Composite Materials
Materials Science · FE Reference Handbook section
Handbook notes for this section
Definitions and conditions exactly as the handbook states them.
- Also, for axially oriented, long, fiber-reinforced composites, the strains of the two components are equal.
Core formulas for this FE topic
Definitions, applicability, units, assumptions and worked examples for each relation.
Worked exam-style examples
The four ways this section is written on the real exam — thoughts first, then equations, then substitution.
An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 30.0000 Msi; matrix modulus (Em) = 0.9000 Msi; fiber volume fraction (Vf) = 0.1900, determine the composite modulus (Ec) in Msi.
Given
Find
composite modulus (Ec), in Msi
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Ec:
Step 3 — List the givens: fiber modulus (Ef) = 30.0000 Msi, matrix modulus (Em) = 0.9000 Msi, fiber volume fraction (Vf) = 0.1900.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Ec = 6.4290 Msi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 12.8580 — kept a factor of two that cancels in the correct rearrangement.
- 3.2145 — dropped that same factor in the other direction.
- 7.0719 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
A student applies the rule of mixtures to estimate a composite material's stiffness. Given fiber modulus (Ef) = 25.5000 Msi; matrix modulus (Em) = 1.9000 Msi; composite modulus (Ec) = 8.2500 Msi, determine the fiber volume fraction (Vf).
Given
Find
fiber volume fraction (Vf)
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Vf is given, so isolate Vf symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Vf:
Step 3 — List the givens: fiber modulus (Ef) = 25.5000 Msi, matrix modulus (Em) = 1.9000 Msi, composite modulus (Ec) = 8.2500 Msi.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Vf = 0.2691 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 0.5381 — kept a factor of two that cancels in the correct rearrangement.
- 0.1345 — dropped that same factor in the other direction.
- 0.2960 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
The composite material's modulus is checked against fiber and matrix properties. Given matrix modulus (Em) = 0.5000 Msi; fiber volume fraction (Vf) = 0.3000; composite modulus (Ec) = 29.6900 Msi, determine the fiber modulus (Ef) in Msi.
Given
Find
fiber modulus (Ef), in Msi
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Ef is given, so isolate Ef symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Ef:
Step 3 — List the givens: matrix modulus (Em) = 0.5000 Msi, fiber volume fraction (Vf) = 0.3000, composite modulus (Ec) = 29.6900 Msi.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Ef = 97.8000 Msi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 195.6 — kept a factor of two that cancels in the correct rearrangement.
- 48.9000 — dropped that same factor in the other direction.
- 107.6 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 30.0000 Msi; matrix modulus (Em) = 1.0500 Msi; fiber volume fraction (Vf) = 0.5200, determine the composite modulus (Ec) in Msi.
Given
Find
composite modulus (Ec), in Msi
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Ec:
Step 3 — List the givens: fiber modulus (Ef) = 30.0000 Msi, matrix modulus (Em) = 1.0500 Msi, fiber volume fraction (Vf) = 0.5200.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Ec = 16.1040 Msi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 32.2080 — kept a factor of two that cancels in the correct rearrangement.
- 8.0520 — dropped that same factor in the other direction.
- 17.7144 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
A student applies the rule of mixtures to estimate a composite material's stiffness. Given fiber modulus (Ef) = 18.5000 Msi; matrix modulus (Em) = 1.3500 Msi; composite modulus (Ec) = 16.1800 Msi, determine the fiber volume fraction (Vf).
Given
Find
fiber volume fraction (Vf)
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Vf is given, so isolate Vf symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Vf:
Step 3 — List the givens: fiber modulus (Ef) = 18.5000 Msi, matrix modulus (Em) = 1.3500 Msi, composite modulus (Ec) = 16.1800 Msi.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Vf = 0.8647 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 1.7294 — kept a factor of two that cancels in the correct rearrangement.
- 0.4324 — dropped that same factor in the other direction.
- 0.9512 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
The composite material's modulus is checked against fiber and matrix properties. Given matrix modulus (Em) = 0.8000 Msi; fiber volume fraction (Vf) = 0.2000; composite modulus (Ec) = 13.0900 Msi, determine the fiber modulus (Ef) in Msi.
Given
Find
fiber modulus (Ef), in Msi
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Ef is given, so isolate Ef symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Ef:
Step 3 — List the givens: matrix modulus (Em) = 0.8000 Msi, fiber volume fraction (Vf) = 0.2000, composite modulus (Ec) = 13.0900 Msi.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Ef = 62.2500 Msi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 124.5 — kept a factor of two that cancels in the correct rearrangement.
- 31.1250 — dropped that same factor in the other direction.
- 68.4750 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 36.0000 Msi; matrix modulus (Em) = 0.8500 Msi; fiber volume fraction (Vf) = 0.7000, determine the composite modulus (Ec) in Msi.
Given
Find
composite modulus (Ec), in Msi
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Ec:
Step 3 — List the givens: fiber modulus (Ef) = 36.0000 Msi, matrix modulus (Em) = 0.8500 Msi, fiber volume fraction (Vf) = 0.7000.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Ec = 25.4550 Msi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 50.9100 — kept a factor of two that cancels in the correct rearrangement.
- 12.7275 — dropped that same factor in the other direction.
- 28.0005 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
A student applies the rule of mixtures to estimate a composite material's stiffness. Given fiber modulus (Ef) = 28.0000 Msi; matrix modulus (Em) = 1.0000 Msi; composite modulus (Ec) = 13.1000 Msi, determine the fiber volume fraction (Vf).
Given
Find
fiber volume fraction (Vf)
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Vf is given, so isolate Vf symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Vf:
Step 3 — List the givens: fiber modulus (Ef) = 28.0000 Msi, matrix modulus (Em) = 1.0000 Msi, composite modulus (Ec) = 13.1000 Msi.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Vf = 0.4481 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 0.8963 — kept a factor of two that cancels in the correct rearrangement.
- 0.2241 — dropped that same factor in the other direction.
- 0.4930 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
The composite material's modulus is checked against fiber and matrix properties. Given matrix modulus (Em) = 1.7000 Msi; fiber volume fraction (Vf) = 0.4800; composite modulus (Ec) = 15.4400 Msi, determine the fiber modulus (Ef) in Msi.
Given
Find
fiber modulus (Ef), in Msi
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Ef is given, so isolate Ef symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Ef:
Step 3 — List the givens: matrix modulus (Em) = 1.7000 Msi, fiber volume fraction (Vf) = 0.4800, composite modulus (Ec) = 15.4400 Msi.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Ef = 30.3250 Msi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 60.6500 — kept a factor of two that cancels in the correct rearrangement.
- 15.1625 — dropped that same factor in the other direction.
- 33.3575 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials
An engineer designs a composite material laminate for a given target modulus. Given fiber modulus (Ef) = 15.5000 Msi; matrix modulus (Em) = 1.7500 Msi; fiber volume fraction (Vf) = 0.6000, determine the composite modulus (Ec) in Msi.
Given
Find
composite modulus (Ec), in Msi
Start with the thinking
- The governing relation printed in this handbook section is Composite materials — rule of mixtures modulus.
- Everything except Ec is given, so isolate Ec symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Composite materials follow the rule of mixtures, combining fiber and matrix moduli by volume fraction.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange symbolically for Ec:
Step 3 — List the givens: fiber modulus (Ef) = 15.5000 Msi, matrix modulus (Em) = 1.7500 Msi, fiber volume fraction (Vf) = 0.6000.
Step 4 — Substitute the given values:
Step 5 — Evaluate:
Step 6 — Check: returning Ec = 10.0000 Msi to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 20.0000 — kept a factor of two that cancels in the correct rearrangement.
- 5.0000 — dropped that same factor in the other direction.
- 11.0000 — rounded an intermediate value before the final step.
Reference: FE Handbook — Composite Materials