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Indefinite Integrals

Mathematics · FE Reference Handbook section

Mathematics
33 formulas
10 exam-style examples
~60 min
All Mathematics lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Indefinite integrals — power rule — solve for antiderivative value — Indefinite Integrals

A student evaluates the indefinite integral of a polynomial load function. Given coefficient (a) = 5.0000; exponent (n) = 4.0000; x-value (x) = 3.0000; constant of integration (C) = 4.5000, determine the antiderivative value (F).

Given

  • coefficient(a)=5.0000coefficient (a) = 5.0000
  • exponent(n)=4.0000exponent (n) = 4.0000
  • x−value(x)=3.0000x-value (x) = 3.0000
  • constantofintegration(C)=4.5000constant of integration (C) = 4.5000

Find

antiderivative value (F)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except F is given, so isolate F symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 1 — schematic for Indefinite integrals — power rule — solve for antiderivative value — Indefinite Integrals

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for F:

    F=an+1xn+1+CF = \dfrac{a}{n+1}x^{n+1} + C
  3. Step 3 — List the givens: coefficient (a) = 5.0000, exponent (n) = 4.0000, x-value (x) = 3.0000, constant of integration (C) = 4.5000.

  4. Step 4 — Substitute the given values:

    F=5.00004.0000+13.00004.0000+1+4.5000F = \dfrac{5.0000}{4.0000+1}3.0000^{4.0000+1} + 4.5000
  5. Step 5 — Evaluate:

    F=247.5F = 247.5
  6. Step 6 — Check: returning F = 247.5 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
F=247.5F = 247.5

Why the other options are there

  • 495.0 — kept a factor of two that cancels in the correct rearrangement.
  • 123.8 — dropped that same factor in the other direction.
  • 272.3 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 2
Indefinite integrals — power rule — solve for constant of integration — Indefinite Integrals (2)

An engineer integrates a velocity function to obtain the indefinite integral for displacement. Given coefficient (a) = 4.8000; exponent (n) = 3.0000; x-value (x) = 1.3000; antiderivative value (F) = 240.5, determine the constant of integration (C).

Given

  • coefficient(a)=4.8000coefficient (a) = 4.8000
  • exponent(n)=3.0000exponent (n) = 3.0000
  • x−value(x)=1.3000x-value (x) = 1.3000
  • antiderivativevalue(F)=240.5antiderivative value (F) = 240.5

Find

constant of integration (C)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 2 — schematic for Indefinite integrals — power rule — solve for constant of integration — Indefinite Integrals (2)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for C:

    C=F−an+1xn+1C = F - \dfrac{a}{n+1}x^{n+1}
  3. Step 3 — List the givens: coefficient (a) = 4.8000, exponent (n) = 3.0000, x-value (x) = 1.3000, antiderivative value (F) = 240.5.

  4. Step 4 — Substitute the given values:

    C=240.5−4.80003.0000+11.30003.0000+1C = 240.5 - \dfrac{4.8000}{3.0000+1}1.3000^{3.0000+1}
  5. Step 5 — Evaluate:

    C=237.1C = 237.1
  6. Step 6 — Check: returning C = 237.1 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=237.1C = 237.1

Why the other options are there

  • 474.1 — kept a factor of two that cancels in the correct rearrangement.
  • 118.5 — dropped that same factor in the other direction.
  • 260.8 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 3
Indefinite integrals — power rule — solve for coefficient — Indefinite Integrals (3)

The indefinite integral of an acceleration function is checked against a known constant. Given exponent (n) = 1.0000; x-value (x) = 3.7000; constant of integration (C) = 1.7000; antiderivative value (F) = 276.6, determine the coefficient (a).

Given

  • exponent(n)=1.0000exponent (n) = 1.0000
  • x−value(x)=3.7000x-value (x) = 3.7000
  • constantofintegration(C)=1.7000constant of integration (C) = 1.7000
  • antiderivativevalue(F)=276.6antiderivative value (F) = 276.6

Find

coefficient (a)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except a is given, so isolate a symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 3 — schematic for Indefinite integrals — power rule — solve for coefficient — Indefinite Integrals (3)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for a:

    a=(F−C)(n+1)xn+1a = \dfrac{(F-C)(n+1)}{x^{n+1}}
  3. Step 3 — List the givens: exponent (n) = 1.0000, x-value (x) = 3.7000, constant of integration (C) = 1.7000, antiderivative value (F) = 276.6.

  4. Step 4 — Substitute the given values:

    a=(276.6−1.7000)(1.0000+1)3.70001.0000+1a = \dfrac{(276.6-1.7000)(1.0000+1)}{3.7000^{1.0000+1}}
  5. Step 5 — Evaluate:

    a=40.1607a = 40.1607
  6. Step 6 — Check: returning a = 40.1607 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
a=40.1607a = 40.1607

Why the other options are there

  • 80.3214 — kept a factor of two that cancels in the correct rearrangement.
  • 20.0804 — dropped that same factor in the other direction.
  • 44.1768 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 4
Indefinite integrals — power rule — solve for antiderivative value (case 2) — Indefinite Integrals (4)

A student evaluates the indefinite integral of a polynomial load function. Given coefficient (a) = 3.1000; exponent (n) = 3.0000; x-value (x) = 3.0000; constant of integration (C) = 4.8000, determine the antiderivative value (F).

Given

  • coefficient(a)=3.1000coefficient (a) = 3.1000
  • exponent(n)=3.0000exponent (n) = 3.0000
  • x−value(x)=3.0000x-value (x) = 3.0000
  • constantofintegration(C)=4.8000constant of integration (C) = 4.8000

Find

antiderivative value (F)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except F is given, so isolate F symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 4 — schematic for Indefinite integrals — power rule — solve for antiderivative value (case 2) — Indefinite Integrals (4)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for F:

    F=an+1xn+1+CF = \dfrac{a}{n+1}x^{n+1} + C
  3. Step 3 — List the givens: coefficient (a) = 3.1000, exponent (n) = 3.0000, x-value (x) = 3.0000, constant of integration (C) = 4.8000.

  4. Step 4 — Substitute the given values:

    F=3.10003.0000+13.00003.0000+1+4.8000F = \dfrac{3.1000}{3.0000+1}3.0000^{3.0000+1} + 4.8000
  5. Step 5 — Evaluate:

    F=67.5750F = 67.5750
  6. Step 6 — Check: returning F = 67.5750 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
F=67.5750F = 67.5750

Why the other options are there

  • 135.2 — kept a factor of two that cancels in the correct rearrangement.
  • 33.7875 — dropped that same factor in the other direction.
  • 74.3325 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 5
Indefinite integrals — power rule — solve for constant of integration (case 2) — Indefinite Integrals (5)

An engineer integrates a velocity function to obtain the indefinite integral for displacement. Given coefficient (a) = 3.2000; exponent (n) = 4.0000; x-value (x) = 2.7000; antiderivative value (F) = 468.8, determine the constant of integration (C).

Given

  • coefficient(a)=3.2000coefficient (a) = 3.2000
  • exponent(n)=4.0000exponent (n) = 4.0000
  • x−value(x)=2.7000x-value (x) = 2.7000
  • antiderivativevalue(F)=468.8antiderivative value (F) = 468.8

Find

constant of integration (C)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 5 — schematic for Indefinite integrals — power rule — solve for constant of integration (case 2) — Indefinite Integrals (5)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for C:

    C=F−an+1xn+1C = F - \dfrac{a}{n+1}x^{n+1}
  3. Step 3 — List the givens: coefficient (a) = 3.2000, exponent (n) = 4.0000, x-value (x) = 2.7000, antiderivative value (F) = 468.8.

  4. Step 4 — Substitute the given values:

    C=468.8−3.20004.0000+12.70004.0000+1C = 468.8 - \dfrac{3.2000}{4.0000+1}2.7000^{4.0000+1}
  5. Step 5 — Evaluate:

    C=377.0C = 377.0
  6. Step 6 — Check: returning C = 377.0 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=377.0C = 377.0

Why the other options are there

  • 753.9 — kept a factor of two that cancels in the correct rearrangement.
  • 188.5 — dropped that same factor in the other direction.
  • 414.7 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 6
Indefinite integrals — power rule — solve for coefficient (case 2) — Indefinite Integrals (6)

The indefinite integral of an acceleration function is checked against a known constant. Given exponent (n) = 3.0000; x-value (x) = 3.5000; constant of integration (C) = -3.4000; antiderivative value (F) = 142.3, determine the coefficient (a).

Given

  • exponent(n)=3.0000exponent (n) = 3.0000
  • x−value(x)=3.5000x-value (x) = 3.5000
  • constantofintegration(C)=−3.4000constant of integration (C) = -3.4000
  • antiderivativevalue(F)=142.3antiderivative value (F) = 142.3

Find

coefficient (a)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except a is given, so isolate a symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 6 — schematic for Indefinite integrals — power rule — solve for coefficient (case 2) — Indefinite Integrals (6)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for a:

    a=(F−C)(n+1)xn+1a = \dfrac{(F-C)(n+1)}{x^{n+1}}
  3. Step 3 — List the givens: exponent (n) = 3.0000, x-value (x) = 3.5000, constant of integration (C) = -3.4000, antiderivative value (F) = 142.3.

  4. Step 4 — Substitute the given values:

    a=(142.3−−3.4000)(3.0000+1)3.50003.0000+1a = \dfrac{(142.3--3.4000)(3.0000+1)}{3.5000^{3.0000+1}}
  5. Step 5 — Evaluate:

    a=3.8837a = 3.8837
  6. Step 6 — Check: returning a = 3.8837 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
a=3.8837a = 3.8837

Why the other options are there

  • 7.7674 — kept a factor of two that cancels in the correct rearrangement.
  • 1.9419 — dropped that same factor in the other direction.
  • 4.2721 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 7
Indefinite integrals — power rule — solve for antiderivative value (case 3) — Indefinite Integrals (7)

A student evaluates the indefinite integral of a polynomial load function. Given coefficient (a) = 1.7000; exponent (n) = 4.0000; x-value (x) = 2.0000; constant of integration (C) = 0.8000, determine the antiderivative value (F).

Given

  • coefficient(a)=1.7000coefficient (a) = 1.7000
  • exponent(n)=4.0000exponent (n) = 4.0000
  • x−value(x)=2.0000x-value (x) = 2.0000
  • constantofintegration(C)=0.8000constant of integration (C) = 0.8000

Find

antiderivative value (F)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except F is given, so isolate F symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 7 — schematic for Indefinite integrals — power rule — solve for antiderivative value (case 3) — Indefinite Integrals (7)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for F:

    F=an+1xn+1+CF = \dfrac{a}{n+1}x^{n+1} + C
  3. Step 3 — List the givens: coefficient (a) = 1.7000, exponent (n) = 4.0000, x-value (x) = 2.0000, constant of integration (C) = 0.8000.

  4. Step 4 — Substitute the given values:

    F=1.70004.0000+12.00004.0000+1+0.8000F = \dfrac{1.7000}{4.0000+1}2.0000^{4.0000+1} + 0.8000
  5. Step 5 — Evaluate:

    F=11.6800F = 11.6800
  6. Step 6 — Check: returning F = 11.6800 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
F=11.6800F = 11.6800

Why the other options are there

  • 23.3600 — kept a factor of two that cancels in the correct rearrangement.
  • 5.8400 — dropped that same factor in the other direction.
  • 12.8480 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 8
Indefinite integrals — power rule — solve for constant of integration (case 3) — Indefinite Integrals (8)

An engineer integrates a velocity function to obtain the indefinite integral for displacement. Given coefficient (a) = 4.8000; exponent (n) = 3.0000; x-value (x) = 1.5000; antiderivative value (F) = 468.8, determine the constant of integration (C).

Given

  • coefficient(a)=4.8000coefficient (a) = 4.8000
  • exponent(n)=3.0000exponent (n) = 3.0000
  • x−value(x)=1.5000x-value (x) = 1.5000
  • antiderivativevalue(F)=468.8antiderivative value (F) = 468.8

Find

constant of integration (C)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 8 — schematic for Indefinite integrals — power rule — solve for constant of integration (case 3) — Indefinite Integrals (8)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for C:

    C=F−an+1xn+1C = F - \dfrac{a}{n+1}x^{n+1}
  3. Step 3 — List the givens: coefficient (a) = 4.8000, exponent (n) = 3.0000, x-value (x) = 1.5000, antiderivative value (F) = 468.8.

  4. Step 4 — Substitute the given values:

    C=468.8−4.80003.0000+11.50003.0000+1C = 468.8 - \dfrac{4.8000}{3.0000+1}1.5000^{3.0000+1}
  5. Step 5 — Evaluate:

    C=462.7C = 462.7
  6. Step 6 — Check: returning C = 462.7 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=462.7C = 462.7

Why the other options are there

  • 925.5 — kept a factor of two that cancels in the correct rearrangement.
  • 231.4 — dropped that same factor in the other direction.
  • 509.0 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 9
Indefinite integrals — power rule — solve for coefficient (case 3) — Indefinite Integrals (9)

The indefinite integral of an acceleration function is checked against a known constant. Given exponent (n) = 2.0000; x-value (x) = 1.1000; constant of integration (C) = -1.9000; antiderivative value (F) = 111.7, determine the coefficient (a).

Given

  • exponent(n)=2.0000exponent (n) = 2.0000
  • x−value(x)=1.1000x-value (x) = 1.1000
  • constantofintegration(C)=−1.9000constant of integration (C) = -1.9000
  • antiderivativevalue(F)=111.7antiderivative value (F) = 111.7

Find

coefficient (a)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except a is given, so isolate a symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 9 — schematic for Indefinite integrals — power rule — solve for coefficient (case 3) — Indefinite Integrals (9)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for a:

    a=(F−C)(n+1)xn+1a = \dfrac{(F-C)(n+1)}{x^{n+1}}
  3. Step 3 — List the givens: exponent (n) = 2.0000, x-value (x) = 1.1000, constant of integration (C) = -1.9000, antiderivative value (F) = 111.7.

  4. Step 4 — Substitute the given values:

    a=(111.7−−1.9000)(2.0000+1)1.10002.0000+1a = \dfrac{(111.7--1.9000)(2.0000+1)}{1.1000^{2.0000+1}}
  5. Step 5 — Evaluate:

    a=256.0a = 256.0
  6. Step 6 — Check: returning a = 256.0 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
a=256.0a = 256.0

Why the other options are there

  • 512.1 — kept a factor of two that cancels in the correct rearrangement.
  • 128.0 — dropped that same factor in the other direction.
  • 281.7 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

Example 10
Indefinite integrals — power rule — solve for antiderivative value (case 4) — Indefinite Integrals (10)

A student evaluates the indefinite integral of a polynomial load function. Given coefficient (a) = 4.4000; exponent (n) = 2.0000; x-value (x) = 1.0000; constant of integration (C) = 4.6000, determine the antiderivative value (F).

Given

  • coefficient(a)=4.4000coefficient (a) = 4.4000
  • exponent(n)=2.0000exponent (n) = 2.0000
  • x−value(x)=1.0000x-value (x) = 1.0000
  • constantofintegration(C)=4.6000constant of integration (C) = 4.6000

Find

antiderivative value (F)

Start with the thinking

  • The governing relation printed in this handbook section is Indefinite integrals — power rule.
  • Everything except F is given, so isolate F symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The power-rule indefinite integral gives the antiderivative of a x^n plus a constant of integration.
xyIndefinite integral (antiderivative)

Figure 10 — schematic for Indefinite integrals — power rule — solve for antiderivative value (case 4) — Indefinite Integrals (10)

Step-by-step solution

  1. Step 1 — State the governing relation:

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C
  2. Step 2 — Rearrange symbolically for F:

    F=an+1xn+1+CF = \dfrac{a}{n+1}x^{n+1} + C
  3. Step 3 — List the givens: coefficient (a) = 4.4000, exponent (n) = 2.0000, x-value (x) = 1.0000, constant of integration (C) = 4.6000.

  4. Step 4 — Substitute the given values:

    F=4.40002.0000+11.00002.0000+1+4.6000F = \dfrac{4.4000}{2.0000+1}1.0000^{2.0000+1} + 4.6000
  5. Step 5 — Evaluate:

    F=6.0667F = 6.0667
  6. Step 6 — Check: returning F = 6.0667 to

    ∫axn dx=an+1xn+1+C\int a x^n \, dx = \dfrac{a}{n+1} x^{n+1} + C

    reproduces the given quantities, and both sides carry the same units.

Answer:
F=6.0667F = 6.0667

Why the other options are there

  • 12.1333 — kept a factor of two that cancels in the correct rearrangement.
  • 3.0333 — dropped that same factor in the other direction.
  • 6.6733 — rounded an intermediate value before the final step.

Reference: FE Handbook — Indefinite Integrals

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