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First-Order Linear Difference Equation

Mathematics · FE Reference Handbook section

Mathematics
2 formulas
10 exam-style examples
~49 min
All Mathematics lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Slope–intercept line — solve for y-value — First-Order Linear Difference Equation

A mathematics problem uses Slope–intercept line. Given slope (m) = 2.6000; x-value (x) = 1.5000; intercept (b) = 8.0000, determine the y-value (y).

Given

  • slope(m)=2.6000slope (m) = 2.6000
  • x−value(x)=1.5000x-value (x) = 1.5000
  • intercept(b)=8.0000intercept (b) = 8.0000

Find

y-value (y)

Start with the thinking

  • The governing relation printed in this handbook section is Slope–intercept line.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=mx+by = m x + b
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:slope(m)=2.6000,x−value(x)=1.5000,intercept(b)=8.0000List the givens: slope (m) = 2.6000, x-value (x) = 1.5000, intercept (b) = 8.0000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=11.9000y = 11.9000
  6. Step 6 — Check: returning y = 11.9000 to

    y=mx+by = m x + b

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=11.9000y = 11.9000

Why the other options are there

  • 23.8000 — kept a factor of two that cancels in the correct rearrangement.
  • 5.9500 — dropped that same factor in the other direction.
  • 13.0900 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → First-Order Linear Difference Equation

Example 2
First-order linear ODE solution — solve for value at time t — First-Order Linear Difference Equation (2)

radioactive tracer decay in a groundwater test Given initial value (y_0) = 10.9000 mg/L; rate constant (k) = 0.5000 1/h; elapsed time (t) = 1.4000 h, determine the value at time t (y) in mg/L.

Given

  • initialvalue(y0)=10.9000mg/Linitial value (y_0) = 10.9000 mg/L
  • rateconstant(k)=0.50001/hrate constant (k) = 0.5000 1/h
  • elapsedtime(t)=1.4000helapsed time (t) = 1.4000 h

Find

value at time t (y), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order linear ODE solution.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The ODE y' + k y = 0 has the exponential solution shown.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y(t)=y0e−kty(t) = y_0 e^{-k t}
  2. Step 2 — Rearrange symbolically for y:

    y=y=y0e−kty = y = y_0 e^{-k t}
  3. Step 3 — List the givens: initial value (y_0) = 10.9000 mg/L, rate constant (k) = 0.5000 1/h, elapsed time (t) = 1.4000 h.

  4. Step 4 — Substitute the given values:

    y=y=y0e−0.50001.4000y = y = y_0 e^{-0.5000 1.4000}
  5. Step 5 — Evaluate:

    y=5.4128 mg/Ly = 5.4128\ \text{mg/L}
  6. Step 6 — Check: returning y = 5.4128 mg/L to

    y(t)=y0e−kty(t) = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=5.4128 mg/Ly = 5.4128\ \text{mg/L}

Why the other options are there

  • 10.8256 — kept a factor of two that cancels in the correct rearrangement.
  • 2.7064 — dropped that same factor in the other direction.
  • 5.9541 — rounded an intermediate value before the final step.

Reference: FE Handbook — Differential Equations (First Order)

Example 3
Slope–intercept line — solve for slope — First-Order Linear Difference Equation (3)

A mathematics problem uses Slope–intercept line. Given x-value (x) = 8.0000; intercept (b) = -9.0000; y-value (y) = -16.7000, determine the slope (m).

Given

  • x−value(x)=8.0000x-value (x) = 8.0000
  • intercept(b)=−9.0000intercept (b) = -9.0000
  • y−value(y)=−16.7000y-value (y) = -16.7000

Find

slope (m)

Start with the thinking

  • The governing relation printed in this handbook section is Slope–intercept line.
  • Everything except m is given, so isolate m symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=mx+by = m x + b
  2. Step 2 — Rearrange the relation so that m stands alone on the left-hand side.

  3. Step 3

    Listthegivens:x−value(x)=8.0000,intercept(b)=−9.0000,y−value(y)=−16.7000List the givens: x-value (x) = 8.0000, intercept (b) = -9.0000, y-value (y) = -16.7000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    m=−0.9625m = -0.9625
  6. Step 6 — Check: returning m = -0.9625 to

    y=mx+by = m x + b

    reproduces the given quantities, and both sides carry the same units.

Answer:
m=−0.9625m = -0.9625

Why the other options are there

  • -1.9250 — kept a factor of two that cancels in the correct rearrangement.
  • -0.4812 — dropped that same factor in the other direction.
  • -1.0588 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → First-Order Linear Difference Equation

Example 4
First-order linear ODE solution — solve for initial value — First-Order Linear Difference Equation (4)

temperature decay of a mass concrete pour Given value at time t (y) = 3.1000 mg/L; rate constant (k) = 0.5000 1/h; elapsed time (t) = 5.1000 h, determine the initial value (y_0) in mg/L.

Given

  • valueattimet(y)=3.1000mg/Lvalue at time t (y) = 3.1000 mg/L
  • rateconstant(k)=0.50001/hrate constant (k) = 0.5000 1/h
  • elapsedtime(t)=5.1000helapsed time (t) = 5.1000 h

Find

initial value (y_0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order linear ODE solution.
  • Everything except y_0 is given, so isolate y_0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The ODE y' + k y = 0 has the exponential solution shown.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y(t)=y0e−kty(t) = y_0 e^{-k t}
  2. Step 2 — Rearrange symbolically for y_0:

    y0=y0=yekty_{0} = y_0 = y e^{k t}
  3. Step 3 — List the givens: value at time t (y) = 3.1000 mg/L, rate constant (k) = 0.5000 1/h, elapsed time (t) = 5.1000 h.

  4. Step 4 — Substitute the given values:

    y0=y0=3.1000e0.50005.1000y_{0} = y_0 = 3.1000 e^{0.5000 5.1000}
  5. Step 5 — Evaluate:

    y0=39.7020 mg/Ly_{0} = 39.7020\ \text{mg/L}
  6. Step 6 — Check: returning y_0 = 39.7020 mg/L to

    y(t)=y0e−kty(t) = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y0=39.7020 mg/Ly_{0} = 39.7020\ \text{mg/L}

Why the other options are there

  • 79.4040 — kept a factor of two that cancels in the correct rearrangement.
  • 19.8510 — dropped that same factor in the other direction.
  • 43.6722 — rounded an intermediate value before the final step.

Reference: FE Handbook — Differential Equations (First Order)

Example 5
Slope–intercept line — solve for intercept — First-Order Linear Difference Equation (5)

A mathematics problem uses Slope–intercept line. Given slope (m) = 2.5000; x-value (x) = 9.0000; y-value (y) = 28.8000, determine the intercept (b).

Given

  • slope(m)=2.5000slope (m) = 2.5000
  • x−value(x)=9.0000x-value (x) = 9.0000
  • y−value(y)=28.8000y-value (y) = 28.8000

Find

intercept (b)

Start with the thinking

  • The governing relation printed in this handbook section is Slope–intercept line.
  • Everything except b is given, so isolate b symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=mx+by = m x + b
  2. Step 2 — Rearrange the relation so that b stands alone on the left-hand side.

  3. Step 3

    Listthegivens:slope(m)=2.5000,x−value(x)=9.0000,y−value(y)=28.8000List the givens: slope (m) = 2.5000, x-value (x) = 9.0000, y-value (y) = 28.8000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    b=6.3000b = 6.3000
  6. Step 6 — Check: returning b = 6.3000 to

    y=mx+by = m x + b

    reproduces the given quantities, and both sides carry the same units.

Answer:
b=6.3000b = 6.3000

Why the other options are there

  • 12.6000 — kept a factor of two that cancels in the correct rearrangement.
  • 3.1500 — dropped that same factor in the other direction.
  • 6.9300 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → First-Order Linear Difference Equation

Example 6
First-order linear ODE solution — solve for rate constant — First-Order Linear Difference Equation (6)

chlorine residual decay in a storage tank Given value at time t (y) = 3.0000 mg/L; initial value (y_0) = 10.1000 mg/L; elapsed time (t) = 9.5000 h, determine the rate constant (k) in 1/h.

Given

  • valueattimet(y)=3.0000mg/Lvalue at time t (y) = 3.0000 mg/L
  • initialvalue(y0)=10.1000mg/Linitial value (y_0) = 10.1000 mg/L
  • elapsedtime(t)=9.5000helapsed time (t) = 9.5000 h

Find

rate constant (k), in 1/h

Start with the thinking

  • The governing relation printed in this handbook section is First-order linear ODE solution.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The ODE y' + k y = 0 has the exponential solution shown.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y(t)=y0e−kty(t) = y_0 e^{-k t}
  2. Step 2 — Rearrange symbolically for k:

    k=k=ln⁡(y0/y)tk = k = \dfrac{\ln(y_0 / y)}{t}
  3. Step 3 — List the givens: value at time t (y) = 3.0000 mg/L, initial value (y_0) = 10.1000 mg/L, elapsed time (t) = 9.5000 h.

  4. Step 4 — Substitute the given values:

    k=k=ln⁡(y0/3.0000)9.5000k = k = \dfrac{\ln(y_0 / 3.0000)}{9.5000}
  5. Step 5 — Evaluate:

    k=0.1278 1/hk = 0.1278\ \text{1/h}
  6. Step 6 — Check: returning k = 0.1278 1/h to

    y(t)=y0e−kty(t) = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.1278 1/hk = 0.1278\ \text{1/h}

Why the other options are there

  • 0.2556 — kept a factor of two that cancels in the correct rearrangement.
  • 0.0639 — dropped that same factor in the other direction.
  • 0.1406 — rounded an intermediate value before the final step.

Reference: FE Handbook — Differential Equations (First Order)

Example 7
Slope–intercept line — solve for x-value — First-Order Linear Difference Equation (7)

A mathematics problem uses Slope–intercept line. Given slope (m) = 2.6000; intercept (b) = -6.0000; y-value (y) = 19.0000, determine the x-value (x).

Given

  • slope(m)=2.6000slope (m) = 2.6000
  • intercept(b)=−6.0000intercept (b) = -6.0000
  • y−value(y)=19.0000y-value (y) = 19.0000

Find

x-value (x)

Start with the thinking

  • The governing relation printed in this handbook section is Slope–intercept line.
  • Everything except x is given, so isolate x symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=mx+by = m x + b
  2. Step 2 — Rearrange the relation so that x stands alone on the left-hand side.

  3. Step 3

    Listthegivens:slope(m)=2.6000,intercept(b)=−6.0000,y−value(y)=19.0000List the givens: slope (m) = 2.6000, intercept (b) = -6.0000, y-value (y) = 19.0000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    x=9.6154x = 9.6154
  6. Step 6 — Check: returning x = 9.6154 to

    y=mx+by = m x + b

    reproduces the given quantities, and both sides carry the same units.

Answer:
x=9.6154x = 9.6154

Why the other options are there

  • 19.2308 — kept a factor of two that cancels in the correct rearrangement.
  • 4.8077 — dropped that same factor in the other direction.
  • 10.5769 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → First-Order Linear Difference Equation

Example 8
First-order linear ODE solution — solve for elapsed time — First-Order Linear Difference Equation (8)

radioactive tracer decay in a groundwater test Given value at time t (y) = 2.2000 mg/L; initial value (y_0) = 4.1000 mg/L; rate constant (k) = 0.6000 1/h, determine the elapsed time (t) in h.

Given

  • valueattimet(y)=2.2000mg/Lvalue at time t (y) = 2.2000 mg/L
  • initialvalue(y0)=4.1000mg/Linitial value (y_0) = 4.1000 mg/L
  • rateconstant(k)=0.60001/hrate constant (k) = 0.6000 1/h

Find

elapsed time (t), in h

Start with the thinking

  • The governing relation printed in this handbook section is First-order linear ODE solution.
  • Everything except t is given, so isolate t symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The ODE y' + k y = 0 has the exponential solution shown.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y(t)=y0e−kty(t) = y_0 e^{-k t}
  2. Step 2 — Rearrange symbolically for t:

    t=t=ln⁡(y0/y)kt = t = \dfrac{\ln(y_0 / y)}{k}
  3. Step 3 — List the givens: value at time t (y) = 2.2000 mg/L, initial value (y_0) = 4.1000 mg/L, rate constant (k) = 0.6000 1/h.

  4. Step 4 — Substitute the given values:

    t=t=ln⁡(y0/2.2000)0.6000t = t = \dfrac{\ln(y_0 / 2.2000)}{0.6000}
  5. Step 5 — Evaluate:

    t=1.0375 ht = 1.0375\ \text{h}
  6. Step 6 — Check: returning t = 1.0375 h to

    y(t)=y0e−kty(t) = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
t=1.0375 ht = 1.0375\ \text{h}

Why the other options are there

  • 2.0751 — kept a factor of two that cancels in the correct rearrangement.
  • 0.5188 — dropped that same factor in the other direction.
  • 1.1413 — rounded an intermediate value before the final step.

Reference: FE Handbook — Differential Equations (First Order)

Example 9
Slope–intercept line — solve for y-value (case 2) — First-Order Linear Difference Equation (9)

A mathematics problem uses Slope–intercept line. Given slope (m) = 1.4000; x-value (x) = 4.0000; intercept (b) = -6.5000, determine the y-value (y).

Given

  • slope(m)=1.4000slope (m) = 1.4000
  • x−value(x)=4.0000x-value (x) = 4.0000
  • intercept(b)=−6.5000intercept (b) = -6.5000

Find

y-value (y)

Start with the thinking

  • The governing relation printed in this handbook section is Slope–intercept line.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=mx+by = m x + b
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:slope(m)=1.4000,x−value(x)=4.0000,intercept(b)=−6.5000List the givens: slope (m) = 1.4000, x-value (x) = 4.0000, intercept (b) = -6.5000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=−0.9000y = -0.9000
  6. Step 6 — Check: returning y = -0.9000 to

    y=mx+by = m x + b

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=−0.9000y = -0.9000

Why the other options are there

  • -1.8000 — kept a factor of two that cancels in the correct rearrangement.
  • -0.4500 — dropped that same factor in the other direction.
  • -0.9900 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → First-Order Linear Difference Equation

Example 10
First-order linear ODE solution — solve for value at time t (case 2) — First-Order Linear Difference Equation (10)

temperature decay of a mass concrete pour Given initial value (y_0) = 11.3000 mg/L; rate constant (k) = 0.6000 1/h; elapsed time (t) = 9.4000 h, determine the value at time t (y) in mg/L.

Given

  • initialvalue(y0)=11.3000mg/Linitial value (y_0) = 11.3000 mg/L
  • rateconstant(k)=0.60001/hrate constant (k) = 0.6000 1/h
  • elapsedtime(t)=9.4000helapsed time (t) = 9.4000 h

Find

value at time t (y), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order linear ODE solution.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The ODE y' + k y = 0 has the exponential solution shown.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y(t)=y0e−kty(t) = y_0 e^{-k t}
  2. Step 2 — Rearrange symbolically for y:

    y=y=y0e−kty = y = y_0 e^{-k t}
  3. Step 3 — List the givens: initial value (y_0) = 11.3000 mg/L, rate constant (k) = 0.6000 1/h, elapsed time (t) = 9.4000 h.

  4. Step 4 — Substitute the given values:

    y=y=y0e−0.60009.4000y = y = y_0 e^{-0.6000 9.4000}
  5. Step 5 — Evaluate:

    y=0.0401 mg/Ly = 0.0401\ \text{mg/L}
  6. Step 6 — Check: returning y = 0.0401 mg/L to

    y(t)=y0e−kty(t) = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=0.0401 mg/Ly = 0.0401\ \text{mg/L}

Why the other options are there

  • 0.0803 — kept a factor of two that cancels in the correct rearrangement.
  • 0.0201 — dropped that same factor in the other direction.
  • 0.0442 — rounded an intermediate value before the final step.

Reference: FE Handbook — Differential Equations (First Order)

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