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National Research Council (NRC) Trickling Filter Performance

Environmental Engineering · FE Reference Handbook section

Environmental Engineering
5 formulas
10 exam-style examples
~55 min
All Environmental Engineering lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • For a single-stage or first-stage rock filter, the equation is
  • The recirculation factor is calculated using

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
First-order BOD decay — solve for remaining BOD — National Research Council (NRC) Trickling Filter Performance

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 385.0 mg/L; rate constant (k) = 0.2600 1/day; time (t) = 7.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=385.0mg/Lultimate BOD (L_{0}) = 385.0 mg/L
  • rateconstant(k)=0.26001/dayrate constant (k) = 0.2600 1/day
  • time(t)=7.0000daytime (t) = 7.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=385.0mg/L,rateconstant(k)=0.26001/day,time(t)=7.0000dayList the givens: ultimate BOD (L_{0}) = 385.0 mg/L, rate constant (k) = 0.2600 1/day, time (t) = 7.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=62.3799 mg/LLt = 62.3799\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 62.3799 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=62.3799 mg/LLt = 62.3799\ \text{mg/L}

Why the other options are there

  • 124.8 — kept a factor of two that cancels in the correct rearrangement.
  • 31.1900 — dropped that same factor in the other direction.
  • 68.6179 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 2
First-order BOD decay — solve for ultimate BOD — National Research Council (NRC) Trickling Filter Performance (2)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.2200 1/day; time (t) = 6.0000 day; remaining BOD (Lt) = 191.8 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.22001/dayrate constant (k) = 0.2200 1/day
  • time(t)=6.0000daytime (t) = 6.0000 day
  • remainingBOD(Lt)=191.8mg/Lremaining BOD (Lt) = 191.8 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.22001/day,time(t)=6.0000day,remainingBOD(Lt)=191.8mg/LList the givens: rate constant (k) = 0.2200 1/day, time (t) = 6.0000 day, remaining BOD (Lt) = 191.8 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=718.0 mg/LL_{0} = 718.0\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 718.0 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=718.0 mg/LL_{0} = 718.0\ \text{mg/L}

Why the other options are there

  • 1,436 — kept a factor of two that cancels in the correct rearrangement.
  • 359.0 — dropped that same factor in the other direction.
  • 789.8 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 3
First-order BOD decay — solve for rate constant — National Research Council (NRC) Trickling Filter Performance (3)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 110.0 mg/L; time (t) = 7.5000 day; remaining BOD (Lt) = 397.0 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=110.0mg/Lultimate BOD (L_{0}) = 110.0 mg/L
  • time(t)=7.5000daytime (t) = 7.5000 day
  • remainingBOD(Lt)=397.0mg/Lremaining BOD (Lt) = 397.0 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=110.0mg/L,time(t)=7.5000day,remainingBOD(Lt)=397.0mg/LList the givens: ultimate BOD (L_{0}) = 110.0 mg/L, time (t) = 7.5000 day, remaining BOD (Lt) = 397.0 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−0.1711 1/dayk = -0.1711\ \text{1/day}
  6. Step 6 — Check: returning k = -0.1711 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−0.1711 1/dayk = -0.1711\ \text{1/day}

Why the other options are there

  • -0.3423 — kept a factor of two that cancels in the correct rearrangement.
  • -0.0856 — dropped that same factor in the other direction.
  • -0.1882 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 4
First-order BOD decay — solve for remaining BOD (case 2) — National Research Council (NRC) Trickling Filter Performance (4)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 395.0 mg/L; rate constant (k) = 0.2200 1/day; time (t) = 9.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=395.0mg/Lultimate BOD (L_{0}) = 395.0 mg/L
  • rateconstant(k)=0.22001/dayrate constant (k) = 0.2200 1/day
  • time(t)=9.0000daytime (t) = 9.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=395.0mg/L,rateconstant(k)=0.22001/day,time(t)=9.0000dayList the givens: ultimate BOD (L_{0}) = 395.0 mg/L, rate constant (k) = 0.2200 1/day, time (t) = 9.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=54.5373 mg/LLt = 54.5373\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 54.5373 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=54.5373 mg/LLt = 54.5373\ \text{mg/L}

Why the other options are there

  • 109.1 — kept a factor of two that cancels in the correct rearrangement.
  • 27.2687 — dropped that same factor in the other direction.
  • 59.9911 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 5
First-order BOD decay — solve for ultimate BOD (case 2) — National Research Council (NRC) Trickling Filter Performance (5)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.0900 1/day; time (t) = 5.0000 day; remaining BOD (Lt) = 375.3 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.09001/dayrate constant (k) = 0.0900 1/day
  • time(t)=5.0000daytime (t) = 5.0000 day
  • remainingBOD(Lt)=375.3mg/Lremaining BOD (Lt) = 375.3 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.09001/day,time(t)=5.0000day,remainingBOD(Lt)=375.3mg/LList the givens: rate constant (k) = 0.0900 1/day, time (t) = 5.0000 day, remaining BOD (Lt) = 375.3 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=588.6 mg/LL_{0} = 588.6\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 588.6 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=588.6 mg/LL_{0} = 588.6\ \text{mg/L}

Why the other options are there

  • 1,177 — kept a factor of two that cancels in the correct rearrangement.
  • 294.3 — dropped that same factor in the other direction.
  • 647.4 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 6
First-order BOD decay — solve for rate constant (case 2) — National Research Council (NRC) Trickling Filter Performance (6)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 310.0 mg/L; time (t) = 7.0000 day; remaining BOD (Lt) = 51.2000 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=310.0mg/Lultimate BOD (L_{0}) = 310.0 mg/L
  • time(t)=7.0000daytime (t) = 7.0000 day
  • remainingBOD(Lt)=51.2000mg/Lremaining BOD (Lt) = 51.2000 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=310.0mg/L,time(t)=7.0000day,remainingBOD(Lt)=51.2000mg/LList the givens: ultimate BOD (L_{0}) = 310.0 mg/L, time (t) = 7.0000 day, remaining BOD (Lt) = 51.2000 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=0.2573 1/dayk = 0.2573\ \text{1/day}
  6. Step 6 — Check: returning k = 0.2573 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.2573 1/dayk = 0.2573\ \text{1/day}

Why the other options are there

  • 0.5145 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1286 — dropped that same factor in the other direction.
  • 0.2830 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 7
First-order BOD decay — solve for remaining BOD (case 3) — National Research Council (NRC) Trickling Filter Performance (7)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 290.0 mg/L; rate constant (k) = 0.3000 1/day; time (t) = 6.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=290.0mg/Lultimate BOD (L_{0}) = 290.0 mg/L
  • rateconstant(k)=0.30001/dayrate constant (k) = 0.3000 1/day
  • time(t)=6.0000daytime (t) = 6.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=290.0mg/L,rateconstant(k)=0.30001/day,time(t)=6.0000dayList the givens: ultimate BOD (L_{0}) = 290.0 mg/L, rate constant (k) = 0.3000 1/day, time (t) = 6.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=47.9367 mg/LLt = 47.9367\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 47.9367 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=47.9367 mg/LLt = 47.9367\ \text{mg/L}

Why the other options are there

  • 95.8734 — kept a factor of two that cancels in the correct rearrangement.
  • 23.9683 — dropped that same factor in the other direction.
  • 52.7303 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 8
First-order BOD decay — solve for ultimate BOD (case 3) — National Research Council (NRC) Trickling Filter Performance (8)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.1500 1/day; time (t) = 5.5000 day; remaining BOD (Lt) = 223.3 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.15001/dayrate constant (k) = 0.1500 1/day
  • time(t)=5.5000daytime (t) = 5.5000 day
  • remainingBOD(Lt)=223.3mg/Lremaining BOD (Lt) = 223.3 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.15001/day,time(t)=5.5000day,remainingBOD(Lt)=223.3mg/LList the givens: rate constant (k) = 0.1500 1/day, time (t) = 5.5000 day, remaining BOD (Lt) = 223.3 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=509.5 mg/LL_{0} = 509.5\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 509.5 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=509.5 mg/LL_{0} = 509.5\ \text{mg/L}

Why the other options are there

  • 1,019 — kept a factor of two that cancels in the correct rearrangement.
  • 254.8 — dropped that same factor in the other direction.
  • 560.5 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 9
First-order BOD decay — solve for rate constant (case 3) — National Research Council (NRC) Trickling Filter Performance (9)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 120.0 mg/L; time (t) = 2.5000 day; remaining BOD (Lt) = 309.7 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=120.0mg/Lultimate BOD (L_{0}) = 120.0 mg/L
  • time(t)=2.5000daytime (t) = 2.5000 day
  • remainingBOD(Lt)=309.7mg/Lremaining BOD (Lt) = 309.7 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=120.0mg/L,time(t)=2.5000day,remainingBOD(Lt)=309.7mg/LList the givens: ultimate BOD (L_{0}) = 120.0 mg/L, time (t) = 2.5000 day, remaining BOD (Lt) = 309.7 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−0.3792 1/dayk = -0.3792\ \text{1/day}
  6. Step 6 — Check: returning k = -0.3792 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−0.3792 1/dayk = -0.3792\ \text{1/day}

Why the other options are there

  • -0.7585 — kept a factor of two that cancels in the correct rearrangement.
  • -0.1896 — dropped that same factor in the other direction.
  • -0.4172 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

Example 10
First-order BOD decay — solve for remaining BOD (case 4) — National Research Council (NRC) Trickling Filter Performance (10)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 400.0 mg/L; rate constant (k) = 0.1300 1/day; time (t) = 4.5000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=400.0mg/Lultimate BOD (L_{0}) = 400.0 mg/L
  • rateconstant(k)=0.13001/dayrate constant (k) = 0.1300 1/day
  • time(t)=4.5000daytime (t) = 4.5000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=400.0mg/L,rateconstant(k)=0.13001/day,time(t)=4.5000dayList the givens: ultimate BOD (L_{0}) = 400.0 mg/L, rate constant (k) = 0.1300 1/day, time (t) = 4.5000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=222.8 mg/LLt = 222.8\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 222.8 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=222.8 mg/LLt = 222.8\ \text{mg/L}

Why the other options are there

  • 445.7 — kept a factor of two that cancels in the correct rearrangement.
  • 111.4 — dropped that same factor in the other direction.
  • 245.1 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → National Research Council (NRC) Trickling Filter Performance

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