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Void ratio

Geotechnical · FE Reference Handbook section

Geotechnical
1 formulas
10 exam-style examples
~47 min
All Geotechnical lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Soil phase relationships from field data

A sample has moist unit weight 19.2 kN/m³, water content 16% and Gs = 2.68. Find the dry unit weight, void ratio and degree of saturation.

Given

  • γ=19.2kN/m3\gamma = 19.2 kN/m^{3}
  • w=0.16w = 0.16
  • Gs=2.68Gs = 2.68
  • γw = 9.81 kN/m³

Find

γ_d, e, S

Start with the thinking

  • Dry unit weight first — everything else follows.
  • Se = wGs closes the saturation calculation.
Moist sand, γ = 19.2 kN/m³Saturated sandWT

Figure 1 — schematic for Soil phase relationships from field data

Step-by-step solution

  1. Dry unit weight

    γd=γ/(1+w)=19.2/1.16=16.55kN/m3\gamma_d = \gamma/(1 + w) = 19.2/1.16 = 16.55 kN/m^{3}
  2. Void ratio — e = Gsγw/γ_d − 1 = 2.68(9.81)/16.55 − 1

  3. Evaluate

    e=26.29/16.55−1=1.589−1=0.589e = 26.29/16.55 - 1 = 1.589 - 1 = 0.589
  4. Saturation

    S=wGs/e=0.16(2.68)/0.589S = wGs/e = 0.16(2.68)/0.589
  5. Result

    γd=16.6kN/m3,e=0.589,S=0.728(72.8\gamma_d = 16.6 kN/m^{3}, e = 0.589, S = 0.728 (72.8%)
Answer:
γd=16.6kN/m3,e=0.589,S=72.8\gamma_d = 16.6 kN/m^{3}, e = 0.589, S = 72.8%

Why the other options are there

  • γ_d = 22.3 kN/m³ (multiplied by 1 + w)
  • S = 100% (assumed saturated)

Reference: FE Reference Handbook — Geotechnical — Phase relationships

Example 2
Void ratio–porosity relation — solve for void ratio — Void ratio

A geotechnical problem uses Void ratio–porosity relation. Given porosity (n) = 0.3500, determine the void ratio (e).

Given

  • porosity(n)=0.3500porosity (n) = 0.3500

Find

void ratio (e)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except e is given, so isolate e symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that e stands alone on the left-hand side.

  3. Step 3

    Listthegivens:porosity(n)=0.3500List the givens: porosity (n) = 0.3500
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    e=0.5385e = 0.5385
  6. Step 6 — Check: returning e = 0.5385 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
e=0.5385e = 0.5385

Why the other options are there

  • 1.0769 — kept a factor of two that cancels in the correct rearrangement.
  • 0.2692 — dropped that same factor in the other direction.
  • 0.5923 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 3
Void ratio–porosity relation — solve for porosity — Void ratio (2)

A geotechnical problem uses Void ratio–porosity relation. Given void ratio (e) = 0.6400, determine the porosity (n).

Given

  • voidratio(e)=0.6400void ratio (e) = 0.6400

Find

porosity (n)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that n stands alone on the left-hand side.

  3. Step 3

    Listthegivens:voidratio(e)=0.6400List the givens: void ratio (e) = 0.6400
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    n=0.3902n = 0.3902
  6. Step 6 — Check: returning n = 0.3902 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=0.3902n = 0.3902

Why the other options are there

  • 0.7805 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1951 — dropped that same factor in the other direction.
  • 0.4293 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 4
Void ratio–porosity relation — solve for void ratio (case 2) — Void ratio (3)

A geotechnical problem uses Void ratio–porosity relation. Given porosity (n) = 0.4600, determine the void ratio (e).

Given

  • porosity(n)=0.4600porosity (n) = 0.4600

Find

void ratio (e)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except e is given, so isolate e symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that e stands alone on the left-hand side.

  3. Step 3

    Listthegivens:porosity(n)=0.4600List the givens: porosity (n) = 0.4600
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    e=0.8519e = 0.8519
  6. Step 6 — Check: returning e = 0.8519 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
e=0.8519e = 0.8519

Why the other options are there

  • 1.7037 — kept a factor of two that cancels in the correct rearrangement.
  • 0.4259 — dropped that same factor in the other direction.
  • 0.9370 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 5
Void ratio–porosity relation — solve for porosity (case 2) — Void ratio (4)

A geotechnical problem uses Void ratio–porosity relation. Given void ratio (e) = 0.6510, determine the porosity (n).

Given

  • voidratio(e)=0.6510void ratio (e) = 0.6510

Find

porosity (n)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that n stands alone on the left-hand side.

  3. Step 3

    Listthegivens:voidratio(e)=0.6510List the givens: void ratio (e) = 0.6510
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    n=0.3943n = 0.3943
  6. Step 6 — Check: returning n = 0.3943 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=0.3943n = 0.3943

Why the other options are there

  • 0.7886 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1972 — dropped that same factor in the other direction.
  • 0.4337 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 6
Void ratio–porosity relation — solve for void ratio (case 3) — Void ratio (5)

A geotechnical problem uses Void ratio–porosity relation. Given porosity (n) = 0.4000, determine the void ratio (e).

Given

  • porosity(n)=0.4000porosity (n) = 0.4000

Find

void ratio (e)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except e is given, so isolate e symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that e stands alone on the left-hand side.

  3. Step 3

    Listthegivens:porosity(n)=0.4000List the givens: porosity (n) = 0.4000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    e=0.6667e = 0.6667
  6. Step 6 — Check: returning e = 0.6667 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
e=0.6667e = 0.6667

Why the other options are there

  • 1.3333 — kept a factor of two that cancels in the correct rearrangement.
  • 0.3333 — dropped that same factor in the other direction.
  • 0.7333 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 7
Void ratio–porosity relation — solve for porosity (case 3) — Void ratio (6)

A geotechnical problem uses Void ratio–porosity relation. Given void ratio (e) = 0.8690, determine the porosity (n).

Given

  • voidratio(e)=0.8690void ratio (e) = 0.8690

Find

porosity (n)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that n stands alone on the left-hand side.

  3. Step 3

    Listthegivens:voidratio(e)=0.8690List the givens: void ratio (e) = 0.8690
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    n=0.4650n = 0.4650
  6. Step 6 — Check: returning n = 0.4650 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=0.4650n = 0.4650

Why the other options are there

  • 0.9299 — kept a factor of two that cancels in the correct rearrangement.
  • 0.2325 — dropped that same factor in the other direction.
  • 0.5114 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 8
Void ratio–porosity relation — solve for void ratio (case 4) — Void ratio (7)

A geotechnical problem uses Void ratio–porosity relation. Given porosity (n) = 0.2000, determine the void ratio (e).

Given

  • porosity(n)=0.2000porosity (n) = 0.2000

Find

void ratio (e)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except e is given, so isolate e symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that e stands alone on the left-hand side.

  3. Step 3

    Listthegivens:porosity(n)=0.2000List the givens: porosity (n) = 0.2000
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    e=0.2500e = 0.2500
  6. Step 6 — Check: returning e = 0.2500 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
e=0.2500e = 0.2500

Why the other options are there

  • 0.5000 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1250 — dropped that same factor in the other direction.
  • 0.2750 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 9
Void ratio–porosity relation — solve for porosity (case 4) — Void ratio (8)

A geotechnical problem uses Void ratio–porosity relation. Given void ratio (e) = 0.3030, determine the porosity (n).

Given

  • voidratio(e)=0.3030void ratio (e) = 0.3030

Find

porosity (n)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that n stands alone on the left-hand side.

  3. Step 3

    Listthegivens:voidratio(e)=0.3030List the givens: void ratio (e) = 0.3030
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    n=0.2325n = 0.2325
  6. Step 6 — Check: returning n = 0.2325 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=0.2325n = 0.2325

Why the other options are there

  • 0.4651 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1163 — dropped that same factor in the other direction.
  • 0.2558 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

Example 10
Void ratio–porosity relation — solve for void ratio (case 5) — Void ratio (9)

A geotechnical problem uses Void ratio–porosity relation. Given porosity (n) = 0.4900, determine the void ratio (e).

Given

  • porosity(n)=0.4900porosity (n) = 0.4900

Find

void ratio (e)

Start with the thinking

  • The governing relation printed in this handbook section is Void ratio–porosity relation.
  • Everything except e is given, so isolate e symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Geotechnical items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    e=n/(1−n)e = n / (1 - n)
  2. Step 2 — Rearrange the relation so that e stands alone on the left-hand side.

  3. Step 3

    Listthegivens:porosity(n)=0.4900List the givens: porosity (n) = 0.4900
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    e=0.9608e = 0.9608
  6. Step 6 — Check: returning e = 0.9608 to

    e=n/(1−n)e = n / (1 - n)

    reproduces the given quantities, and both sides carry the same units.

Answer:
e=0.9608e = 0.9608

Why the other options are there

  • 1.9216 — kept a factor of two that cancels in the correct rearrangement.
  • 0.4804 — dropped that same factor in the other direction.
  • 1.0569 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Geotechnical → Void ratio

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