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Methanol Requirement for Biologically Treated Wastewater

Environmental Engineering · FE Reference Handbook section

Environmental Engineering
5 formulas
10 exam-style examples
~55 min
All Environmental Engineering lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Steady-state mass balance — solve for blended concentration — Methanol Requirement for Biologically Treated Wastewater

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 11.5000 MGD; concentration 1 (C1) = 2.0000 mg/L; flow 2 (Q2) = 13.0000 MGD; concentration 2 (C2) = 47.5000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=11.5000MGDflow 1 (Q_{1}) = 11.5000 MGD
  • concentration1(C1)=2.0000mg/Lconcentration 1 (C_{1}) = 2.0000 mg/L
  • flow2(Q2)=13.0000MGDflow 2 (Q_{2}) = 13.0000 MGD
  • concentration2(C2)=47.5000mg/Lconcentration 2 (C_{2}) = 47.5000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 11.5000 MGD, concentration 1 (C1) = 2.0000 mg/L, flow 2 (Q2) = 13.0000 MGD, concentration 2 (C2) = 47.5000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=26.1429 mg/LC = 26.1429\ \text{mg/L}
  6. Step 6 — Check: returning C = 26.1429 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=26.1429 mg/LC = 26.1429\ \text{mg/L}

Why the other options are there

  • 52.2857 — kept a factor of two that cancels in the correct rearrangement.
  • 13.0714 — dropped that same factor in the other direction.
  • 28.7571 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 2
Steady-state mass balance — solve for concentration 1 — Methanol Requirement for Biologically Treated Wastewater (2)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 17.5000 MGD; flow 2 (Q2) = 1.5000 MGD; concentration 2 (C2) = 9.5000 mg/L; blended concentration (C) = 36.8100 mg/L, determine the concentration 1 (C1) in mg/L.

Given

  • flow1(Q1)=17.5000MGDflow 1 (Q_{1}) = 17.5000 MGD
  • flow2(Q2)=1.5000MGDflow 2 (Q_{2}) = 1.5000 MGD
  • concentration2(C2)=9.5000mg/Lconcentration 2 (C_{2}) = 9.5000 mg/L
  • blendedconcentration(C)=36.8100mg/Lblended concentration (C) = 36.8100 mg/L

Find

concentration 1 (C1), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C1 is given, so isolate C1 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C1 stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 17.5000 MGD, flow 2 (Q2) = 1.5000 MGD, concentration 2 (C2) = 9.5000 mg/L, blended concentration (C) = 36.8100 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C1=39.1509 mg/LC_{1} = 39.1509\ \text{mg/L}
  6. Step 6 — Check: returning C1 = 39.1509 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C1=39.1509 mg/LC_{1} = 39.1509\ \text{mg/L}

Why the other options are there

  • 78.3017 — kept a factor of two that cancels in the correct rearrangement.
  • 19.5754 — dropped that same factor in the other direction.
  • 43.0659 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 3
Steady-state mass balance — solve for blended concentration (case 2) — Methanol Requirement for Biologically Treated Wastewater (3)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 4.5000 MGD; concentration 1 (C1) = 11.5000 mg/L; flow 2 (Q2) = 3.0000 MGD; concentration 2 (C2) = 13.0000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=4.5000MGDflow 1 (Q_{1}) = 4.5000 MGD
  • concentration1(C1)=11.5000mg/Lconcentration 1 (C_{1}) = 11.5000 mg/L
  • flow2(Q2)=3.0000MGDflow 2 (Q_{2}) = 3.0000 MGD
  • concentration2(C2)=13.0000mg/Lconcentration 2 (C_{2}) = 13.0000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 4.5000 MGD, concentration 1 (C1) = 11.5000 mg/L, flow 2 (Q2) = 3.0000 MGD, concentration 2 (C2) = 13.0000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=12.1000 mg/LC = 12.1000\ \text{mg/L}
  6. Step 6 — Check: returning C = 12.1000 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=12.1000 mg/LC = 12.1000\ \text{mg/L}

Why the other options are there

  • 24.2000 — kept a factor of two that cancels in the correct rearrangement.
  • 6.0500 — dropped that same factor in the other direction.
  • 13.3100 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 4
Steady-state mass balance — solve for concentration 1 (case 2) — Methanol Requirement for Biologically Treated Wastewater (4)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 10.5000 MGD; flow 2 (Q2) = 11.0000 MGD; concentration 2 (C2) = 31.5000 mg/L; blended concentration (C) = 49.0000 mg/L, determine the concentration 1 (C1) in mg/L.

Given

  • flow1(Q1)=10.5000MGDflow 1 (Q_{1}) = 10.5000 MGD
  • flow2(Q2)=11.0000MGDflow 2 (Q_{2}) = 11.0000 MGD
  • concentration2(C2)=31.5000mg/Lconcentration 2 (C_{2}) = 31.5000 mg/L
  • blendedconcentration(C)=49.0000mg/Lblended concentration (C) = 49.0000 mg/L

Find

concentration 1 (C1), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C1 is given, so isolate C1 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C1 stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 10.5000 MGD, flow 2 (Q2) = 11.0000 MGD, concentration 2 (C2) = 31.5000 mg/L, blended concentration (C) = 49.0000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C1=67.3333 mg/LC_{1} = 67.3333\ \text{mg/L}
  6. Step 6 — Check: returning C1 = 67.3333 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C1=67.3333 mg/LC_{1} = 67.3333\ \text{mg/L}

Why the other options are there

  • 134.7 — kept a factor of two that cancels in the correct rearrangement.
  • 33.6667 — dropped that same factor in the other direction.
  • 74.0667 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 5
Steady-state mass balance — solve for blended concentration (case 3) — Methanol Requirement for Biologically Treated Wastewater (5)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 9.5000 MGD; concentration 1 (C1) = 17.0000 mg/L; flow 2 (Q2) = 17.0000 MGD; concentration 2 (C2) = 28.0000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=9.5000MGDflow 1 (Q_{1}) = 9.5000 MGD
  • concentration1(C1)=17.0000mg/Lconcentration 1 (C_{1}) = 17.0000 mg/L
  • flow2(Q2)=17.0000MGDflow 2 (Q_{2}) = 17.0000 MGD
  • concentration2(C2)=28.0000mg/Lconcentration 2 (C_{2}) = 28.0000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 9.5000 MGD, concentration 1 (C1) = 17.0000 mg/L, flow 2 (Q2) = 17.0000 MGD, concentration 2 (C2) = 28.0000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=24.0566 mg/LC = 24.0566\ \text{mg/L}
  6. Step 6 — Check: returning C = 24.0566 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=24.0566 mg/LC = 24.0566\ \text{mg/L}

Why the other options are there

  • 48.1132 — kept a factor of two that cancels in the correct rearrangement.
  • 12.0283 — dropped that same factor in the other direction.
  • 26.4623 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 6
Steady-state mass balance — solve for concentration 1 (case 3) — Methanol Requirement for Biologically Treated Wastewater (6)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 9.0000 MGD; flow 2 (Q2) = 10.5000 MGD; concentration 2 (C2) = 34.0000 mg/L; blended concentration (C) = 13.4200 mg/L, determine the concentration 1 (C1) in mg/L.

Given

  • flow1(Q1)=9.0000MGDflow 1 (Q_{1}) = 9.0000 MGD
  • flow2(Q2)=10.5000MGDflow 2 (Q_{2}) = 10.5000 MGD
  • concentration2(C2)=34.0000mg/Lconcentration 2 (C_{2}) = 34.0000 mg/L
  • blendedconcentration(C)=13.4200mg/Lblended concentration (C) = 13.4200 mg/L

Find

concentration 1 (C1), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C1 is given, so isolate C1 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C1 stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 9.0000 MGD, flow 2 (Q2) = 10.5000 MGD, concentration 2 (C2) = 34.0000 mg/L, blended concentration (C) = 13.4200 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C1=−10.5900 mg/LC_{1} = -10.5900\ \text{mg/L}
  6. Step 6 — Check: returning C1 = -10.5900 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C1=−10.5900 mg/LC_{1} = -10.5900\ \text{mg/L}

Why the other options are there

  • -21.1800 — kept a factor of two that cancels in the correct rearrangement.
  • -5.2950 — dropped that same factor in the other direction.
  • -11.6490 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 7
Steady-state mass balance — solve for blended concentration (case 4) — Methanol Requirement for Biologically Treated Wastewater (7)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 5.0000 MGD; concentration 1 (C1) = 44.0000 mg/L; flow 2 (Q2) = 6.5000 MGD; concentration 2 (C2) = 5.5000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=5.0000MGDflow 1 (Q_{1}) = 5.0000 MGD
  • concentration1(C1)=44.0000mg/Lconcentration 1 (C_{1}) = 44.0000 mg/L
  • flow2(Q2)=6.5000MGDflow 2 (Q_{2}) = 6.5000 MGD
  • concentration2(C2)=5.5000mg/Lconcentration 2 (C_{2}) = 5.5000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 5.0000 MGD, concentration 1 (C1) = 44.0000 mg/L, flow 2 (Q2) = 6.5000 MGD, concentration 2 (C2) = 5.5000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=22.2391 mg/LC = 22.2391\ \text{mg/L}
  6. Step 6 — Check: returning C = 22.2391 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=22.2391 mg/LC = 22.2391\ \text{mg/L}

Why the other options are there

  • 44.4783 — kept a factor of two that cancels in the correct rearrangement.
  • 11.1196 — dropped that same factor in the other direction.
  • 24.4630 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 8
Steady-state mass balance — solve for concentration 1 (case 4) — Methanol Requirement for Biologically Treated Wastewater (8)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 13.5000 MGD; flow 2 (Q2) = 9.5000 MGD; concentration 2 (C2) = 23.5000 mg/L; blended concentration (C) = 9.9100 mg/L, determine the concentration 1 (C1) in mg/L.

Given

  • flow1(Q1)=13.5000MGDflow 1 (Q_{1}) = 13.5000 MGD
  • flow2(Q2)=9.5000MGDflow 2 (Q_{2}) = 9.5000 MGD
  • concentration2(C2)=23.5000mg/Lconcentration 2 (C_{2}) = 23.5000 mg/L
  • blendedconcentration(C)=9.9100mg/Lblended concentration (C) = 9.9100 mg/L

Find

concentration 1 (C1), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C1 is given, so isolate C1 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C1 stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 13.5000 MGD, flow 2 (Q2) = 9.5000 MGD, concentration 2 (C2) = 23.5000 mg/L, blended concentration (C) = 9.9100 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C1=0.3467 mg/LC_{1} = 0.3467\ \text{mg/L}
  6. Step 6 — Check: returning C1 = 0.3467 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C1=0.3467 mg/LC_{1} = 0.3467\ \text{mg/L}

Why the other options are there

  • 0.6933 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1733 — dropped that same factor in the other direction.
  • 0.3813 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 9
Steady-state mass balance — solve for blended concentration (case 5) — Methanol Requirement for Biologically Treated Wastewater (9)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 9.0000 MGD; concentration 1 (C1) = 31.5000 mg/L; flow 2 (Q2) = 12.0000 MGD; concentration 2 (C2) = 6.5000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=9.0000MGDflow 1 (Q_{1}) = 9.0000 MGD
  • concentration1(C1)=31.5000mg/Lconcentration 1 (C_{1}) = 31.5000 mg/L
  • flow2(Q2)=12.0000MGDflow 2 (Q_{2}) = 12.0000 MGD
  • concentration2(C2)=6.5000mg/Lconcentration 2 (C_{2}) = 6.5000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 9.0000 MGD, concentration 1 (C1) = 31.5000 mg/L, flow 2 (Q2) = 12.0000 MGD, concentration 2 (C2) = 6.5000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=17.2143 mg/LC = 17.2143\ \text{mg/L}
  6. Step 6 — Check: returning C = 17.2143 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=17.2143 mg/LC = 17.2143\ \text{mg/L}

Why the other options are there

  • 34.4286 — kept a factor of two that cancels in the correct rearrangement.
  • 8.6071 — dropped that same factor in the other direction.
  • 18.9357 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

Example 10
Steady-state mass balance — solve for concentration 1 (case 5) — Methanol Requirement for Biologically Treated Wastewater (10)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 13.0000 MGD; flow 2 (Q2) = 8.0000 MGD; concentration 2 (C2) = 29.5000 mg/L; blended concentration (C) = 30.4000 mg/L, determine the concentration 1 (C1) in mg/L.

Given

  • flow1(Q1)=13.0000MGDflow 1 (Q_{1}) = 13.0000 MGD
  • flow2(Q2)=8.0000MGDflow 2 (Q_{2}) = 8.0000 MGD
  • concentration2(C2)=29.5000mg/Lconcentration 2 (C_{2}) = 29.5000 mg/L
  • blendedconcentration(C)=30.4000mg/Lblended concentration (C) = 30.4000 mg/L

Find

concentration 1 (C1), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C1 is given, so isolate C1 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C1 stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 13.0000 MGD, flow 2 (Q2) = 8.0000 MGD, concentration 2 (C2) = 29.5000 mg/L, blended concentration (C) = 30.4000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C1=30.9538 mg/LC_{1} = 30.9538\ \text{mg/L}
  6. Step 6 — Check: returning C1 = 30.9538 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C1=30.9538 mg/LC_{1} = 30.9538\ \text{mg/L}

Why the other options are there

  • 61.9077 — kept a factor of two that cancels in the correct rearrangement.
  • 15.4769 — dropped that same factor in the other direction.
  • 34.0492 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Methanol Requirement for Biologically Treated Wastewater

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