement.
  • -0.3388 — dropped that same factor in the other direction.
  • -0.7455 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

Example 10
Parabola vertex form — solve for vertex y (case 3) — Quadratic Equation (9)

A mathematics problem uses Parabola vertex form. Given coefficient (a) = 0.5000; x-value (x) = -4.5000; vertex x (h) = -1.0000; y-value (y) = -30.6000, determine the vertex y (k).

Given

  • coefficient(a)=0.5000coefficient (a) = 0.5000
  • x−value(x)=−4.5000x-value (x) = -4.5000
  • vertexx(h)=−1.0000vertex x (h) = -1.0000
  • y−value(y)=−30.6000y-value (y) = -30.6000

Find

vertex y (k)

Start with the thinking

  • The governing relation printed in this handbook section is Parabola vertex form.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=a(x−h)2+ky = a (x - h)^2 + k
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3 — List the givens: coefficient (a) = 0.5000, x-value (x) = -4.5000, vertex x (h) = -1.0000, y-value (y) = -30.6000.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−36.7250k = -36.7250
  6. Step 6 — Check: returning k = -36.7250 to

    y=a(x−h)2+ky = a (x - h)^2 + k

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−36.7250k = -36.7250

Why the other options are there

  • -73.4500 — kept a factor of two that cancels in the correct rearrangement.
  • -18.3625 — dropped that same factor in the other direction.
  • -40.3975 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Quadratic Equation

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