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Matrix Properties

Mathematics · FE Reference Handbook section

Mathematics
3 formulas
10 exam-style examples
~51 min
All Mathematics lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Matrix properties — trace and scalar multiplication — solve for trace of kA — Matrix Properties

An engineer checks matrix properties while scaling a stiffness matrix. Given a11 (a11) = 2.5000; a22 (a22) = 3.0000; scalar (k) = 1.2000, determine the trace of kA (trkA).

Given

  • a11(a11)=2.5000a11 (a11) = 2.5000
  • a22(a22)=3.0000a22 (a22) = 3.0000
  • scalar(k)=1.2000scalar (k) = 1.2000

Find

trace of kA (trkA)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except trkA is given, so isolate trkA symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for trkA:

    trkA=k(a11+a22)trkA = k (a_{11}+a_{22})
  3. Step 3

    Listthegivens:a11(a11)=2.5000,a22(a22)=3.0000,scalar(k)=1.2000List the givens: a11 (a11) = 2.5000, a22 (a22) = 3.0000, scalar (k) = 1.2000
  4. Step 4 — Substitute the given values:

    trkA=1.2000(2.5000+3.0000)trkA = 1.2000 (2.5000+3.0000)
  5. Step 5 — Evaluate:

    trkA=6.6000trkA = 6.6000
  6. Step 6 — Check: returning trkA = 6.6000 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
trkA=6.6000trkA = 6.6000

Why the other options are there

  • 13.2000 — kept a factor of two that cancels in the correct rearrangement.
  • 3.3000 — dropped that same factor in the other direction.
  • 7.2600 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 2
Matrix properties — trace and scalar multiplication — solve for scalar — Matrix Properties (2)

A student verifies the matrix property tr(kA) = k tr(A) numerically. Given a11 (a11) = 2.0000; a22 (a22) = 7.0000; trace of kA (trkA) = 98.0000, determine the scalar (k).

Given

  • a11(a11)=2.0000a11 (a11) = 2.0000
  • a22(a22)=7.0000a22 (a22) = 7.0000
  • traceofkA(trkA)=98.0000trace of kA (trkA) = 98.0000

Find

scalar (k)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for k:

    k=tr(kA)a11+a22k = \dfrac{\text{tr}(kA)}{a_{11}+a_{22}}
  3. Step 3

    Listthegivens:a11(a11)=2.0000,a22(a22)=7.0000,traceofkA(trkA)=98.0000List the givens: a11 (a11) = 2.0000, a22 (a22) = 7.0000, trace of kA (trkA) = 98.0000
  4. Step 4 — Substitute the given values:

    k=tr(kA)2.0000+7.0000k = \dfrac{\text{tr}(kA)}{2.0000+7.0000}
  5. Step 5 — Evaluate:

    k=10.8889k = 10.8889
  6. Step 6 — Check: returning k = 10.8889 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=10.8889k = 10.8889

Why the other options are there

  • 21.7778 — kept a factor of two that cancels in the correct rearrangement.
  • 5.4444 — dropped that same factor in the other direction.
  • 11.9778 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 3
Matrix properties — trace and scalar multiplication — solve for a11 — Matrix Properties (3)

The matrix properties of a scaled transformation matrix are confirmed. Given a22 (a22) = 6.0000; scalar (k) = 4.9000; trace of kA (trkA) = 94.8000, determine the a11 (a11).

Given

  • a22(a22)=6.0000a22 (a22) = 6.0000
  • scalar(k)=4.9000scalar (k) = 4.9000
  • traceofkA(trkA)=94.8000trace of kA (trkA) = 94.8000

Find

a11 (a11)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except a11 is given, so isolate a11 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for a11:

    a11=tr(kA)k−a22a_{11} = \dfrac{\text{tr}(kA)}{k} - a_{22}
  3. Step 3

    Listthegivens:a22(a22)=6.0000,scalar(k)=4.9000,traceofkA(trkA)=94.8000List the givens: a22 (a22) = 6.0000, scalar (k) = 4.9000, trace of kA (trkA) = 94.8000
  4. Step 4 — Substitute the given values:

    a11=tr(kA)4.9000−6.0000a_{11} = \dfrac{\text{tr}(kA)}{4.9000} - 6.0000
  5. Step 5 — Evaluate:

    a11=13.3469a_{11} = 13.3469
  6. Step 6 — Check: returning a11 = 13.3469 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
a11=13.3469a_{11} = 13.3469

Why the other options are there

  • 26.6939 — kept a factor of two that cancels in the correct rearrangement.
  • 6.6735 — dropped that same factor in the other direction.
  • 14.6816 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 4
Matrix properties — trace and scalar multiplication — solve for trace of kA (case 2) — Matrix Properties (4)

An engineer checks matrix properties while scaling a stiffness matrix. Given a11 (a11) = 5.5000; a22 (a22) = 5.5000; scalar (k) = 0.8000, determine the trace of kA (trkA).

Given

  • a11(a11)=5.5000a11 (a11) = 5.5000
  • a22(a22)=5.5000a22 (a22) = 5.5000
  • scalar(k)=0.8000scalar (k) = 0.8000

Find

trace of kA (trkA)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except trkA is given, so isolate trkA symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for trkA:

    trkA=k(a11+a22)trkA = k (a_{11}+a_{22})
  3. Step 3

    Listthegivens:a11(a11)=5.5000,a22(a22)=5.5000,scalar(k)=0.8000List the givens: a11 (a11) = 5.5000, a22 (a22) = 5.5000, scalar (k) = 0.8000
  4. Step 4 — Substitute the given values:

    trkA=0.8000(5.5000+5.5000)trkA = 0.8000 (5.5000+5.5000)
  5. Step 5 — Evaluate:

    trkA=8.8000trkA = 8.8000
  6. Step 6 — Check: returning trkA = 8.8000 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
trkA=8.8000trkA = 8.8000

Why the other options are there

  • 17.6000 — kept a factor of two that cancels in the correct rearrangement.
  • 4.4000 — dropped that same factor in the other direction.
  • 9.6800 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 5
Matrix properties — trace and scalar multiplication — solve for scalar (case 2) — Matrix Properties (5)

A student verifies the matrix property tr(kA) = k tr(A) numerically. Given a11 (a11) = 7.5000; a22 (a22) = 9.5000; trace of kA (trkA) = 41.7000, determine the scalar (k).

Given

  • a11(a11)=7.5000a11 (a11) = 7.5000
  • a22(a22)=9.5000a22 (a22) = 9.5000
  • traceofkA(trkA)=41.7000trace of kA (trkA) = 41.7000

Find

scalar (k)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for k:

    k=tr(kA)a11+a22k = \dfrac{\text{tr}(kA)}{a_{11}+a_{22}}
  3. Step 3

    Listthegivens:a11(a11)=7.5000,a22(a22)=9.5000,traceofkA(trkA)=41.7000List the givens: a11 (a11) = 7.5000, a22 (a22) = 9.5000, trace of kA (trkA) = 41.7000
  4. Step 4 — Substitute the given values:

    k=tr(kA)7.5000+9.5000k = \dfrac{\text{tr}(kA)}{7.5000+9.5000}
  5. Step 5 — Evaluate:

    k=2.4529k = 2.4529
  6. Step 6 — Check: returning k = 2.4529 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=2.4529k = 2.4529

Why the other options are there

  • 4.9059 — kept a factor of two that cancels in the correct rearrangement.
  • 1.2265 — dropped that same factor in the other direction.
  • 2.6982 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 6
Matrix properties — trace and scalar multiplication — solve for a11 (case 2) — Matrix Properties (6)

The matrix properties of a scaled transformation matrix are confirmed. Given a22 (a22) = 4.5000; scalar (k) = 1.5000; trace of kA (trkA) = 46.9000, determine the a11 (a11).

Given

  • a22(a22)=4.5000a22 (a22) = 4.5000
  • scalar(k)=1.5000scalar (k) = 1.5000
  • traceofkA(trkA)=46.9000trace of kA (trkA) = 46.9000

Find

a11 (a11)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except a11 is given, so isolate a11 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for a11:

    a11=tr(kA)k−a22a_{11} = \dfrac{\text{tr}(kA)}{k} - a_{22}
  3. Step 3

    Listthegivens:a22(a22)=4.5000,scalar(k)=1.5000,traceofkA(trkA)=46.9000List the givens: a22 (a22) = 4.5000, scalar (k) = 1.5000, trace of kA (trkA) = 46.9000
  4. Step 4 — Substitute the given values:

    a11=tr(kA)1.5000−4.5000a_{11} = \dfrac{\text{tr}(kA)}{1.5000} - 4.5000
  5. Step 5 — Evaluate:

    a11=26.7667a_{11} = 26.7667
  6. Step 6 — Check: returning a11 = 26.7667 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
a11=26.7667a_{11} = 26.7667

Why the other options are there

  • 53.5333 — kept a factor of two that cancels in the correct rearrangement.
  • 13.3833 — dropped that same factor in the other direction.
  • 29.4433 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 7
Matrix properties — trace and scalar multiplication — solve for trace of kA (case 3) — Matrix Properties (7)

An engineer checks matrix properties while scaling a stiffness matrix. Given a11 (a11) = 5.0000; a22 (a22) = 9.5000; scalar (k) = 1.9000, determine the trace of kA (trkA).

Given

  • a11(a11)=5.0000a11 (a11) = 5.0000
  • a22(a22)=9.5000a22 (a22) = 9.5000
  • scalar(k)=1.9000scalar (k) = 1.9000

Find

trace of kA (trkA)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except trkA is given, so isolate trkA symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for trkA:

    trkA=k(a11+a22)trkA = k (a_{11}+a_{22})
  3. Step 3

    Listthegivens:a11(a11)=5.0000,a22(a22)=9.5000,scalar(k)=1.9000List the givens: a11 (a11) = 5.0000, a22 (a22) = 9.5000, scalar (k) = 1.9000
  4. Step 4 — Substitute the given values:

    trkA=1.9000(5.0000+9.5000)trkA = 1.9000 (5.0000+9.5000)
  5. Step 5 — Evaluate:

    trkA=27.5500trkA = 27.5500
  6. Step 6 — Check: returning trkA = 27.5500 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
trkA=27.5500trkA = 27.5500

Why the other options are there

  • 55.1000 — kept a factor of two that cancels in the correct rearrangement.
  • 13.7750 — dropped that same factor in the other direction.
  • 30.3050 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 8
Matrix properties — trace and scalar multiplication — solve for scalar (case 3) — Matrix Properties (8)

A student verifies the matrix property tr(kA) = k tr(A) numerically. Given a11 (a11) = 6.5000; a22 (a22) = 7.0000; trace of kA (trkA) = 14.4000, determine the scalar (k).

Given

  • a11(a11)=6.5000a11 (a11) = 6.5000
  • a22(a22)=7.0000a22 (a22) = 7.0000
  • traceofkA(trkA)=14.4000trace of kA (trkA) = 14.4000

Find

scalar (k)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for k:

    k=tr(kA)a11+a22k = \dfrac{\text{tr}(kA)}{a_{11}+a_{22}}
  3. Step 3

    Listthegivens:a11(a11)=6.5000,a22(a22)=7.0000,traceofkA(trkA)=14.4000List the givens: a11 (a11) = 6.5000, a22 (a22) = 7.0000, trace of kA (trkA) = 14.4000
  4. Step 4 — Substitute the given values:

    k=tr(kA)6.5000+7.0000k = \dfrac{\text{tr}(kA)}{6.5000+7.0000}
  5. Step 5 — Evaluate:

    k=1.0667k = 1.0667
  6. Step 6 — Check: returning k = 1.0667 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=1.0667k = 1.0667

Why the other options are there

  • 2.1333 — kept a factor of two that cancels in the correct rearrangement.
  • 0.5333 — dropped that same factor in the other direction.
  • 1.1733 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 9
Matrix properties — trace and scalar multiplication — solve for a11 (case 3) — Matrix Properties (9)

The matrix properties of a scaled transformation matrix are confirmed. Given a22 (a22) = 4.5000; scalar (k) = 3.6000; trace of kA (trkA) = 19.9000, determine the a11 (a11).

Given

  • a22(a22)=4.5000a22 (a22) = 4.5000
  • scalar(k)=3.6000scalar (k) = 3.6000
  • traceofkA(trkA)=19.9000trace of kA (trkA) = 19.9000

Find

a11 (a11)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except a11 is given, so isolate a11 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for a11:

    a11=tr(kA)k−a22a_{11} = \dfrac{\text{tr}(kA)}{k} - a_{22}
  3. Step 3

    Listthegivens:a22(a22)=4.5000,scalar(k)=3.6000,traceofkA(trkA)=19.9000List the givens: a22 (a22) = 4.5000, scalar (k) = 3.6000, trace of kA (trkA) = 19.9000
  4. Step 4 — Substitute the given values:

    a11=tr(kA)3.6000−4.5000a_{11} = \dfrac{\text{tr}(kA)}{3.6000} - 4.5000
  5. Step 5 — Evaluate:

    a11=1.0278a_{11} = 1.0278
  6. Step 6 — Check: returning a11 = 1.0278 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
a11=1.0278a_{11} = 1.0278

Why the other options are there

  • 2.0556 — kept a factor of two that cancels in the correct rearrangement.
  • 0.5139 — dropped that same factor in the other direction.
  • 1.1306 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

Example 10
Matrix properties — trace and scalar multiplication — solve for trace of kA (case 4) — Matrix Properties (10)

An engineer checks matrix properties while scaling a stiffness matrix. Given a11 (a11) = 5.0000; a22 (a22) = 10.0000; scalar (k) = 2.0000, determine the trace of kA (trkA).

Given

  • a11(a11)=5.0000a11 (a11) = 5.0000
  • a22(a22)=10.0000a22 (a22) = 10.0000
  • scalar(k)=2.0000scalar (k) = 2.0000

Find

trace of kA (trkA)

Start with the thinking

  • The governing relation printed in this handbook section is Matrix properties — trace and scalar multiplication.
  • Everything except trkA is given, so isolate trkA symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Matrix properties state that scaling a matrix by k scales its trace by the same factor k.

Step-by-step solution

  1. Step 1 — State the governing relation:

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)
  2. Step 2 — Rearrange symbolically for trkA:

    trkA=k(a11+a22)trkA = k (a_{11}+a_{22})
  3. Step 3

    Listthegivens:a11(a11)=5.0000,a22(a22)=10.0000,scalar(k)=2.0000List the givens: a11 (a11) = 5.0000, a22 (a22) = 10.0000, scalar (k) = 2.0000
  4. Step 4 — Substitute the given values:

    trkA=2.0000(5.0000+10.0000)trkA = 2.0000 (5.0000+10.0000)
  5. Step 5 — Evaluate:

    trkA=30.0000trkA = 30.0000
  6. Step 6 — Check: returning trkA = 30.0000 to

    tr(kA)=k tr(A)\text{tr}(kA) = k \, \text{tr}(A)

    reproduces the given quantities, and both sides carry the same units.

Answer:
trkA=30.0000trkA = 30.0000

Why the other options are there

  • 60.0000 — kept a factor of two that cancels in the correct rearrangement.
  • 15.0000 — dropped that same factor in the other direction.
  • 33.0000 — rounded an intermediate value before the final step.

Reference: FE Handbook — Matrix Properties

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