hazardous waste incineration destruction and removal efficiency requirement Given mass fed to incinerator (W_in) = 181.0 kg/hr; mass emitted in stack (W_out) = 1.3300 kg/hr, determine the destruction and removal efficiency (DRE) in %.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except DRE is given, so isolate DRE symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for DRE:

   $$DRE = \dfrac{W_{in}-W_{out}}{W_{in}}\times 100$$

3. Step 3 — List the givens: mass fed to incinerator (W_in) = 181.0 kg/hr, mass emitted in stack (W_out) = 1.3300 kg/hr.

4. Step 4 — Substitute the given values:

   $$DRE = \dfrac{181.0-1.3300}{181.0}\times 100$$

5. Step 5 — Evaluate:

   DRE = 99.2652\ \text{%}

6. Step 6 — Check: returning DRE = 99.2652 % to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 198.5 — kept a factor of two that cancels in the correct rearrangement.
• 49.6326 — dropped that same factor in the other direction.
• 109.2 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

incineration DRE calculation from feed rate and stack emission rate Given mass fed to incinerator (W_in) = 109.0 kg/hr; destruction and removal efficiency (DRE) = 97.6200 %, determine the mass emitted in stack (W_out) in kg/hr.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except W_out is given, so isolate W_out symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for W_out:

   $$W_{out} = W_{in}\left(1-\dfrac{DRE}{100}\right)$$

3. Step 3 — List the givens: mass fed to incinerator (W_in) = 109.0 kg/hr, destruction and removal efficiency (DRE) = 97.6200 %.

4. Step 4 — Substitute the given values:

   $$W_{out} = 109.0\left(1-\dfrac{97.6200}{100}\right)$$

5. Step 5 — Evaluate:

   $$W_{out} = 2.5942\ \text{kg/hr}$$

6. Step 6 — Check: returning W_out = 2.5942 kg/hr to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 5.1884 — kept a factor of two that cancels in the correct rearrangement.
• 1.2971 — dropped that same factor in the other direction.
• 2.8536 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

incinerator DRE demonstration for regulatory compliance Given mass emitted in stack (W_out) = 1.1830 kg/hr; destruction and removal efficiency (DRE) = 90.9520 %, determine the mass fed to incinerator (W_in) in kg/hr.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except W_in is given, so isolate W_in symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for W_in:

   $$W_{in} = \dfrac{W_{out}}{1-\dfrac{DRE}{100}}$$

3. Step 3 — List the givens: mass emitted in stack (W_out) = 1.1830 kg/hr, destruction and removal efficiency (DRE) = 90.9520 %.

4. Step 4 — Substitute the given values:

   $$W_{in} = \dfrac{1.1830}{1-\dfrac{90.9520}{100}}$$

5. Step 5 — Evaluate:

   $$W_{in} = 13.0747\ \text{kg/hr}$$

6. Step 6 — Check: returning W_in = 13.0747 kg/hr to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 26.1494 — kept a factor of two that cancels in the correct rearrangement.
• 6.5374 — dropped that same factor in the other direction.
• 14.3822 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

hazardous waste incineration destruction and removal efficiency requirement Given mass fed to incinerator (W_in) = 467.0 kg/hr; mass emitted in stack (W_out) = 1.2380 kg/hr, determine the destruction and removal efficiency (DRE) in %.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except DRE is given, so isolate DRE symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for DRE:

   $$DRE = \dfrac{W_{in}-W_{out}}{W_{in}}\times 100$$

3. Step 3 — List the givens: mass fed to incinerator (W_in) = 467.0 kg/hr, mass emitted in stack (W_out) = 1.2380 kg/hr.

4. Step 4 — Substitute the given values:

   $$DRE = \dfrac{467.0-1.2380}{467.0}\times 100$$

5. Step 5 — Evaluate:

   DRE = 99.7349\ \text{%}

6. Step 6 — Check: returning DRE = 99.7349 % to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 199.5 — kept a factor of two that cancels in the correct rearrangement.
• 49.8675 — dropped that same factor in the other direction.
• 109.7 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

incineration DRE calculation from feed rate and stack emission rate Given mass fed to incinerator (W_in) = 702.0 kg/hr; destruction and removal efficiency (DRE) = 91.5700 %, determine the mass emitted in stack (W_out) in kg/hr.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except W_out is given, so isolate W_out symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for W_out:

   $$W_{out} = W_{in}\left(1-\dfrac{DRE}{100}\right)$$

3. Step 3 — List the givens: mass fed to incinerator (W_in) = 702.0 kg/hr, destruction and removal efficiency (DRE) = 91.5700 %.

4. Step 4 — Substitute the given values:

   $$W_{out} = 702.0\left(1-\dfrac{91.5700}{100}\right)$$

5. Step 5 — Evaluate:

   $$W_{out} = 59.1786\ \text{kg/hr}$$

6. Step 6 — Check: returning W_out = 59.1786 kg/hr to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 118.4 — kept a factor of two that cancels in the correct rearrangement.
• 29.5893 — dropped that same factor in the other direction.
• 65.0965 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

incinerator DRE demonstration for regulatory compliance Given mass emitted in stack (W_out) = 4.2810 kg/hr; destruction and removal efficiency (DRE) = 91.1820 %, determine the mass fed to incinerator (W_in) in kg/hr.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except W_in is given, so isolate W_in symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for W_in:

   $$W_{in} = \dfrac{W_{out}}{1-\dfrac{DRE}{100}}$$

3. Step 3 — List the givens: mass emitted in stack (W_out) = 4.2810 kg/hr, destruction and removal efficiency (DRE) = 91.1820 %.

4. Step 4 — Substitute the given values:

   $$W_{in} = \dfrac{4.2810}{1-\dfrac{91.1820}{100}}$$

5. Step 5 — Evaluate:

   $$W_{in} = 48.5484\ \text{kg/hr}$$

6. Step 6 — Check: returning W_in = 48.5484 kg/hr to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 97.0968 — kept a factor of two that cancels in the correct rearrangement.
• 24.2742 — dropped that same factor in the other direction.
• 53.4033 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

hazardous waste incineration destruction and removal efficiency requirement Given mass fed to incinerator (W_in) = 700.0 kg/hr; mass emitted in stack (W_out) = 3.7600 kg/hr, determine the destruction and removal efficiency (DRE) in %.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except DRE is given, so isolate DRE symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for DRE:

   $$DRE = \dfrac{W_{in}-W_{out}}{W_{in}}\times 100$$

3. Step 3 — List the givens: mass fed to incinerator (W_in) = 700.0 kg/hr, mass emitted in stack (W_out) = 3.7600 kg/hr.

4. Step 4 — Substitute the given values:

   $$DRE = \dfrac{700.0-3.7600}{700.0}\times 100$$

5. Step 5 — Evaluate:

   DRE = 99.4629\ \text{%}

6. Step 6 — Check: returning DRE = 99.4629 % to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 198.9 — kept a factor of two that cancels in the correct rearrangement.
• 49.7314 — dropped that same factor in the other direction.
• 109.4 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

incineration DRE calculation from feed rate and stack emission rate Given mass fed to incinerator (W_in) = 993.0 kg/hr; destruction and removal efficiency (DRE) = 96.3690 %, determine the mass emitted in stack (W_out) in kg/hr.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except W_out is given, so isolate W_out symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for W_out:

   $$W_{out} = W_{in}\left(1-\dfrac{DRE}{100}\right)$$

3. Step 3 — List the givens: mass fed to incinerator (W_in) = 993.0 kg/hr, destruction and removal efficiency (DRE) = 96.3690 %.

4. Step 4 — Substitute the given values:

   $$W_{out} = 993.0\left(1-\dfrac{96.3690}{100}\right)$$

5. Step 5 — Evaluate:

   $$W_{out} = 36.0558\ \text{kg/hr}$$

6. Step 6 — Check: returning W_out = 36.0558 kg/hr to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 72.1117 — kept a factor of two that cancels in the correct rearrangement.
• 18.0279 — dropped that same factor in the other direction.
• 39.6614 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

incinerator DRE demonstration for regulatory compliance Given mass emitted in stack (W_out) = 0.9930 kg/hr; destruction and removal efficiency (DRE) = 98.0830 %, determine the mass fed to incinerator (W_in) in kg/hr.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except W_in is given, so isolate W_in symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for W_in:

   $$W_{in} = \dfrac{W_{out}}{1-\dfrac{DRE}{100}}$$

3. Step 3 — List the givens: mass emitted in stack (W_out) = 0.9930 kg/hr, destruction and removal efficiency (DRE) = 98.0830 %.

4. Step 4 — Substitute the given values:

   $$W_{in} = \dfrac{0.9930}{1-\dfrac{98.0830}{100}}$$

5. Step 5 — Evaluate:

   $$W_{in} = 51.7997\ \text{kg/hr}$$

6. Step 6 — Check: returning W_in = 51.7997 kg/hr to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 103.6 — kept a factor of two that cancels in the correct rearrangement.
• 25.8998 — dropped that same factor in the other direction.
• 56.9797 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency

hazardous waste incineration destruction and removal efficiency requirement Given mass fed to incinerator (W_in) = 764.0 kg/hr; mass emitted in stack (W_out) = 2.1890 kg/hr, determine the destruction and removal efficiency (DRE) in %.

Start with the thinking

• The governing relation printed in this handbook section is Incineration (DRE).
• Everything except DRE is given, so isolate DRE symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Incineration performance is measured by the destruction and removal efficiency (DRE) of hazardous waste feed.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

2. Step 2 — Rearrange symbolically for DRE:

   $$DRE = \dfrac{W_{in}-W_{out}}{W_{in}}\times 100$$

3. Step 3 — List the givens: mass fed to incinerator (W_in) = 764.0 kg/hr, mass emitted in stack (W_out) = 2.1890 kg/hr.

4. Step 4 — Substitute the given values:

   $$DRE = \dfrac{764.0-2.1890}{764.0}\times 100$$

5. Step 5 — Evaluate:

   DRE = 99.7135\ \text{%}

6. Step 6 — Check: returning DRE = 99.7135 % to

   $$DRE = \dfrac{W_{in} - W_{out}}{W_{in}} \times 100$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 199.4 — kept a factor of two that cancels in the correct rearrangement.
• 49.8567 — dropped that same factor in the other direction.
• 109.7 — rounded an intermediate value before the final step.

Reference: FE Handbook — Incineration, Destruction and Removal Efficiency