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Retardation Factor R

Environmental Engineering · FE Reference Handbook section

Environmental Engineering
12 formulas
10 exam-style examples
~60 min
All Environmental Engineering lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Retardation Factor R — solve for retardation factor — Retardation Factor R

retardation factor of a sorbing contaminant plume in an aquifer Given bulk density (rho_b) = 1.5200 g/cm^3; distribution coefficient (K_d) = 8.5300 cm^3/g; porosity (n) = 0.2400, determine the retardation factor (R).

Given

  • bulkdensity(rhob)=1.5200g/cm3bulk density (rho_b) = 1.5200 g/cm^3
  • distributioncoefficient(Kd)=8.5300cm3/gdistribution coefficient (K_d) = 8.5300 cm^3/g
  • porosity(n)=0.2400porosity (n) = 0.2400

Find

retardation factor (R)

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for R:

    R=1+ρbKdnR = 1+\dfrac{\rho_b K_d}{n}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.5200 g/cm^3, distribution coefficient (K_d) = 8.5300 cm^3/g, porosity (n) = 0.2400.

  4. Step 4 — Substitute the given values:

    R=1+ρbKd0.2400R = 1+\dfrac{\rho_b K_d}{0.2400}
  5. Step 5 — Evaluate:

    R=55.0233R = 55.0233
  6. Step 6 — Check: returning R = 55.0233 to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
R=55.0233R = 55.0233

Why the other options are there

  • 110.0 — kept a factor of two that cancels in the correct rearrangement.
  • 27.5117 — dropped that same factor in the other direction.
  • 60.5257 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 2
Retardation Factor R — solve for distribution coefficient — Retardation Factor R (2)

retardation factor R calculation from bulk density, distribution coefficient, and porosity Given bulk density (rho_b) = 1.7500 g/cm^3; porosity (n) = 0.3700; retardation factor (R) = 15.3000, determine the distribution coefficient (K_d) in cm^3/g.

Given

  • bulkdensity(rhob)=1.7500g/cm3bulk density (rho_b) = 1.7500 g/cm^3
  • porosity(n)=0.3700porosity (n) = 0.3700
  • retardationfactor(R)=15.3000retardation factor (R) = 15.3000

Find

distribution coefficient (K_d), in cm^3/g

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except K_d is given, so isolate K_d symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for K_d:

    Kd=(R−1)nρbK_{d} = \dfrac{(R-1)n}{\rho_b}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.7500 g/cm^3, porosity (n) = 0.3700, retardation factor (R) = 15.3000.

  4. Step 4 — Substitute the given values:

    Kd=(15.3000−1)0.3700ρbK_{d} = \dfrac{(15.3000-1)0.3700}{\rho_b}
  5. Step 5 — Evaluate:

    K_{d} = 3.0234\ \text{cm^3/g}
  6. Step 6 — Check: returning K_d = 3.0234 cm^3/g to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
K_{d} = 3.0234\ \text{cm^3/g}

Why the other options are there

  • 6.0469 — kept a factor of two that cancels in the correct rearrangement.
  • 1.5117 — dropped that same factor in the other direction.
  • 3.3258 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 3
Retardation Factor R — solve for porosity — Retardation Factor R (3)

retardation factor used to estimate contaminant travel time in groundwater Given bulk density (rho_b) = 1.7900 g/cm^3; distribution coefficient (K_d) = 2.5700 cm^3/g; retardation factor (R) = 27.4000, determine the porosity (n).

Given

  • bulkdensity(rhob)=1.7900g/cm3bulk density (rho_b) = 1.7900 g/cm^3
  • distributioncoefficient(Kd)=2.5700cm3/gdistribution coefficient (K_d) = 2.5700 cm^3/g
  • retardationfactor(R)=27.4000retardation factor (R) = 27.4000

Find

porosity (n)

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for n:

    n=ρbKdR−1n = \dfrac{\rho_b K_d}{R-1}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.7900 g/cm^3, distribution coefficient (K_d) = 2.5700 cm^3/g, retardation factor (R) = 27.4000.

  4. Step 4 — Substitute the given values:

    n=ρbKd27.4000−1n = \dfrac{\rho_b K_d}{27.4000-1}
  5. Step 5 — Evaluate:

    n=0.1743n = 0.1743
  6. Step 6 — Check: returning n = 0.1743 to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=0.1743n = 0.1743

Why the other options are there

  • 0.3485 — kept a factor of two that cancels in the correct rearrangement.
  • 0.0871 — dropped that same factor in the other direction.
  • 0.1917 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 4
Retardation Factor R — solve for retardation factor (case 2) — Retardation Factor R (4)

retardation factor of a sorbing contaminant plume in an aquifer Given bulk density (rho_b) = 1.3800 g/cm^3; distribution coefficient (K_d) = 4.5800 cm^3/g; porosity (n) = 0.4000, determine the retardation factor (R).

Given

  • bulkdensity(rhob)=1.3800g/cm3bulk density (rho_b) = 1.3800 g/cm^3
  • distributioncoefficient(Kd)=4.5800cm3/gdistribution coefficient (K_d) = 4.5800 cm^3/g
  • porosity(n)=0.4000porosity (n) = 0.4000

Find

retardation factor (R)

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for R:

    R=1+ρbKdnR = 1+\dfrac{\rho_b K_d}{n}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.3800 g/cm^3, distribution coefficient (K_d) = 4.5800 cm^3/g, porosity (n) = 0.4000.

  4. Step 4 — Substitute the given values:

    R=1+ρbKd0.4000R = 1+\dfrac{\rho_b K_d}{0.4000}
  5. Step 5 — Evaluate:

    R=16.8010R = 16.8010
  6. Step 6 — Check: returning R = 16.8010 to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
R=16.8010R = 16.8010

Why the other options are there

  • 33.6020 — kept a factor of two that cancels in the correct rearrangement.
  • 8.4005 — dropped that same factor in the other direction.
  • 18.4811 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 5
Retardation Factor R — solve for distribution coefficient (case 2) — Retardation Factor R (5)

retardation factor R calculation from bulk density, distribution coefficient, and porosity Given bulk density (rho_b) = 1.8500 g/cm^3; porosity (n) = 0.3800; retardation factor (R) = 12.2000, determine the distribution coefficient (K_d) in cm^3/g.

Given

  • bulkdensity(rhob)=1.8500g/cm3bulk density (rho_b) = 1.8500 g/cm^3
  • porosity(n)=0.3800porosity (n) = 0.3800
  • retardationfactor(R)=12.2000retardation factor (R) = 12.2000

Find

distribution coefficient (K_d), in cm^3/g

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except K_d is given, so isolate K_d symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for K_d:

    Kd=(R−1)nρbK_{d} = \dfrac{(R-1)n}{\rho_b}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.8500 g/cm^3, porosity (n) = 0.3800, retardation factor (R) = 12.2000.

  4. Step 4 — Substitute the given values:

    Kd=(12.2000−1)0.3800ρbK_{d} = \dfrac{(12.2000-1)0.3800}{\rho_b}
  5. Step 5 — Evaluate:

    K_{d} = 2.3005\ \text{cm^3/g}
  6. Step 6 — Check: returning K_d = 2.3005 cm^3/g to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
K_{d} = 2.3005\ \text{cm^3/g}

Why the other options are there

  • 4.6011 — kept a factor of two that cancels in the correct rearrangement.
  • 1.1503 — dropped that same factor in the other direction.
  • 2.5306 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 6
Retardation Factor R — solve for porosity (case 2) — Retardation Factor R (6)

retardation factor used to estimate contaminant travel time in groundwater Given bulk density (rho_b) = 1.6900 g/cm^3; distribution coefficient (K_d) = 2.9500 cm^3/g; retardation factor (R) = 32.2000, determine the porosity (n).

Given

  • bulkdensity(rhob)=1.6900g/cm3bulk density (rho_b) = 1.6900 g/cm^3
  • distributioncoefficient(Kd)=2.9500cm3/gdistribution coefficient (K_d) = 2.9500 cm^3/g
  • retardationfactor(R)=32.2000retardation factor (R) = 32.2000

Find

porosity (n)

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for n:

    n=ρbKdR−1n = \dfrac{\rho_b K_d}{R-1}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.6900 g/cm^3, distribution coefficient (K_d) = 2.9500 cm^3/g, retardation factor (R) = 32.2000.

  4. Step 4 — Substitute the given values:

    n=ρbKd32.2000−1n = \dfrac{\rho_b K_d}{32.2000-1}
  5. Step 5 — Evaluate:

    n=0.1598n = 0.1598
  6. Step 6 — Check: returning n = 0.1598 to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=0.1598n = 0.1598

Why the other options are there

  • 0.3196 — kept a factor of two that cancels in the correct rearrangement.
  • 0.0799 — dropped that same factor in the other direction.
  • 0.1758 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 7
Retardation Factor R — solve for retardation factor (case 3) — Retardation Factor R (7)

retardation factor of a sorbing contaminant plume in an aquifer Given bulk density (rho_b) = 1.7100 g/cm^3; distribution coefficient (K_d) = 6.3700 cm^3/g; porosity (n) = 0.3000, determine the retardation factor (R).

Given

  • bulkdensity(rhob)=1.7100g/cm3bulk density (rho_b) = 1.7100 g/cm^3
  • distributioncoefficient(Kd)=6.3700cm3/gdistribution coefficient (K_d) = 6.3700 cm^3/g
  • porosity(n)=0.3000porosity (n) = 0.3000

Find

retardation factor (R)

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for R:

    R=1+ρbKdnR = 1+\dfrac{\rho_b K_d}{n}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.7100 g/cm^3, distribution coefficient (K_d) = 6.3700 cm^3/g, porosity (n) = 0.3000.

  4. Step 4 — Substitute the given values:

    R=1+ρbKd0.3000R = 1+\dfrac{\rho_b K_d}{0.3000}
  5. Step 5 — Evaluate:

    R=37.3090R = 37.3090
  6. Step 6 — Check: returning R = 37.3090 to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
R=37.3090R = 37.3090

Why the other options are there

  • 74.6180 — kept a factor of two that cancels in the correct rearrangement.
  • 18.6545 — dropped that same factor in the other direction.
  • 41.0399 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 8
Retardation Factor R — solve for distribution coefficient (case 3) — Retardation Factor R (8)

retardation factor R calculation from bulk density, distribution coefficient, and porosity Given bulk density (rho_b) = 1.6900 g/cm^3; porosity (n) = 0.2900; retardation factor (R) = 20.5000, determine the distribution coefficient (K_d) in cm^3/g.

Given

  • bulkdensity(rhob)=1.6900g/cm3bulk density (rho_b) = 1.6900 g/cm^3
  • porosity(n)=0.2900porosity (n) = 0.2900
  • retardationfactor(R)=20.5000retardation factor (R) = 20.5000

Find

distribution coefficient (K_d), in cm^3/g

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except K_d is given, so isolate K_d symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for K_d:

    Kd=(R−1)nρbK_{d} = \dfrac{(R-1)n}{\rho_b}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.6900 g/cm^3, porosity (n) = 0.2900, retardation factor (R) = 20.5000.

  4. Step 4 — Substitute the given values:

    Kd=(20.5000−1)0.2900ρbK_{d} = \dfrac{(20.5000-1)0.2900}{\rho_b}
  5. Step 5 — Evaluate:

    K_{d} = 3.3462\ \text{cm^3/g}
  6. Step 6 — Check: returning K_d = 3.3462 cm^3/g to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
K_{d} = 3.3462\ \text{cm^3/g}

Why the other options are there

  • 6.6923 — kept a factor of two that cancels in the correct rearrangement.
  • 1.6731 — dropped that same factor in the other direction.
  • 3.6808 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 9
Retardation Factor R — solve for porosity (case 3) — Retardation Factor R (9)

retardation factor used to estimate contaminant travel time in groundwater Given bulk density (rho_b) = 1.5700 g/cm^3; distribution coefficient (K_d) = 7.7900 cm^3/g; retardation factor (R) = 2.5000, determine the porosity (n).

Given

  • bulkdensity(rhob)=1.5700g/cm3bulk density (rho_b) = 1.5700 g/cm^3
  • distributioncoefficient(Kd)=7.7900cm3/gdistribution coefficient (K_d) = 7.7900 cm^3/g
  • retardationfactor(R)=2.5000retardation factor (R) = 2.5000

Find

porosity (n)

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except n is given, so isolate n symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for n:

    n=ρbKdR−1n = \dfrac{\rho_b K_d}{R-1}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.5700 g/cm^3, distribution coefficient (K_d) = 7.7900 cm^3/g, retardation factor (R) = 2.5000.

  4. Step 4 — Substitute the given values:

    n=ρbKd2.5000−1n = \dfrac{\rho_b K_d}{2.5000-1}
  5. Step 5 — Evaluate:

    n=8.1535n = 8.1535
  6. Step 6 — Check: returning n = 8.1535 to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
n=8.1535n = 8.1535

Why the other options are there

  • 16.3071 — kept a factor of two that cancels in the correct rearrangement.
  • 4.0768 — dropped that same factor in the other direction.
  • 8.9689 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

Example 10
Retardation Factor R — solve for retardation factor (case 4) — Retardation Factor R (10)

retardation factor of a sorbing contaminant plume in an aquifer Given bulk density (rho_b) = 1.5100 g/cm^3; distribution coefficient (K_d) = 2.7800 cm^3/g; porosity (n) = 0.2100, determine the retardation factor (R).

Given

  • bulkdensity(rhob)=1.5100g/cm3bulk density (rho_b) = 1.5100 g/cm^3
  • distributioncoefficient(Kd)=2.7800cm3/gdistribution coefficient (K_d) = 2.7800 cm^3/g
  • porosity(n)=0.2100porosity (n) = 0.2100

Find

retardation factor (R)

Start with the thinking

  • The governing relation printed in this handbook section is Retardation Factor R.
  • Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • The retardation factor R describes how much slower a sorbing contaminant moves relative to groundwater seepage velocity.

Step-by-step solution

  1. Step 1 — State the governing relation:

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}
  2. Step 2 — Rearrange symbolically for R:

    R=1+ρbKdnR = 1+\dfrac{\rho_b K_d}{n}
  3. Step 3 — List the givens: bulk density (rho_b) = 1.5100 g/cm^3, distribution coefficient (K_d) = 2.7800 cm^3/g, porosity (n) = 0.2100.

  4. Step 4 — Substitute the given values:

    R=1+ρbKd0.2100R = 1+\dfrac{\rho_b K_d}{0.2100}
  5. Step 5 — Evaluate:

    R=20.9895R = 20.9895
  6. Step 6 — Check: returning R = 20.9895 to

    R=1+ρbKdnR = 1 + \dfrac{\rho_b K_d}{n}

    reproduces the given quantities, and both sides carry the same units.

Answer:
R=20.9895R = 20.9895

Why the other options are there

  • 41.9790 — kept a factor of two that cancels in the correct rearrangement.
  • 10.4948 — dropped that same factor in the other direction.
  • 23.0885 — rounded an intermediate value before the final step.

Reference: FE Handbook — Retardation Factor

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