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Hydraulic Jump

Hydraulics · FE Reference Handbook section

Hydraulics
4 formulas
10 exam-style examples
~53 min
All Hydraulics lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Critical depth and flow regime

The same 3.0 m channel carries 7.32 m³/s. Find the critical depth and state whether the 1.2 m normal depth is subcritical or supercritical.

Given

  • q=Q/b=7.32/3.0=2.44m2/sq = Q/b = 7.32/3.0 = 2.44 m^{2}/s
  • g=9.81m/s2g = 9.81 m/s^{2}
  • yn=1.2my_n = 1.2 m

Find

y_c and the regime

Start with the thinking

  • For a rectangle y_c = (q²/g)^{1/3}.
  • y_n > y_c means subcritical, mild slope.

Step-by-step solution

  1. Unit discharge

    q=2.44m2/sq = 2.44 m^{2}/s
  2. Ratio

    q2/g=5.95/9.81=0.607q^{2}/g = 5.95/9.81 = 0.607
  3. Critical depth

    yc=0.6071/3=0.847my_c = 0.607^{1/3} = 0.847 m
  4. Compare

    yn=1.2m>yc=0.847my_n = 1.2 m > y_c = 0.847 m
  5. Conclusion — subcritical flow on a mild slope; control is downstream

Answer:
yc=0.847m;flowissubcriticaly_c = 0.847 m; flow is subcritical

Why the other options are there

  • y_c = 0.607 m (cube root omitted)
  • Supercritical (comparison reversed)

Reference: FE Reference Handbook — Hydraulics — Critical flow

Example 2
Froude number — solve for Froude number — Hydraulic Jump

A hydraulics problem uses Froude number. Given velocity (V) = 6.7000 ft/s; flow depth (y) = 1.0000 ft, determine the Froude number (Fr).

Given

  • velocity(V)=6.7000ft/svelocity (V) = 6.7000 ft/s
  • flowdepth(y)=1.0000ftflow depth (y) = 1.0000 ft

Find

Froude number (Fr)

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except Fr is given, so isolate Fr symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that Fr stands alone on the left-hand side.

  3. Step 3

    Listthegivens:velocity(V)=6.7000ft/s,flowdepth(y)=1.0000ftList the givens: velocity (V) = 6.7000 ft/s, flow depth (y) = 1.0000 ft
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Fr=1.1807Fr = 1.1807
  6. Step 6 — Check: returning Fr = 1.1807 to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Fr=1.1807Fr = 1.1807

Why the other options are there

  • 2.3614 — kept a factor of two that cancels in the correct rearrangement.
  • 0.5904 — dropped that same factor in the other direction.
  • 1.2988 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 3
Froude number — solve for velocity — Hydraulic Jump (2)

A hydraulics problem uses Froude number. Given flow depth (y) = 1.8000 ft; Froude number (Fr) = 2.0900, determine the velocity (V) in ft/s.

Given

  • flowdepth(y)=1.8000ftflow depth (y) = 1.8000 ft
  • Froudenumber(Fr)=2.0900Froude number (Fr) = 2.0900

Find

velocity (V), in ft/s

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except V is given, so isolate V symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that V stands alone on the left-hand side.

  3. Step 3

    Listthegivens:flowdepth(y)=1.8000ft,Froudenumber(Fr)=2.0900List the givens: flow depth (y) = 1.8000 ft, Froude number (Fr) = 2.0900
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    V=15.9115 ft/sV = 15.9115\ \text{ft/s}
  6. Step 6 — Check: returning V = 15.9115 ft/s to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
V=15.9115 ft/sV = 15.9115\ \text{ft/s}

Why the other options are there

  • 31.8230 — kept a factor of two that cancels in the correct rearrangement.
  • 7.9557 — dropped that same factor in the other direction.
  • 17.5026 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 4
Froude number — solve for flow depth — Hydraulic Jump (3)

A hydraulics problem uses Froude number. Given velocity (V) = 13.7000 ft/s; Froude number (Fr) = 0.2700, determine the flow depth (y) in ft.

Given

  • velocity(V)=13.7000ft/svelocity (V) = 13.7000 ft/s
  • Froudenumber(Fr)=0.2700Froude number (Fr) = 0.2700

Find

flow depth (y), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:velocity(V)=13.7000ft/s,Froudenumber(Fr)=0.2700List the givens: velocity (V) = 13.7000 ft/s, Froude number (Fr) = 0.2700
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=79.9572 fty = 79.9572\ \text{ft}
  6. Step 6 — Check: returning y = 79.9572 ft to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=79.9572 fty = 79.9572\ \text{ft}

Why the other options are there

  • 159.9 — kept a factor of two that cancels in the correct rearrangement.
  • 39.9786 — dropped that same factor in the other direction.
  • 87.9530 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 5
Froude number — solve for Froude number (case 2) — Hydraulic Jump (4)

A hydraulics problem uses Froude number. Given velocity (V) = 6.6000 ft/s; flow depth (y) = 2.2000 ft, determine the Froude number (Fr).

Given

  • velocity(V)=6.6000ft/svelocity (V) = 6.6000 ft/s
  • flowdepth(y)=2.2000ftflow depth (y) = 2.2000 ft

Find

Froude number (Fr)

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except Fr is given, so isolate Fr symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that Fr stands alone on the left-hand side.

  3. Step 3

    Listthegivens:velocity(V)=6.6000ft/s,flowdepth(y)=2.2000ftList the givens: velocity (V) = 6.6000 ft/s, flow depth (y) = 2.2000 ft
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Fr=0.7842Fr = 0.7842
  6. Step 6 — Check: returning Fr = 0.7842 to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Fr=0.7842Fr = 0.7842

Why the other options are there

  • 1.5683 — kept a factor of two that cancels in the correct rearrangement.
  • 0.3921 — dropped that same factor in the other direction.
  • 0.8626 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 6
Froude number — solve for velocity (case 2) — Hydraulic Jump (5)

A hydraulics problem uses Froude number. Given flow depth (y) = 3.4000 ft; Froude number (Fr) = 1.8600, determine the velocity (V) in ft/s.

Given

  • flowdepth(y)=3.4000ftflow depth (y) = 3.4000 ft
  • Froudenumber(Fr)=1.8600Froude number (Fr) = 1.8600

Find

velocity (V), in ft/s

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except V is given, so isolate V symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that V stands alone on the left-hand side.

  3. Step 3

    Listthegivens:flowdepth(y)=3.4000ft,Froudenumber(Fr)=1.8600List the givens: flow depth (y) = 3.4000 ft, Froude number (Fr) = 1.8600
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    V=19.4617 ft/sV = 19.4617\ \text{ft/s}
  6. Step 6 — Check: returning V = 19.4617 ft/s to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
V=19.4617 ft/sV = 19.4617\ \text{ft/s}

Why the other options are there

  • 38.9234 — kept a factor of two that cancels in the correct rearrangement.
  • 9.7308 — dropped that same factor in the other direction.
  • 21.4078 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 7
Froude number — solve for flow depth (case 2) — Hydraulic Jump (6)

A hydraulics problem uses Froude number. Given velocity (V) = 9.6000 ft/s; Froude number (Fr) = 1.1700, determine the flow depth (y) in ft.

Given

  • velocity(V)=9.6000ft/svelocity (V) = 9.6000 ft/s
  • Froudenumber(Fr)=1.1700Froude number (Fr) = 1.1700

Find

flow depth (y), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:velocity(V)=9.6000ft/s,Froudenumber(Fr)=1.1700List the givens: velocity (V) = 9.6000 ft/s, Froude number (Fr) = 1.1700
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=2.0908 fty = 2.0908\ \text{ft}
  6. Step 6 — Check: returning y = 2.0908 ft to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=2.0908 fty = 2.0908\ \text{ft}

Why the other options are there

  • 4.1816 — kept a factor of two that cancels in the correct rearrangement.
  • 1.0454 — dropped that same factor in the other direction.
  • 2.2999 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 8
Froude number — solve for Froude number (case 3) — Hydraulic Jump (7)

A hydraulics problem uses Froude number. Given velocity (V) = 7.8000 ft/s; flow depth (y) = 1.4000 ft, determine the Froude number (Fr).

Given

  • velocity(V)=7.8000ft/svelocity (V) = 7.8000 ft/s
  • flowdepth(y)=1.4000ftflow depth (y) = 1.4000 ft

Find

Froude number (Fr)

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except Fr is given, so isolate Fr symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that Fr stands alone on the left-hand side.

  3. Step 3

    Listthegivens:velocity(V)=7.8000ft/s,flowdepth(y)=1.4000ftList the givens: velocity (V) = 7.8000 ft/s, flow depth (y) = 1.4000 ft
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Fr=1.1617Fr = 1.1617
  6. Step 6 — Check: returning Fr = 1.1617 to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Fr=1.1617Fr = 1.1617

Why the other options are there

  • 2.3234 — kept a factor of two that cancels in the correct rearrangement.
  • 0.5809 — dropped that same factor in the other direction.
  • 1.2779 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 9
Froude number — solve for velocity (case 3) — Hydraulic Jump (8)

A hydraulics problem uses Froude number. Given flow depth (y) = 5.3000 ft; Froude number (Fr) = 2.9600, determine the velocity (V) in ft/s.

Given

  • flowdepth(y)=5.3000ftflow depth (y) = 5.3000 ft
  • Froudenumber(Fr)=2.9600Froude number (Fr) = 2.9600

Find

velocity (V), in ft/s

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except V is given, so isolate V symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that V stands alone on the left-hand side.

  3. Step 3

    Listthegivens:flowdepth(y)=5.3000ft,Froudenumber(Fr)=2.9600List the givens: flow depth (y) = 5.3000 ft, Froude number (Fr) = 2.9600
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    V=38.6685 ft/sV = 38.6685\ \text{ft/s}
  6. Step 6 — Check: returning V = 38.6685 ft/s to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
V=38.6685 ft/sV = 38.6685\ \text{ft/s}

Why the other options are there

  • 77.3370 — kept a factor of two that cancels in the correct rearrangement.
  • 19.3343 — dropped that same factor in the other direction.
  • 42.5354 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

Example 10
Froude number — solve for flow depth (case 3) — Hydraulic Jump (9)

A hydraulics problem uses Froude number. Given velocity (V) = 11.4000 ft/s; Froude number (Fr) = 1.7800, determine the flow depth (y) in ft.

Given

  • velocity(V)=11.4000ft/svelocity (V) = 11.4000 ft/s
  • Froudenumber(Fr)=1.7800Froude number (Fr) = 1.7800

Find

flow depth (y), in ft

Start with the thinking

  • The governing relation printed in this handbook section is Froude number.
  • Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Hydraulics items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Fr=V/gyF_r = V / \sqrt{g y}
  2. Step 2 — Rearrange the relation so that y stands alone on the left-hand side.

  3. Step 3

    Listthegivens:velocity(V)=11.4000ft/s,Froudenumber(Fr)=1.7800List the givens: velocity (V) = 11.4000 ft/s, Froude number (Fr) = 1.7800
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    y=1.2738 fty = 1.2738\ \text{ft}
  6. Step 6 — Check: returning y = 1.2738 ft to

    Fr=V/gyF_r = V / \sqrt{g y}

    reproduces the given quantities, and both sides carry the same units.

Answer:
y=1.2738 fty = 1.2738\ \text{ft}

Why the other options are there

  • 2.5477 — kept a factor of two that cancels in the correct rearrangement.
  • 0.6369 — dropped that same factor in the other direction.
  • 1.4012 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump

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