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Composite Materials

Materials Science · FE Reference Handbook section

Materials Science
14 formulas
10 exam-style examples
~60 min
All Materials Science lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • Also, for axially oriented, long, fiber-reinforced composites, the strains of the two components are equal.

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Composite materials — rule of mixtures modulus — solve for composite modulus — Composite Materials

An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 30.0000 Msi; matrix modulus (Em) = 0.9000 Msi; fiber volume fraction (Vf) = 0.1900, determine the composite modulus (Ec) in Msi.

Given

  • fibermodulus(Ef)=30.0000Msifiber modulus (Ef) = 30.0000 Msi
  • matrixmodulus(Em)=0.9000Msimatrix modulus (Em) = 0.9000 Msi
  • fibervolumefraction(Vf)=0.1900fiber volume fraction (Vf) = 0.1900

Find

composite modulus (Ec), in Msi

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Ec:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  3. Step 3 — List the givens: fiber modulus (Ef) = 30.0000 Msi, matrix modulus (Em) = 0.9000 Msi, fiber volume fraction (Vf) = 0.1900.

  4. Step 4 — Substitute the given values:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  5. Step 5 — Evaluate:

    Ec=6.4290 MsiEc = 6.4290\ \text{Msi}
  6. Step 6 — Check: returning Ec = 6.4290 Msi to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Ec=6.4290 MsiEc = 6.4290\ \text{Msi}

Why the other options are there

  • 12.8580 — kept a factor of two that cancels in the correct rearrangement.
  • 3.2145 — dropped that same factor in the other direction.
  • 7.0719 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 2
Composite materials — rule of mixtures modulus — solve for fiber volume fraction — Composite Materials (2)

A student applies the rule of mixtures to estimate a composite material's stiffness. Given fiber modulus (Ef) = 25.5000 Msi; matrix modulus (Em) = 1.9000 Msi; composite modulus (Ec) = 8.2500 Msi, determine the fiber volume fraction (Vf).

Given

  • fibermodulus(Ef)=25.5000Msifiber modulus (Ef) = 25.5000 Msi
  • matrixmodulus(Em)=1.9000Msimatrix modulus (Em) = 1.9000 Msi
  • compositemodulus(Ec)=8.2500Msicomposite modulus (Ec) = 8.2500 Msi

Find

fiber volume fraction (Vf)

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Vf is given, so isolate Vf symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Vf:

    Vf=Ec−EmEf−EmVf = \dfrac{E_c - E_m}{E_f - E_m}
  3. Step 3 — List the givens: fiber modulus (Ef) = 25.5000 Msi, matrix modulus (Em) = 1.9000 Msi, composite modulus (Ec) = 8.2500 Msi.

  4. Step 4 — Substitute the given values:

    Vf=Ec−EmEf−EmVf = \dfrac{E_c - E_m}{E_f - E_m}
  5. Step 5 — Evaluate:

    Vf=0.2691Vf = 0.2691
  6. Step 6 — Check: returning Vf = 0.2691 to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Vf=0.2691Vf = 0.2691

Why the other options are there

  • 0.5381 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1345 — dropped that same factor in the other direction.
  • 0.2960 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 3
Composite materials — rule of mixtures modulus — solve for fiber modulus — Composite Materials (3)

The composite material's modulus is checked against fiber and matrix properties. Given matrix modulus (Em) = 0.5000 Msi; fiber volume fraction (Vf) = 0.3000; composite modulus (Ec) = 29.6900 Msi, determine the fiber modulus (Ef) in Msi.

Given

  • matrixmodulus(Em)=0.5000Msimatrix modulus (Em) = 0.5000 Msi
  • fibervolumefraction(Vf)=0.3000fiber volume fraction (Vf) = 0.3000
  • compositemodulus(Ec)=29.6900Msicomposite modulus (Ec) = 29.6900 Msi

Find

fiber modulus (Ef), in Msi

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Ef is given, so isolate Ef symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Ef:

    Ef=Ec−Em(1−Vf)VfEf = \dfrac{E_c - E_m(1-V_f)}{V_f}
  3. Step 3 — List the givens: matrix modulus (Em) = 0.5000 Msi, fiber volume fraction (Vf) = 0.3000, composite modulus (Ec) = 29.6900 Msi.

  4. Step 4 — Substitute the given values:

    Ef=Ec−Em(1−Vf)VfEf = \dfrac{E_c - E_m(1-V_f)}{V_f}
  5. Step 5 — Evaluate:

    Ef=97.8000 MsiEf = 97.8000\ \text{Msi}
  6. Step 6 — Check: returning Ef = 97.8000 Msi to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Ef=97.8000 MsiEf = 97.8000\ \text{Msi}

Why the other options are there

  • 195.6 — kept a factor of two that cancels in the correct rearrangement.
  • 48.9000 — dropped that same factor in the other direction.
  • 107.6 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 4
Composite materials — rule of mixtures modulus — solve for composite modulus (case 2) — Composite Materials (4)

An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 30.0000 Msi; matrix modulus (Em) = 1.0500 Msi; fiber volume fraction (Vf) = 0.5200, determine the composite modulus (Ec) in Msi.

Given

  • fibermodulus(Ef)=30.0000Msifiber modulus (Ef) = 30.0000 Msi
  • matrixmodulus(Em)=1.0500Msimatrix modulus (Em) = 1.0500 Msi
  • fibervolumefraction(Vf)=0.5200fiber volume fraction (Vf) = 0.5200

Find

composite modulus (Ec), in Msi

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Ec:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  3. Step 3 — List the givens: fiber modulus (Ef) = 30.0000 Msi, matrix modulus (Em) = 1.0500 Msi, fiber volume fraction (Vf) = 0.5200.

  4. Step 4 — Substitute the given values:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  5. Step 5 — Evaluate:

    Ec=16.1040 MsiEc = 16.1040\ \text{Msi}
  6. Step 6 — Check: returning Ec = 16.1040 Msi to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Ec=16.1040 MsiEc = 16.1040\ \text{Msi}

Why the other options are there

  • 32.2080 — kept a factor of two that cancels in the correct rearrangement.
  • 8.0520 — dropped that same factor in the other direction.
  • 17.7144 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 5
Composite materials — rule of mixtures modulus — solve for fiber volume fraction (case 2) — Composite Materials (5)

A student applies the rule of mixtures to estimate a composite material's stiffness. Given fiber modulus (Ef) = 18.5000 Msi; matrix modulus (Em) = 1.3500 Msi; composite modulus (Ec) = 16.1800 Msi, determine the fiber volume fraction (Vf).

Given

  • fibermodulus(Ef)=18.5000Msifiber modulus (Ef) = 18.5000 Msi
  • matrixmodulus(Em)=1.3500Msimatrix modulus (Em) = 1.3500 Msi
  • compositemodulus(Ec)=16.1800Msicomposite modulus (Ec) = 16.1800 Msi

Find

fiber volume fraction (Vf)

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Vf is given, so isolate Vf symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Vf:

    Vf=Ec−EmEf−EmVf = \dfrac{E_c - E_m}{E_f - E_m}
  3. Step 3 — List the givens: fiber modulus (Ef) = 18.5000 Msi, matrix modulus (Em) = 1.3500 Msi, composite modulus (Ec) = 16.1800 Msi.

  4. Step 4 — Substitute the given values:

    Vf=Ec−EmEf−EmVf = \dfrac{E_c - E_m}{E_f - E_m}
  5. Step 5 — Evaluate:

    Vf=0.8647Vf = 0.8647
  6. Step 6 — Check: returning Vf = 0.8647 to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Vf=0.8647Vf = 0.8647

Why the other options are there

  • 1.7294 — kept a factor of two that cancels in the correct rearrangement.
  • 0.4324 — dropped that same factor in the other direction.
  • 0.9512 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 6
Composite materials — rule of mixtures modulus — solve for fiber modulus (case 2) — Composite Materials (6)

The composite material's modulus is checked against fiber and matrix properties. Given matrix modulus (Em) = 0.8000 Msi; fiber volume fraction (Vf) = 0.2000; composite modulus (Ec) = 13.0900 Msi, determine the fiber modulus (Ef) in Msi.

Given

  • matrixmodulus(Em)=0.8000Msimatrix modulus (Em) = 0.8000 Msi
  • fibervolumefraction(Vf)=0.2000fiber volume fraction (Vf) = 0.2000
  • compositemodulus(Ec)=13.0900Msicomposite modulus (Ec) = 13.0900 Msi

Find

fiber modulus (Ef), in Msi

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Ef is given, so isolate Ef symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Ef:

    Ef=Ec−Em(1−Vf)VfEf = \dfrac{E_c - E_m(1-V_f)}{V_f}
  3. Step 3 — List the givens: matrix modulus (Em) = 0.8000 Msi, fiber volume fraction (Vf) = 0.2000, composite modulus (Ec) = 13.0900 Msi.

  4. Step 4 — Substitute the given values:

    Ef=Ec−Em(1−Vf)VfEf = \dfrac{E_c - E_m(1-V_f)}{V_f}
  5. Step 5 — Evaluate:

    Ef=62.2500 MsiEf = 62.2500\ \text{Msi}
  6. Step 6 — Check: returning Ef = 62.2500 Msi to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Ef=62.2500 MsiEf = 62.2500\ \text{Msi}

Why the other options are there

  • 124.5 — kept a factor of two that cancels in the correct rearrangement.
  • 31.1250 — dropped that same factor in the other direction.
  • 68.4750 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 7
Composite materials — rule of mixtures modulus — solve for composite modulus (case 3) — Composite Materials (7)

An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 36.0000 Msi; matrix modulus (Em) = 0.8500 Msi; fiber volume fraction (Vf) = 0.7000, determine the composite modulus (Ec) in Msi.

Given

  • fibermodulus(Ef)=36.0000Msifiber modulus (Ef) = 36.0000 Msi
  • matrixmodulus(Em)=0.8500Msimatrix modulus (Em) = 0.8500 Msi
  • fibervolumefraction(Vf)=0.7000fiber volume fraction (Vf) = 0.7000

Find

composite modulus (Ec), in Msi

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Ec:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  3. Step 3 — List the givens: fiber modulus (Ef) = 36.0000 Msi, matrix modulus (Em) = 0.8500 Msi, fiber volume fraction (Vf) = 0.7000.

  4. Step 4 — Substitute the given values:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  5. Step 5 — Evaluate:

    Ec=25.4550 MsiEc = 25.4550\ \text{Msi}
  6. Step 6 — Check: returning Ec = 25.4550 Msi to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Ec=25.4550 MsiEc = 25.4550\ \text{Msi}

Why the other options are there

  • 50.9100 — kept a factor of two that cancels in the correct rearrangement.
  • 12.7275 — dropped that same factor in the other direction.
  • 28.0005 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 8
Composite materials — rule of mixtures modulus — solve for fiber volume fraction (case 3) — Composite Materials (8)

A student applies the rule of mixtures to estimate a composite material's stiffness. Given fiber modulus (Ef) = 28.0000 Msi; matrix modulus (Em) = 1.0000 Msi; composite modulus (Ec) = 13.1000 Msi, determine the fiber volume fraction (Vf).

Given

  • fibermodulus(Ef)=28.0000Msifiber modulus (Ef) = 28.0000 Msi
  • matrixmodulus(Em)=1.0000Msimatrix modulus (Em) = 1.0000 Msi
  • compositemodulus(Ec)=13.1000Msicomposite modulus (Ec) = 13.1000 Msi

Find

fiber volume fraction (Vf)

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Vf is given, so isolate Vf symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Vf:

    Vf=Ec−EmEf−EmVf = \dfrac{E_c - E_m}{E_f - E_m}
  3. Step 3 — List the givens: fiber modulus (Ef) = 28.0000 Msi, matrix modulus (Em) = 1.0000 Msi, composite modulus (Ec) = 13.1000 Msi.

  4. Step 4 — Substitute the given values:

    Vf=Ec−EmEf−EmVf = \dfrac{E_c - E_m}{E_f - E_m}
  5. Step 5 — Evaluate:

    Vf=0.4481Vf = 0.4481
  6. Step 6 — Check: returning Vf = 0.4481 to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Vf=0.4481Vf = 0.4481

Why the other options are there

  • 0.8963 — kept a factor of two that cancels in the correct rearrangement.
  • 0.2241 — dropped that same factor in the other direction.
  • 0.4930 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 9
Composite materials — rule of mixtures modulus — solve for fiber modulus (case 3) — Composite Materials (9)

The composite material's modulus is checked against fiber and matrix properties. Given matrix modulus (Em) = 1.7000 Msi; fiber volume fraction (Vf) = 0.4800; composite modulus (Ec) = 15.4400 Msi, determine the fiber modulus (Ef) in Msi.

Given

  • matrixmodulus(Em)=1.7000Msimatrix modulus (Em) = 1.7000 Msi
  • fibervolumefraction(Vf)=0.4800fiber volume fraction (Vf) = 0.4800
  • compositemodulus(Ec)=15.4400Msicomposite modulus (Ec) = 15.4400 Msi

Find

fiber modulus (Ef), in Msi

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Ef is given, so isolate Ef symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Ef:

    Ef=Ec−Em(1−Vf)VfEf = \dfrac{E_c - E_m(1-V_f)}{V_f}
  3. Step 3 — List the givens: matrix modulus (Em) = 1.7000 Msi, fiber volume fraction (Vf) = 0.4800, composite modulus (Ec) = 15.4400 Msi.

  4. Step 4 — Substitute the given values:

    Ef=Ec−Em(1−Vf)VfEf = \dfrac{E_c - E_m(1-V_f)}{V_f}
  5. Step 5 — Evaluate:

    Ef=30.3250 MsiEf = 30.3250\ \text{Msi}
  6. Step 6 — Check: returning Ef = 30.3250 Msi to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Ef=30.3250 MsiEf = 30.3250\ \text{Msi}

Why the other options are there

  • 60.6500 — kept a factor of two that cancels in the correct rearrangement.
  • 15.1625 — dropped that same factor in the other direction.
  • 33.3575 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

Example 10
Composite materials — rule of mixtures modulus — solve for composite modulus (case 4) — Composite Materials (10)

An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 15.5000 Msi; matrix modulus (Em) = 1.7500 Msi; fiber volume fraction (Vf) = 0.6000, determine the composite modulus (Ec) in Msi.

Given

  • fibermodulus(Ef)=15.5000Msifiber modulus (Ef) = 15.5000 Msi
  • matrixmodulus(Em)=1.7500Msimatrix modulus (Em) = 1.7500 Msi
  • fibervolumefraction(Vf)=0.6000fiber volume fraction (Vf) = 0.6000

Find

composite modulus (Ec), in Msi

Start with the thinking

  • The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
  • Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)
  2. Step 2 — Rearrange symbolically for Ec:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  3. Step 3 — List the givens: fiber modulus (Ef) = 15.5000 Msi, matrix modulus (Em) = 1.7500 Msi, fiber volume fraction (Vf) = 0.6000.

  4. Step 4 — Substitute the given values:

    Ec=EfVf+Em(1−Vf)Ec = E_f V_f + E_m(1-V_f)
  5. Step 5 — Evaluate:

    Ec=10.0000 MsiEc = 10.0000\ \text{Msi}
  6. Step 6 — Check: returning Ec = 10.0000 Msi to

    Ec=EfVf+Em(1−Vf)E_c = E_f V_f + E_m (1-V_f)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Ec=10.0000 MsiEc = 10.0000\ \text{Msi}

Why the other options are there

  • 20.0000 — kept a factor of two that cancels in the correct rearrangement.
  • 5.0000 — dropped that same factor in the other direction.
  • 11.0000 — rounded an intermediate value before the final step.

Reference: FE Handbook — Composite Materials

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