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Dispersion, Mean, Median, and Mode Values

Mathematics · FE Reference Handbook section

Mathematics
20 formulas
10 exam-style examples
~60 min
All Mathematics lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • The weighted arithmetic mean is
  • The variance of the population is the arithmetic mean of the squared deviations from the population mean. If µ is the arithmetic
  • mean of a discrete population of size N, the population variance is defined by
  • Standard deviation formulas (assuming statistical independence) are
  • The sample standard deviation is
  • When the discrete data are rearranged in increasing order and n is odd, the median is the value of the b n + 1 l item
  • The mode of a set of data is the value that occurs with greatest frequency.
  • The sample range R is the largest sample value minus the smallest sample value.
  • Engineering Probability and Statistics

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Exponential decay — solve for value at t — Dispersion, Mean, Median, and Mode Values

A mathematics problem uses Exponential decay. Given initial value (y0) = 23.5000; decay constant (k) = 1.5500 1/s; time (t) = 2.5000 s, determine the value at t (y).

Given

  • initialvalue(y0)=23.5000initial value (y_{0}) = 23.5000
  • decayconstant(k)=1.55001/sdecay constant (k) = 1.5500 1/s
  • time(t)=2.5000stime (t) = 2.5000 s

Find

value at t (y)

Start with the thinking

  • The governing relation printed in this handbook section is Exponential decay.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=y0e−kty = y_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3 — List the givens: initial value (y0) = 23.5000, decay constant (k) = 1.5500 1/s, time (t) = 2.5000 s.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=0.4877y = 0.4877
  6. Step 6 — Check: returning y = 0.4877 to

    y=y0e−kty = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=0.4877y = 0.4877

Why the other options are there

  • 0.9755 — kept a factor of two that cancels in the correct rearrangement.
  • 0.2439 — dropped that same factor in the other direction.
  • 0.5365 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Dispersion, Mean, Median, and Mode Values

Example 2
Dispersion, mean, median, and mode — solve for mean — Dispersion, Mean, Median, and Mode Values (2)

A student computes the mean of a data set to assess its dispersion. Given sum of values (sumx) = 476.0; number of values (n) = 30.0000; standard deviation (dispersion) (s) = 13.1300, determine the mean (xbar).

Given

  • sumofvalues(sumx)=476.0sum of values (sumx) = 476.0
  • numberofvalues(n)=30.0000number of values (n) = 30.0000
  • standarddeviation(dispersion)(s)=13.1300standard deviation (dispersion) (s) = 13.1300

Find

mean (xbar)

Start with the thinking

  • The governing relation printed in this handbook section is Dispersion, mean, median, and mode.
  • Everything except xbar is given, so isolate xbar symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The mean is the central measure used with median and mode to describe the dispersion of a data set.
Dispersion of sample values059141812Q118Q29Q315Q4frequency

Figure 2 — schematic for Dispersion, mean, median, and mode — solve for mean — Dispersion, Mean, Median, and Mode Values (2)

Step-by-step solution

  1. Step 1 — State the governing relation:

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}
  2. Step 2 — Rearrange symbolically for xbar:

    xbar=∑xinxbar = \dfrac{\sum x_i}{n}
  3. Step 3 — List the givens: sum of values (sumx) = 476.0, number of values (n) = 30.0000, standard deviation (dispersion) (s) = 13.1300.

  4. Step 4 — Substitute the given values:

    xbar=∑xi30.0000xbar = \dfrac{\sum x_i}{30.0000}
  5. Step 5 — Evaluate:

    xbar=15.8667xbar = 15.8667
  6. Step 6 — Check: returning xbar = 15.8667 to

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
xbar=15.8667xbar = 15.8667

Why the other options are there

  • 31.7333 — kept a factor of two that cancels in the correct rearrangement.
  • 7.9333 — dropped that same factor in the other direction.
  • 17.4533 — rounded an intermediate value before the final step.

Reference: FE Handbook — Dispersion, Mean, Median, and Mode Values

Example 3
Exponential decay — solve for initial value — Dispersion, Mean, Median, and Mode Values (3)

A mathematics problem uses Exponential decay. Given decay constant (k) = 1.4000 1/s; time (t) = 2.8500 s; value at t (y) = 32.6100, determine the initial value (y0).

Given

  • decayconstant(k)=1.40001/sdecay constant (k) = 1.4000 1/s
  • time(t)=2.8500stime (t) = 2.8500 s
  • valueatt(y)=32.6100value at t (y) = 32.6100

Find

initial value (y0)

Start with the thinking

  • The governing relation printed in this handbook section is Exponential decay.
  • Everything except y0 is given, so isolate y0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=y0e−kty = y_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that y0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:decayconstant(k)=1.40001/s,time(t)=2.8500s,valueatt(y)=32.6100List the givens: decay constant (k) = 1.4000 1/s, time (t) = 2.8500 s, value at t (y) = 32.6100
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y0=1763y_{0} = 1763
  6. Step 6 — Check: returning y0 = 1,763 to

    y=y0e−kty = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y0=1763y_{0} = 1763

Why the other options are there

  • 3,525 — kept a factor of two that cancels in the correct rearrangement.
  • 881.4 — dropped that same factor in the other direction.
  • 1,939 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Dispersion, Mean, Median, and Mode Values

Example 4
Dispersion, mean, median, and mode — solve for sum of values — Dispersion, Mean, Median, and Mode Values (4)

The mean value of test results is compared with the median and mode. Given number of values (n) = 24.0000; mean (xbar) = 94.1300; standard deviation (dispersion) (s) = 9.3800, determine the sum of values (sumx).

Given

  • numberofvalues(n)=24.0000number of values (n) = 24.0000
  • mean(xbar)=94.1300mean (xbar) = 94.1300
  • standarddeviation(dispersion)(s)=9.3800standard deviation (dispersion) (s) = 9.3800

Find

sum of values (sumx)

Start with the thinking

  • The governing relation printed in this handbook section is Dispersion, mean, median, and mode.
  • Everything except sumx is given, so isolate sumx symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The mean is the central measure used with median and mode to describe the dispersion of a data set.
Dispersion of sample values059141812Q118Q29Q315Q4frequency

Figure 4 — schematic for Dispersion, mean, median, and mode — solve for sum of values — Dispersion, Mean, Median, and Mode Values (4)

Step-by-step solution

  1. Step 1 — State the governing relation:

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}
  2. Step 2 — Rearrange symbolically for sumx:

    sumx=xˉ nsumx = \bar{x}\, n
  3. Step 3 — List the givens: number of values (n) = 24.0000, mean (xbar) = 94.1300, standard deviation (dispersion) (s) = 9.3800.

  4. Step 4 — Substitute the given values:

    sumx=xˉ 24.0000sumx = \bar{x}\, 24.0000
  5. Step 5 — Evaluate:

    sumx=2259sumx = 2259
  6. Step 6 — Check: returning sumx = 2,259 to

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
sumx=2259sumx = 2259

Why the other options are there

  • 4,518 — kept a factor of two that cancels in the correct rearrangement.
  • 1,130 — dropped that same factor in the other direction.
  • 2,485 — rounded an intermediate value before the final step.

Reference: FE Handbook — Dispersion, Mean, Median, and Mode Values

Example 5
Exponential decay — solve for decay constant — Dispersion, Mean, Median, and Mode Values (5)

A mathematics problem uses Exponential decay. Given initial value (y0) = 13.0000; time (t) = 1.0000 s; value at t (y) = 26.6400, determine the decay constant (k) in 1/s.

Given

  • initialvalue(y0)=13.0000initial value (y_{0}) = 13.0000
  • time(t)=1.0000stime (t) = 1.0000 s
  • valueatt(y)=26.6400value at t (y) = 26.6400

Find

decay constant (k), in 1/s

Start with the thinking

  • The governing relation printed in this handbook section is Exponential decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=y0e−kty = y_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:initialvalue(y0)=13.0000,time(t)=1.0000s,valueatt(y)=26.6400List the givens: initial value (y_{0}) = 13.0000, time (t) = 1.0000 s, value at t (y) = 26.6400
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−0.7175 1/sk = -0.7175\ \text{1/s}
  6. Step 6 — Check: returning k = -0.7175 1/s to

    y=y0e−kty = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−0.7175 1/sk = -0.7175\ \text{1/s}

Why the other options are there

  • -1.4349 — kept a factor of two that cancels in the correct rearrangement.
  • -0.3587 — dropped that same factor in the other direction.
  • -0.7892 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Dispersion, Mean, Median, and Mode Values

Example 6
Dispersion, mean, median, and mode — solve for number of values — Dispersion, Mean, Median, and Mode Values (6)

A quality engineer reports the mean, median, and mode of a batch of measurements. Given sum of values (sumx) = 221.0; mean (xbar) = 51.3200; standard deviation (dispersion) (s) = 18.8100, determine the number of values (n).

Given

  • sumofvalues(sumx)=221.0sum of values (sumx) = 221.0
  • mean(xbar)=51.3200mean (xbar) = 51.3200
  • standarddeviation(dispersion)(s)=18.8100standard deviation (dispersion) (s) = 18.8100

Find

number of values (n)

Start with the thinking

  • The governing relation printed in this handbook section is Dispersion, mean, median, and mode.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The mean is the central measure used with median and mode to describe the dispersion of a data set.
Dispersion of sample values059141812Q118Q29Q315Q4frequency

Figure 6 — schematic for Dispersion, mean, median, and mode — solve for number of values — Dispersion, Mean, Median, and Mode Values (6)

Step-by-step solution

  1. Step 1 — State the governing relation:

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}
  2. Step 2 — Rearrange symbolically for n:

    n=∑xixˉn = \dfrac{\sum x_i}{\bar{x}}
  3. Step 3 — List the givens: sum of values (sumx) = 221.0, mean (xbar) = 51.3200, standard deviation (dispersion) (s) = 18.8100.

  4. Step 4 — Substitute the given values:

    n=∑xixˉn = \dfrac{\sum x_i}{\bar{x}}
  5. Step 5 — Evaluate:

    n=4.3063n = 4.3063
  6. Step 6 — Check: returning n = 4.3063 to

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=4.3063n = 4.3063

Why the other options are there

  • 8.6126 — kept a factor of two that cancels in the correct rearrangement.
  • 2.1532 — dropped that same factor in the other direction.
  • 4.7369 — rounded an intermediate value before the final step.

Reference: FE Handbook — Dispersion, Mean, Median, and Mode Values

Example 7
Exponential decay — solve for time — Dispersion, Mean, Median, and Mode Values (7)

A mathematics problem uses Exponential decay. Given initial value (y0) = 47.0000; decay constant (k) = 0.6500 1/s; value at t (y) = 38.5100, determine the time (t) in s.

Given

  • initialvalue(y0)=47.0000initial value (y_{0}) = 47.0000
  • decayconstant(k)=0.65001/sdecay constant (k) = 0.6500 1/s
  • valueatt(y)=38.5100value at t (y) = 38.5100

Find

time (t), in s

Start with the thinking

  • The governing relation printed in this handbook section is Exponential decay.
  • Everything except t is given, so isolate t symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=y0e−kty = y_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that t stands alone on the left-hand side.

  3. Step 3 — List the givens: initial value (y0) = 47.0000, decay constant (k) = 0.6500 1/s, value at t (y) = 38.5100.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    t=0.3065 st = 0.3065\ \text{s}
  6. Step 6 — Check: returning t = 0.3065 s to

    y=y0e−kty = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
t=0.3065 st = 0.3065\ \text{s}

Why the other options are there

  • 0.6130 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1533 — dropped that same factor in the other direction.
  • 0.3372 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Dispersion, Mean, Median, and Mode Values

Example 8
Dispersion, mean, median, and mode — solve for mean (case 2) — Dispersion, Mean, Median, and Mode Values (8)

A student computes the mean of a data set to assess its dispersion. Given sum of values (sumx) = 75.0000; number of values (n) = 23.0000; standard deviation (dispersion) (s) = 1.3600, determine the mean (xbar).

Given

  • sumofvalues(sumx)=75.0000sum of values (sumx) = 75.0000
  • numberofvalues(n)=23.0000number of values (n) = 23.0000
  • standarddeviation(dispersion)(s)=1.3600standard deviation (dispersion) (s) = 1.3600

Find

mean (xbar)

Start with the thinking

  • The governing relation printed in this handbook section is Dispersion, mean, median, and mode.
  • Everything except xbar is given, so isolate xbar symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The mean is the central measure used with median and mode to describe the dispersion of a data set.
Dispersion of sample values059141812Q118Q29Q315Q4frequency

Figure 8 — schematic for Dispersion, mean, median, and mode — solve for mean (case 2) — Dispersion, Mean, Median, and Mode Values (8)

Step-by-step solution

  1. Step 1 — State the governing relation:

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}
  2. Step 2 — Rearrange symbolically for xbar:

    xbar=∑xinxbar = \dfrac{\sum x_i}{n}
  3. Step 3 — List the givens: sum of values (sumx) = 75.0000, number of values (n) = 23.0000, standard deviation (dispersion) (s) = 1.3600.

  4. Step 4 — Substitute the given values:

    xbar=∑xi23.0000xbar = \dfrac{\sum x_i}{23.0000}
  5. Step 5 — Evaluate:

    xbar=3.2609xbar = 3.2609
  6. Step 6 — Check: returning xbar = 3.2609 to

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
xbar=3.2609xbar = 3.2609

Why the other options are there

  • 6.5217 — kept a factor of two that cancels in the correct rearrangement.
  • 1.6304 — dropped that same factor in the other direction.
  • 3.5870 — rounded an intermediate value before the final step.

Reference: FE Handbook — Dispersion, Mean, Median, and Mode Values

Example 9
Exponential decay — solve for value at t (case 2) — Dispersion, Mean, Median, and Mode Values (9)

A mathematics problem uses Exponential decay. Given initial value (y0) = 5.5000; decay constant (k) = 1.0000 1/s; time (t) = 1.6000 s, determine the value at t (y).

Given

  • initialvalue(y0)=5.5000initial value (y_{0}) = 5.5000
  • decayconstant(k)=1.00001/sdecay constant (k) = 1.0000 1/s
  • time(t)=1.6000stime (t) = 1.6000 s

Find

value at t (y)

Start with the thinking

  • The governing relation printed in this handbook section is Exponential decay.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Mathematics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    y=y0e−kty = y_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3 — List the givens: initial value (y0) = 5.5000, decay constant (k) = 1.0000 1/s, time (t) = 1.6000 s.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=1.1104y = 1.1104
  6. Step 6 — Check: returning y = 1.1104 to

    y=y0e−kty = y_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=1.1104y = 1.1104

Why the other options are there

  • 2.2209 — kept a factor of two that cancels in the correct rearrangement.
  • 0.5552 — dropped that same factor in the other direction.
  • 1.2215 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Mathematics → Dispersion, Mean, Median, and Mode Values

Example 10
Dispersion, mean, median, and mode — solve for sum of values (case 2) — Dispersion, Mean, Median, and Mode Values (10)

The mean value of test results is compared with the median and mode. Given number of values (n) = 14.0000; mean (xbar) = 75.9800; standard deviation (dispersion) (s) = 2.6800, determine the sum of values (sumx).

Given

  • numberofvalues(n)=14.0000number of values (n) = 14.0000
  • mean(xbar)=75.9800mean (xbar) = 75.9800
  • standarddeviation(dispersion)(s)=2.6800standard deviation (dispersion) (s) = 2.6800

Find

sum of values (sumx)

Start with the thinking

  • The governing relation printed in this handbook section is Dispersion, mean, median, and mode.
  • Everything except sumx is given, so isolate sumx symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The mean is the central measure used with median and mode to describe the dispersion of a data set.
Dispersion of sample values059141812Q118Q29Q315Q4frequency

Figure 10 — schematic for Dispersion, mean, median, and mode — solve for sum of values (case 2) — Dispersion, Mean, Median, and Mode Values (10)

Step-by-step solution

  1. Step 1 — State the governing relation:

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}
  2. Step 2 — Rearrange symbolically for sumx:

    sumx=xˉ nsumx = \bar{x}\, n
  3. Step 3 — List the givens: number of values (n) = 14.0000, mean (xbar) = 75.9800, standard deviation (dispersion) (s) = 2.6800.

  4. Step 4 — Substitute the given values:

    sumx=xˉ 14.0000sumx = \bar{x}\, 14.0000
  5. Step 5 — Evaluate:

    sumx=1064sumx = 1064
  6. Step 6 — Check: returning sumx = 1,064 to

    xˉ=∑xin\bar{x} = \dfrac{\sum x_i}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
sumx=1064sumx = 1064

Why the other options are there

  • 2,127 — kept a factor of two that cancels in the correct rearrangement.
  • 531.9 — dropped that same factor in the other direction.
  • 1,170 — rounded an intermediate value before the final step.

Reference: FE Handbook — Dispersion, Mean, Median, and Mode Values

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