Skip to content

Euler's Equation

Fluid Mechanics · FE Reference Handbook section

Fluid Mechanics
7 formulas
10 exam-style examples
~59 min
All Fluid Mechanics lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • For unsteady flow due to local acceleration (i.e., temporal acceleration) in the x-direction, the change in pressure between two
  • points in a fluid can be determined by Euler's equation:

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Euler's equation — solve for pressure differential — Euler's Equation

Euler's equation applied along a streamline in an accelerating flow Given fluid density (rho) = 830.0 kg/m^3; velocity (V) = 4.6000 m/s; velocity differential (dV) = -0.1400 m/s; elevation differential (dz) = 0.7500 m; gravity (g) = 9.7600 m/s^2, determine the pressure differential (dp) in Pa.

Given

  • fluiddensity(rho)=830.0kg/m3fluid density (rho) = 830.0 kg/m^3
  • velocity(V)=4.6000m/svelocity (V) = 4.6000 m/s
  • velocitydifferential(dV)=−0.1400m/svelocity differential (dV) = -0.1400 m/s
  • elevationdifferential(dz)=0.7500melevation differential (dz) = 0.7500 m
  • gravity(g)=9.7600m/s2gravity (g) = 9.7600 m/s^2

Find

pressure differential (dp), in Pa

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dp is given, so isolate dp symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dp stands alone on the left-hand side.

  3. Step 3 — List the givens: fluid density (rho) = 830.0 kg/m^3, velocity (V) = 4.6000 m/s, velocity differential (dV) = -0.1400 m/s, elevation differential (dz) = 0.7500 m, gravity (g) = 9.7600 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dp=−5541 Padp = -5541\ \text{Pa}
  6. Step 6 — Check: returning dp = -5,541 Pa to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dp=−5541 Padp = -5541\ \text{Pa}

Why the other options are there

  • -11,082 — kept a factor of two that cancels in the correct rearrangement.
  • -2,771 — dropped that same factor in the other direction.
  • -6,095 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 2
Euler's equation — solve for velocity differential — Euler's Equation (2)

Euler's equation for a fluid particle in a converging nozzle Given pressure differential (dp) = 840.0 Pa; fluid density (rho) = 870.0 kg/m^3; velocity (V) = 3.9000 m/s; elevation differential (dz) = -0.5000 m; gravity (g) = 9.8900 m/s^2, determine the velocity differential (dV) in m/s.

Given

  • pressuredifferential(dp)=840.0Papressure differential (dp) = 840.0 Pa
  • fluiddensity(rho)=870.0kg/m3fluid density (rho) = 870.0 kg/m^3
  • velocity(V)=3.9000m/svelocity (V) = 3.9000 m/s
  • elevationdifferential(dz)=−0.5000melevation differential (dz) = -0.5000 m
  • gravity(g)=9.8900m/s2gravity (g) = 9.8900 m/s^2

Find

velocity differential (dV), in m/s

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dV is given, so isolate dV symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dV stands alone on the left-hand side.

  3. Step 3 — List the givens: pressure differential (dp) = 840.0 Pa, fluid density (rho) = 870.0 kg/m^3, velocity (V) = 3.9000 m/s, elevation differential (dz) = -0.5000 m, gravity (g) = 9.8900 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dV=1.0204 m/sdV = 1.0204\ \text{m/s}
  6. Step 6 — Check: returning dV = 1.0204 m/s to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dV=1.0204 m/sdV = 1.0204\ \text{m/s}

Why the other options are there

  • 2.0408 — kept a factor of two that cancels in the correct rearrangement.
  • 0.5102 — dropped that same factor in the other direction.
  • 1.1224 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 3
Euler's equation — solve for elevation differential — Euler's Equation (3)

Euler's equation used to derive pressure change along a pipeline Given pressure differential (dp) = -4,250 Pa; fluid density (rho) = 1,040 kg/m^3; velocity (V) = 1.8000 m/s; velocity differential (dV) = -0.3200 m/s; gravity (g) = 9.8800 m/s^2, determine the elevation differential (dz) in m.

Given

  • pressuredifferential(dp)=−4,250Papressure differential (dp) = -4,250 Pa
  • fluiddensity(rho)=1,040kg/m3fluid density (rho) = 1,040 kg/m^3
  • velocity(V)=1.8000m/svelocity (V) = 1.8000 m/s
  • velocitydifferential(dV)=−0.3200m/svelocity differential (dV) = -0.3200 m/s
  • gravity(g)=9.8800m/s2gravity (g) = 9.8800 m/s^2

Find

elevation differential (dz), in m

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dz is given, so isolate dz symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dz stands alone on the left-hand side.

  3. Step 3 — List the givens: pressure differential (dp) = -4,250 Pa, fluid density (rho) = 1,040 kg/m^3, velocity (V) = 1.8000 m/s, velocity differential (dV) = -0.3200 m/s, gravity (g) = 9.8800 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dz=0.4719 mdz = 0.4719\ \text{m}
  6. Step 6 — Check: returning dz = 0.4719 m to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dz=0.4719 mdz = 0.4719\ \text{m}

Why the other options are there

  • 0.9438 — kept a factor of two that cancels in the correct rearrangement.
  • 0.2360 — dropped that same factor in the other direction.
  • 0.5191 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 4
Euler's equation — solve for pressure differential (case 2) — Euler's Equation (4)

Euler's equation applied along a streamline in an accelerating flow Given fluid density (rho) = 840.0 kg/m^3; velocity (V) = 2.1000 m/s; velocity differential (dV) = 0.1600 m/s; elevation differential (dz) = -0.0500 m; gravity (g) = 9.8500 m/s^2, determine the pressure differential (dp) in Pa.

Given

  • fluiddensity(rho)=840.0kg/m3fluid density (rho) = 840.0 kg/m^3
  • velocity(V)=2.1000m/svelocity (V) = 2.1000 m/s
  • velocitydifferential(dV)=0.1600m/svelocity differential (dV) = 0.1600 m/s
  • elevationdifferential(dz)=−0.0500melevation differential (dz) = -0.0500 m
  • gravity(g)=9.8500m/s2gravity (g) = 9.8500 m/s^2

Find

pressure differential (dp), in Pa

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dp is given, so isolate dp symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dp stands alone on the left-hand side.

  3. Step 3 — List the givens: fluid density (rho) = 840.0 kg/m^3, velocity (V) = 2.1000 m/s, velocity differential (dV) = 0.1600 m/s, elevation differential (dz) = -0.0500 m, gravity (g) = 9.8500 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dp=131.5 Padp = 131.5\ \text{Pa}
  6. Step 6 — Check: returning dp = 131.5 Pa to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dp=131.5 Padp = 131.5\ \text{Pa}

Why the other options are there

  • 262.9 — kept a factor of two that cancels in the correct rearrangement.
  • 65.7300 — dropped that same factor in the other direction.
  • 144.6 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 5
Euler's equation — solve for velocity differential (case 2) — Euler's Equation (5)

Euler's equation for a fluid particle in a converging nozzle Given pressure differential (dp) = -2,700 Pa; fluid density (rho) = 990.0 kg/m^3; velocity (V) = 2.8000 m/s; elevation differential (dz) = -0.2500 m; gravity (g) = 9.8100 m/s^2, determine the velocity differential (dV) in m/s.

Given

  • pressuredifferential(dp)=−2,700Papressure differential (dp) = -2,700 Pa
  • fluiddensity(rho)=990.0kg/m3fluid density (rho) = 990.0 kg/m^3
  • velocity(V)=2.8000m/svelocity (V) = 2.8000 m/s
  • elevationdifferential(dz)=−0.2500melevation differential (dz) = -0.2500 m
  • gravity(g)=9.8100m/s2gravity (g) = 9.8100 m/s^2

Find

velocity differential (dV), in m/s

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dV is given, so isolate dV symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dV stands alone on the left-hand side.

  3. Step 3 — List the givens: pressure differential (dp) = -2,700 Pa, fluid density (rho) = 990.0 kg/m^3, velocity (V) = 2.8000 m/s, elevation differential (dz) = -0.2500 m, gravity (g) = 9.8100 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dV=1.8499 m/sdV = 1.8499\ \text{m/s}
  6. Step 6 — Check: returning dV = 1.8499 m/s to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dV=1.8499 m/sdV = 1.8499\ \text{m/s}

Why the other options are there

  • 3.6998 — kept a factor of two that cancels in the correct rearrangement.
  • 0.9250 — dropped that same factor in the other direction.
  • 2.0349 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 6
Euler's equation — solve for elevation differential (case 2) — Euler's Equation (6)

Euler's equation used to derive pressure change along a pipeline Given pressure differential (dp) = 1,340 Pa; fluid density (rho) = 860.0 kg/m^3; velocity (V) = 4.3000 m/s; velocity differential (dV) = 0.3000 m/s; gravity (g) = 9.7800 m/s^2, determine the elevation differential (dz) in m.

Given

  • pressuredifferential(dp)=1,340Papressure differential (dp) = 1,340 Pa
  • fluiddensity(rho)=860.0kg/m3fluid density (rho) = 860.0 kg/m^3
  • velocity(V)=4.3000m/svelocity (V) = 4.3000 m/s
  • velocitydifferential(dV)=0.3000m/svelocity differential (dV) = 0.3000 m/s
  • gravity(g)=9.7800m/s2gravity (g) = 9.7800 m/s^2

Find

elevation differential (dz), in m

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dz is given, so isolate dz symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dz stands alone on the left-hand side.

  3. Step 3 — List the givens: pressure differential (dp) = 1,340 Pa, fluid density (rho) = 860.0 kg/m^3, velocity (V) = 4.3000 m/s, velocity differential (dV) = 0.3000 m/s, gravity (g) = 9.7800 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dz=−0.2912 mdz = -0.2912\ \text{m}
  6. Step 6 — Check: returning dz = -0.2912 m to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dz=−0.2912 mdz = -0.2912\ \text{m}

Why the other options are there

  • -0.5824 — kept a factor of two that cancels in the correct rearrangement.
  • -0.1456 — dropped that same factor in the other direction.
  • -0.3203 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 7
Euler's equation — solve for pressure differential (case 3) — Euler's Equation (7)

Euler's equation applied along a streamline in an accelerating flow Given fluid density (rho) = 1,020 kg/m^3; velocity (V) = 3.2000 m/s; velocity differential (dV) = 0.3900 m/s; elevation differential (dz) = 1.7500 m; gravity (g) = 9.7800 m/s^2, determine the pressure differential (dp) in Pa.

Given

  • fluiddensity(rho)=1,020kg/m3fluid density (rho) = 1,020 kg/m^3
  • velocity(V)=3.2000m/svelocity (V) = 3.2000 m/s
  • velocitydifferential(dV)=0.3900m/svelocity differential (dV) = 0.3900 m/s
  • elevationdifferential(dz)=1.7500melevation differential (dz) = 1.7500 m
  • gravity(g)=9.7800m/s2gravity (g) = 9.7800 m/s^2

Find

pressure differential (dp), in Pa

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dp is given, so isolate dp symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dp stands alone on the left-hand side.

  3. Step 3 — List the givens: fluid density (rho) = 1,020 kg/m^3, velocity (V) = 3.2000 m/s, velocity differential (dV) = 0.3900 m/s, elevation differential (dz) = 1.7500 m, gravity (g) = 9.7800 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dp=−18730 Padp = -18730\ \text{Pa}
  6. Step 6 — Check: returning dp = -18,730 Pa to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dp=−18730 Padp = -18730\ \text{Pa}

Why the other options are there

  • -37,461 — kept a factor of two that cancels in the correct rearrangement.
  • -9,365 — dropped that same factor in the other direction.
  • -20,603 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 8
Euler's equation — solve for velocity differential (case 3) — Euler's Equation (8)

Euler's equation for a fluid particle in a converging nozzle Given pressure differential (dp) = 270.0 Pa; fluid density (rho) = 1,050 kg/m^3; velocity (V) = 2.2000 m/s; elevation differential (dz) = 0.8000 m; gravity (g) = 9.7200 m/s^2, determine the velocity differential (dV) in m/s.

Given

  • pressuredifferential(dp)=270.0Papressure differential (dp) = 270.0 Pa
  • fluiddensity(rho)=1,050kg/m3fluid density (rho) = 1,050 kg/m^3
  • velocity(V)=2.2000m/svelocity (V) = 2.2000 m/s
  • elevationdifferential(dz)=0.8000melevation differential (dz) = 0.8000 m
  • gravity(g)=9.7200m/s2gravity (g) = 9.7200 m/s^2

Find

velocity differential (dV), in m/s

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dV is given, so isolate dV symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dV stands alone on the left-hand side.

  3. Step 3 — List the givens: pressure differential (dp) = 270.0 Pa, fluid density (rho) = 1,050 kg/m^3, velocity (V) = 2.2000 m/s, elevation differential (dz) = 0.8000 m, gravity (g) = 9.7200 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dV=−3.6514 m/sdV = -3.6514\ \text{m/s}
  6. Step 6 — Check: returning dV = -3.6514 m/s to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dV=−3.6514 m/sdV = -3.6514\ \text{m/s}

Why the other options are there

  • -7.3029 — kept a factor of two that cancels in the correct rearrangement.
  • -1.8257 — dropped that same factor in the other direction.
  • -4.0166 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 9
Euler's equation — solve for elevation differential (case 3) — Euler's Equation (9)

Euler's equation used to derive pressure change along a pipeline Given pressure differential (dp) = 4,610 Pa; fluid density (rho) = 1,200 kg/m^3; velocity (V) = 3.7000 m/s; velocity differential (dV) = -0.1800 m/s; gravity (g) = 9.8200 m/s^2, determine the elevation differential (dz) in m.

Given

  • pressuredifferential(dp)=4,610Papressure differential (dp) = 4,610 Pa
  • fluiddensity(rho)=1,200kg/m3fluid density (rho) = 1,200 kg/m^3
  • velocity(V)=3.7000m/svelocity (V) = 3.7000 m/s
  • velocitydifferential(dV)=−0.1800m/svelocity differential (dV) = -0.1800 m/s
  • gravity(g)=9.8200m/s2gravity (g) = 9.8200 m/s^2

Find

elevation differential (dz), in m

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dz is given, so isolate dz symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dz stands alone on the left-hand side.

  3. Step 3 — List the givens: pressure differential (dp) = 4,610 Pa, fluid density (rho) = 1,200 kg/m^3, velocity (V) = 3.7000 m/s, velocity differential (dV) = -0.1800 m/s, gravity (g) = 9.8200 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dz=−0.3234 mdz = -0.3234\ \text{m}
  6. Step 6 — Check: returning dz = -0.3234 m to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dz=−0.3234 mdz = -0.3234\ \text{m}

Why the other options are there

  • -0.6468 — kept a factor of two that cancels in the correct rearrangement.
  • -0.1617 — dropped that same factor in the other direction.
  • -0.3557 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

Example 10
Euler's equation — solve for pressure differential (case 4) — Euler's Equation (10)

Euler's equation applied along a streamline in an accelerating flow Given fluid density (rho) = 1,060 kg/m^3; velocity (V) = 3.4000 m/s; velocity differential (dV) = -0.0300 m/s; elevation differential (dz) = -0.1000 m; gravity (g) = 9.7700 m/s^2, determine the pressure differential (dp) in Pa.

Given

  • fluiddensity(rho)=1,060kg/m3fluid density (rho) = 1,060 kg/m^3
  • velocity(V)=3.4000m/svelocity (V) = 3.4000 m/s
  • velocitydifferential(dV)=−0.0300m/svelocity differential (dV) = -0.0300 m/s
  • elevationdifferential(dz)=−0.1000melevation differential (dz) = -0.1000 m
  • gravity(g)=9.7700m/s2gravity (g) = 9.7700 m/s^2

Find

pressure differential (dp), in Pa

Start with the thinking

  • The governing relation printed in this handbook section is Euler's equation.
  • Everything except dp is given, so isolate dp symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Euler's equation for inviscid flow along a streamline underlies derivation of the Bernoulli equation.

Step-by-step solution

  1. Step 1 — State the governing relation:

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0
  2. Step 2 — Rearrange the relation so that dp stands alone on the left-hand side.

  3. Step 3 — List the givens: fluid density (rho) = 1,060 kg/m^3, velocity (V) = 3.4000 m/s, velocity differential (dV) = -0.0300 m/s, elevation differential (dz) = -0.1000 m, gravity (g) = 9.7700 m/s^2.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    dp=1144 Padp = 1144\ \text{Pa}
  6. Step 6 — Check: returning dp = 1,144 Pa to

    dpρ+V dV+g dz=0\dfrac{dp}{\rho} + V\,dV + g\,dz = 0

    reproduces the given quantities, and both sides carry the same units.

Answer:
dp=1144 Padp = 1144\ \text{Pa}

Why the other options are there

  • 2,287 — kept a factor of two that cancels in the correct rearrangement.
  • 571.9 — dropped that same factor in the other direction.
  • 1,258 — rounded an intermediate value before the final step.

Reference: FE Handbook — Euler's Equation

© 2026 Dr. Steve Efe. Civil Engineering Capstone Studio. All rights reserved.