Hydraulic Jump
Hydraulics · FE Reference Handbook section
Core formulas for this FE topic
Definitions, applicability, units, assumptions and worked examples for each relation.
Worked exam-style examples
The four ways this section is written on the real exam — thoughts first, then equations, then substitution.
The same 3.0 m channel carries 7.32 m³/s. Find the critical depth and state whether the 1.2 m normal depth is subcritical or supercritical.
Given
Find
y_c and the regime
Start with the thinking
- For a rectangle y_c = (q²/g)^{1/3}.
- y_n > y_c means subcritical, mild slope.
Step-by-step solution
Unit discharge
Ratio
Critical depth
Compare
Conclusion — subcritical flow on a mild slope; control is downstream
Why the other options are there
- y_c = 0.607 m (cube root omitted)
- Supercritical (comparison reversed)
Reference: FE Reference Handbook — Hydraulics — Critical flow
A hydraulics problem uses Froude number. Given velocity (V) = 6.7000 ft/s; flow depth (y) = 1.0000 ft, determine the Froude number (Fr).
Given
Find
Froude number (Fr)
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except Fr is given, so isolate Fr symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that Fr stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning Fr = 1.1807 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 2.3614 — kept a factor of two that cancels in the correct rearrangement.
- 0.5904 — dropped that same factor in the other direction.
- 1.2988 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given flow depth (y) = 1.8000 ft; Froude number (Fr) = 2.0900, determine the velocity (V) in ft/s.
Given
Find
velocity (V), in ft/s
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except V is given, so isolate V symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that V stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning V = 15.9115 ft/s to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 31.8230 — kept a factor of two that cancels in the correct rearrangement.
- 7.9557 — dropped that same factor in the other direction.
- 17.5026 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given velocity (V) = 13.7000 ft/s; Froude number (Fr) = 0.2700, determine the flow depth (y) in ft.
Given
Find
flow depth (y), in ft
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that y stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning y = 79.9572 ft to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 159.9 — kept a factor of two that cancels in the correct rearrangement.
- 39.9786 — dropped that same factor in the other direction.
- 87.9530 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given velocity (V) = 6.6000 ft/s; flow depth (y) = 2.2000 ft, determine the Froude number (Fr).
Given
Find
Froude number (Fr)
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except Fr is given, so isolate Fr symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that Fr stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning Fr = 0.7842 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 1.5683 — kept a factor of two that cancels in the correct rearrangement.
- 0.3921 — dropped that same factor in the other direction.
- 0.8626 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given flow depth (y) = 3.4000 ft; Froude number (Fr) = 1.8600, determine the velocity (V) in ft/s.
Given
Find
velocity (V), in ft/s
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except V is given, so isolate V symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that V stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning V = 19.4617 ft/s to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 38.9234 — kept a factor of two that cancels in the correct rearrangement.
- 9.7308 — dropped that same factor in the other direction.
- 21.4078 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given velocity (V) = 9.6000 ft/s; Froude number (Fr) = 1.1700, determine the flow depth (y) in ft.
Given
Find
flow depth (y), in ft
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that y stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning y = 2.0908 ft to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 4.1816 — kept a factor of two that cancels in the correct rearrangement.
- 1.0454 — dropped that same factor in the other direction.
- 2.2999 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given velocity (V) = 7.8000 ft/s; flow depth (y) = 1.4000 ft, determine the Froude number (Fr).
Given
Find
Froude number (Fr)
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except Fr is given, so isolate Fr symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that Fr stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning Fr = 1.1617 to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 2.3234 — kept a factor of two that cancels in the correct rearrangement.
- 0.5809 — dropped that same factor in the other direction.
- 1.2779 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given flow depth (y) = 5.3000 ft; Froude number (Fr) = 2.9600, determine the velocity (V) in ft/s.
Given
Find
velocity (V), in ft/s
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except V is given, so isolate V symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that V stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning V = 38.6685 ft/s to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 77.3370 — kept a factor of two that cancels in the correct rearrangement.
- 19.3343 — dropped that same factor in the other direction.
- 42.5354 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump
A hydraulics problem uses Froude number. Given velocity (V) = 11.4000 ft/s; Froude number (Fr) = 1.7800, determine the flow depth (y) in ft.
Given
Find
flow depth (y), in ft
Start with the thinking
- The governing relation printed in this handbook section is Froude number.
- Everything except y is given, so isolate y symbolically first — never rearrange after the numbers are in.
- Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
- Hydraulics items reward recognising the unknown before touching a calculator.
Step-by-step solution
Step 1 — State the governing relation:
Step 2 — Rearrange the relation so that y stands alone on the left-hand side.
Step 3
Step 4 — Substitute the given values into the rearranged relation.
Step 5 — Evaluate:
Step 6 — Check: returning y = 1.2738 ft to
reproduces the given quantities, and both sides carry the same units.
Why the other options are there
- 2.5477 — kept a factor of two that cancels in the correct rearrangement.
- 0.6369 — dropped that same factor in the other direction.
- 1.4012 — rounded an intermediate value before the final step.
Reference: FE Reference Handbook — Hydraulics → Hydraulic Jump