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Polymer Additives

Materials Science · FE Reference Handbook section

Materials Science
0 formulas
10 exam-style examples
~45 min
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Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • Chemicals and compounds are added to polymers to improve properties for commercial use. These substances, such as
  • plasticizers, improve formability during processing, while others increase strength or durability.
  • Plasticizers: vegetable oils, low molecular weight polymers or monomers
  • Flame retardants: halogenated paraffins, zinc borate, chlorinated phosphates
  • Ultraviolet or visible light resistance: carbon black

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

This section is conceptual; there are no equations to memorise.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Polymers — degree of polymerization — solve for degree of polymerization — Polymer Additives

A materials engineer computes the degree of polymerization for a batch of polymers. Given number-average molecular weight (Mn) = 195,500 g/mol; repeat unit molecular weight (M0) = 41.0000 g/mol, determine the degree of polymerization (DP).

Given

  • number−averagemolecularweight(Mn)=195,500g/molnumber-average molecular weight (Mn) = 195,500 g/mol
  • repeatunitmolecularweight(M0)=41.0000g/molrepeat unit molecular weight (M_{0}) = 41.0000 g/mol

Find

degree of polymerization (DP)

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except DP is given, so isolate DP symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for DP:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  3. Step 3 — List the givens: number-average molecular weight (Mn) = 195,500 g/mol, repeat unit molecular weight (M0) = 41.0000 g/mol.

  4. Step 4 — Substitute the given values:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  5. Step 5 — Evaluate:

    DP=4768DP = 4768
  6. Step 6 — Check: returning DP = 4,768 to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
DP=4768DP = 4768

Why the other options are there

  • 9,537 — kept a factor of two that cancels in the correct rearrangement.
  • 2,384 — dropped that same factor in the other direction.
  • 5,245 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 2
Polymers — degree of polymerization — solve for number-average molecular weight — Polymer Additives (2)

A student relates molecular weight to the degree of polymerization for a polymer chain. Given repeat unit molecular weight (M0) = 33.0000 g/mol; degree of polymerization (DP) = 4,455, determine the number-average molecular weight (Mn) in g/mol.

Given

  • repeatunitmolecularweight(M0)=33.0000g/molrepeat unit molecular weight (M_{0}) = 33.0000 g/mol
  • degreeofpolymerization(DP)=4,455degree of polymerization (DP) = 4,455

Find

number-average molecular weight (Mn), in g/mol

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except Mn is given, so isolate Mn symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for Mn:

    Mn=DP×M0Mn = DP \times M_0
  3. Step 3 — List the givens: repeat unit molecular weight (M0) = 33.0000 g/mol, degree of polymerization (DP) = 4,455.

  4. Step 4 — Substitute the given values:

    Mn=4455×M0Mn = 4455 \times M_0
  5. Step 5 — Evaluate:

    Mn=147015 g/molMn = 147015\ \text{g/mol}
  6. Step 6 — Check: returning Mn = 147,015 g/mol to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Mn=147015 g/molMn = 147015\ \text{g/mol}

Why the other options are there

  • 294,030 — kept a factor of two that cancels in the correct rearrangement.
  • 73,508 — dropped that same factor in the other direction.
  • 161,717 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 3
Polymers — degree of polymerization — solve for repeat unit molecular weight — Polymer Additives (3)

The polymer's degree of polymerization influences its mechanical strength. Given number-average molecular weight (Mn) = 163,000 g/mol; degree of polymerization (DP) = 5,422, determine the repeat unit molecular weight (M0) in g/mol.

Given

  • number−averagemolecularweight(Mn)=163,000g/molnumber-average molecular weight (Mn) = 163,000 g/mol
  • degreeofpolymerization(DP)=5,422degree of polymerization (DP) = 5,422

Find

repeat unit molecular weight (M0), in g/mol

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except M0 is given, so isolate M0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for M0:

    M0=MnDPM_{0} = \dfrac{M_n}{DP}
  3. Step 3

    Listthegivens:number−averagemolecularweight(Mn)=163,000g/mol,degreeofpolymerization(DP)=5,422List the givens: number-average molecular weight (Mn) = 163,000 g/mol, degree of polymerization (DP) = 5,422
  4. Step 4 — Substitute the given values:

    M0=Mn5422M_{0} = \dfrac{M_n}{5422}
  5. Step 5 — Evaluate:

    M0=30.0627 g/molM_{0} = 30.0627\ \text{g/mol}
  6. Step 6 — Check: returning M0 = 30.0627 g/mol to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
M0=30.0627 g/molM_{0} = 30.0627\ \text{g/mol}

Why the other options are there

  • 60.1254 — kept a factor of two that cancels in the correct rearrangement.
  • 15.0314 — dropped that same factor in the other direction.
  • 33.0690 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 4
Polymers — degree of polymerization — solve for degree of polymerization (case 2) — Polymer Additives (4)

A materials engineer computes the degree of polymerization for a batch of polymers. Given number-average molecular weight (Mn) = 164,500 g/mol; repeat unit molecular weight (M0) = 75.0000 g/mol, determine the degree of polymerization (DP).

Given

  • number−averagemolecularweight(Mn)=164,500g/molnumber-average molecular weight (Mn) = 164,500 g/mol
  • repeatunitmolecularweight(M0)=75.0000g/molrepeat unit molecular weight (M_{0}) = 75.0000 g/mol

Find

degree of polymerization (DP)

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except DP is given, so isolate DP symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for DP:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  3. Step 3 — List the givens: number-average molecular weight (Mn) = 164,500 g/mol, repeat unit molecular weight (M0) = 75.0000 g/mol.

  4. Step 4 — Substitute the given values:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  5. Step 5 — Evaluate:

    DP=2193DP = 2193
  6. Step 6 — Check: returning DP = 2,193 to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
DP=2193DP = 2193

Why the other options are there

  • 4,387 — kept a factor of two that cancels in the correct rearrangement.
  • 1,097 — dropped that same factor in the other direction.
  • 2,413 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 5
Polymers — degree of polymerization — solve for number-average molecular weight (case 2) — Polymer Additives (5)

A student relates molecular weight to the degree of polymerization for a polymer chain. Given repeat unit molecular weight (M0) = 108.0 g/mol; degree of polymerization (DP) = 3,821, determine the number-average molecular weight (Mn) in g/mol.

Given

  • repeatunitmolecularweight(M0)=108.0g/molrepeat unit molecular weight (M_{0}) = 108.0 g/mol
  • degreeofpolymerization(DP)=3,821degree of polymerization (DP) = 3,821

Find

number-average molecular weight (Mn), in g/mol

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except Mn is given, so isolate Mn symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for Mn:

    Mn=DP×M0Mn = DP \times M_0
  3. Step 3 — List the givens: repeat unit molecular weight (M0) = 108.0 g/mol, degree of polymerization (DP) = 3,821.

  4. Step 4 — Substitute the given values:

    Mn=3821×M0Mn = 3821 \times M_0
  5. Step 5 — Evaluate:

    Mn=412668 g/molMn = 412668\ \text{g/mol}
  6. Step 6 — Check: returning Mn = 412,668 g/mol to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Mn=412668 g/molMn = 412668\ \text{g/mol}

Why the other options are there

  • 825,336 — kept a factor of two that cancels in the correct rearrangement.
  • 206,334 — dropped that same factor in the other direction.
  • 453,935 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 6
Polymers — degree of polymerization — solve for repeat unit molecular weight (case 2) — Polymer Additives (6)

The polymer's degree of polymerization influences its mechanical strength. Given number-average molecular weight (Mn) = 117,500 g/mol; degree of polymerization (DP) = 3,596, determine the repeat unit molecular weight (M0) in g/mol.

Given

  • number−averagemolecularweight(Mn)=117,500g/molnumber-average molecular weight (Mn) = 117,500 g/mol
  • degreeofpolymerization(DP)=3,596degree of polymerization (DP) = 3,596

Find

repeat unit molecular weight (M0), in g/mol

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except M0 is given, so isolate M0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for M0:

    M0=MnDPM_{0} = \dfrac{M_n}{DP}
  3. Step 3

    Listthegivens:number−averagemolecularweight(Mn)=117,500g/mol,degreeofpolymerization(DP)=3,596List the givens: number-average molecular weight (Mn) = 117,500 g/mol, degree of polymerization (DP) = 3,596
  4. Step 4 — Substitute the given values:

    M0=Mn3596M_{0} = \dfrac{M_n}{3596}
  5. Step 5 — Evaluate:

    M0=32.6752 g/molM_{0} = 32.6752\ \text{g/mol}
  6. Step 6 — Check: returning M0 = 32.6752 g/mol to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
M0=32.6752 g/molM_{0} = 32.6752\ \text{g/mol}

Why the other options are there

  • 65.3504 — kept a factor of two that cancels in the correct rearrangement.
  • 16.3376 — dropped that same factor in the other direction.
  • 35.9427 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 7
Polymers — degree of polymerization — solve for degree of polymerization (case 3) — Polymer Additives (7)

A materials engineer computes the degree of polymerization for a batch of polymers. Given number-average molecular weight (Mn) = 108,000 g/mol; repeat unit molecular weight (M0) = 47.0000 g/mol, determine the degree of polymerization (DP).

Given

  • number−averagemolecularweight(Mn)=108,000g/molnumber-average molecular weight (Mn) = 108,000 g/mol
  • repeatunitmolecularweight(M0)=47.0000g/molrepeat unit molecular weight (M_{0}) = 47.0000 g/mol

Find

degree of polymerization (DP)

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except DP is given, so isolate DP symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for DP:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  3. Step 3 — List the givens: number-average molecular weight (Mn) = 108,000 g/mol, repeat unit molecular weight (M0) = 47.0000 g/mol.

  4. Step 4 — Substitute the given values:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  5. Step 5 — Evaluate:

    DP=2298DP = 2298
  6. Step 6 — Check: returning DP = 2,298 to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
DP=2298DP = 2298

Why the other options are there

  • 4,596 — kept a factor of two that cancels in the correct rearrangement.
  • 1,149 — dropped that same factor in the other direction.
  • 2,528 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 8
Polymers — degree of polymerization — solve for number-average molecular weight (case 3) — Polymer Additives (8)

A student relates molecular weight to the degree of polymerization for a polymer chain. Given repeat unit molecular weight (M0) = 115.0 g/mol; degree of polymerization (DP) = 2,441, determine the number-average molecular weight (Mn) in g/mol.

Given

  • repeatunitmolecularweight(M0)=115.0g/molrepeat unit molecular weight (M_{0}) = 115.0 g/mol
  • degreeofpolymerization(DP)=2,441degree of polymerization (DP) = 2,441

Find

number-average molecular weight (Mn), in g/mol

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except Mn is given, so isolate Mn symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for Mn:

    Mn=DP×M0Mn = DP \times M_0
  3. Step 3 — List the givens: repeat unit molecular weight (M0) = 115.0 g/mol, degree of polymerization (DP) = 2,441.

  4. Step 4 — Substitute the given values:

    Mn=2441×M0Mn = 2441 \times M_0
  5. Step 5 — Evaluate:

    Mn=280715 g/molMn = 280715\ \text{g/mol}
  6. Step 6 — Check: returning Mn = 280,715 g/mol to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Mn=280715 g/molMn = 280715\ \text{g/mol}

Why the other options are there

  • 561,430 — kept a factor of two that cancels in the correct rearrangement.
  • 140,358 — dropped that same factor in the other direction.
  • 308,787 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 9
Polymers — degree of polymerization — solve for repeat unit molecular weight (case 3) — Polymer Additives (9)

The polymer's degree of polymerization influences its mechanical strength. Given number-average molecular weight (Mn) = 152,000 g/mol; degree of polymerization (DP) = 5,583, determine the repeat unit molecular weight (M0) in g/mol.

Given

  • number−averagemolecularweight(Mn)=152,000g/molnumber-average molecular weight (Mn) = 152,000 g/mol
  • degreeofpolymerization(DP)=5,583degree of polymerization (DP) = 5,583

Find

repeat unit molecular weight (M0), in g/mol

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except M0 is given, so isolate M0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for M0:

    M0=MnDPM_{0} = \dfrac{M_n}{DP}
  3. Step 3

    Listthegivens:number−averagemolecularweight(Mn)=152,000g/mol,degreeofpolymerization(DP)=5,583List the givens: number-average molecular weight (Mn) = 152,000 g/mol, degree of polymerization (DP) = 5,583
  4. Step 4 — Substitute the given values:

    M0=Mn5583M_{0} = \dfrac{M_n}{5583}
  5. Step 5 — Evaluate:

    M0=27.2255 g/molM_{0} = 27.2255\ \text{g/mol}
  6. Step 6 — Check: returning M0 = 27.2255 g/mol to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
M0=27.2255 g/molM_{0} = 27.2255\ \text{g/mol}

Why the other options are there

  • 54.4510 — kept a factor of two that cancels in the correct rearrangement.
  • 13.6128 — dropped that same factor in the other direction.
  • 29.9481 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

Example 10
Polymers — degree of polymerization — solve for degree of polymerization (case 4) — Polymer Additives (10)

A materials engineer computes the degree of polymerization for a batch of polymers. Given number-average molecular weight (Mn) = 137,500 g/mol; repeat unit molecular weight (M0) = 119.0 g/mol, determine the degree of polymerization (DP).

Given

  • number−averagemolecularweight(Mn)=137,500g/molnumber-average molecular weight (Mn) = 137,500 g/mol
  • repeatunitmolecularweight(M0)=119.0g/molrepeat unit molecular weight (M_{0}) = 119.0 g/mol

Find

degree of polymerization (DP)

Start with the thinking

  • The governing relation printed in this handbook section is Polymers — degree of polymerization.
  • Everything except DP is given, so isolate DP symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Polymers are characterized by their degree of polymerization, the ratio of chain molecular weight to repeat unit weight.

Step-by-step solution

  1. Step 1 — State the governing relation:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  2. Step 2 — Rearrange symbolically for DP:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  3. Step 3 — List the givens: number-average molecular weight (Mn) = 137,500 g/mol, repeat unit molecular weight (M0) = 119.0 g/mol.

  4. Step 4 — Substitute the given values:

    DP=MnM0DP = \dfrac{M_n}{M_0}
  5. Step 5 — Evaluate:

    DP=1155DP = 1155
  6. Step 6 — Check: returning DP = 1,155 to

    DP=MnM0DP = \dfrac{M_n}{M_0}

    reproduces the given quantities, and both sides carry the same units.

Answer:
DP=1155DP = 1155

Why the other options are there

  • 2,311 — kept a factor of two that cancels in the correct rearrangement.
  • 577.7 — dropped that same factor in the other direction.
  • 1,271 — rounded an intermediate value before the final step.

Reference: FE Handbook — Polymers

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