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Gas Flux

Environmental Engineering · FE Reference Handbook section

Environmental Engineering
8 formulas
10 exam-style examples
~60 min
All Environmental Engineering lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • Typical values for the coefficient of diffusion for methane and carbon dioxide are 0.20 cm2/s (18.6 ft2/d) and 0.13 cm2/s

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Steady-state mass balance — solve for blended concentration — Gas Flux

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 9.5000 MGD; concentration 1 (C1) = 32.0000 mg/L; flow 2 (Q2) = 11.5000 MGD; concentration 2 (C2) = 28.0000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=9.5000MGDflow 1 (Q_{1}) = 9.5000 MGD
  • concentration1(C1)=32.0000mg/Lconcentration 1 (C_{1}) = 32.0000 mg/L
  • flow2(Q2)=11.5000MGDflow 2 (Q_{2}) = 11.5000 MGD
  • concentration2(C2)=28.0000mg/Lconcentration 2 (C_{2}) = 28.0000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 9.5000 MGD, concentration 1 (C1) = 32.0000 mg/L, flow 2 (Q2) = 11.5000 MGD, concentration 2 (C2) = 28.0000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=29.8095 mg/LC = 29.8095\ \text{mg/L}
  6. Step 6 — Check: returning C = 29.8095 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=29.8095 mg/LC = 29.8095\ \text{mg/L}

Why the other options are there

  • 59.6190 — kept a factor of two that cancels in the correct rearrangement.
  • 14.9048 — dropped that same factor in the other direction.
  • 32.7905 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Gas Flux

Example 2
Landfill (gas/leachate) — solve for landfill gas generation rate — Gas Flux (2)

landfill gas and leachate generation estimate for a closed cell Given methane generation potential (L_0) = 150.0 m^3/Mg; waste acceptance rate (R) = 90,200 Mg/yr; methane generation rate constant (k) = 0.0390 1/yr; time since landfill closure (c) = 4.5000 yr; time since waste placement (t) = 34.0000 yr, determine the landfill gas generation rate (Q_gas) in m^3/yr.

Given

  • methanegenerationpotential(L0)=150.0m3/Mgmethane generation potential (L_0) = 150.0 m^3/Mg
  • wasteacceptancerate(R)=90,200Mg/yrwaste acceptance rate (R) = 90,200 Mg/yr
  • methanegenerationrateconstant(k)=0.03901/yrmethane generation rate constant (k) = 0.0390 1/yr
  • timesincelandfillclosure(c)=4.5000yrtime since landfill closure (c) = 4.5000 yr
  • timesincewasteplacement(t)=34.0000yrtime since waste placement (t) = 34.0000 yr

Find

landfill gas generation rate (Q_gas), in m^3/yr

Start with the thinking

  • The governing relation printed in this handbook section is Landfill (gas/leachate).
  • Everything except Q_gas is given, so isolate Q_gas symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Landfill gas and leachate generation models estimate methane production and leachate flow from decomposing municipal solid waste.
years after placementgas generation rateLandfill gas generation curve

Figure 2 — schematic for Landfill (gas/leachate) — solve for landfill gas generation rate — Gas Flux (2)

Step-by-step solution

  1. Step 1 — State the governing relation:

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)
  2. Step 2 — Rearrange symbolically for Q_gas:

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0\dfrac{R}{k}\left(e^{-kc}-e^{-kt}\right)
  3. Step 3 — List the givens: methane generation potential (L_0) = 150.0 m^3/Mg, waste acceptance rate (R) = 90,200 Mg/yr, methane generation rate constant (k) = 0.0390 1/yr, time since landfill closure (c) = 4.5000 yr, time since waste placement (t) = 34.0000 yr.

  4. Step 4 — Substitute the given values:

    Qgas=L0902000.0390\lef34.0000(e−k4.5000−e−k34.0000\righ34.0000)Q_{gas} = L_0\dfrac{90200}{0.0390}\lef34.0000(e^{-k4.5000}-e^{-k34.0000}\righ34.0000)
  5. Step 5 — Evaluate:

    Q_{gas} = 198960422\ \text{m^3/yr}
  6. Step 6 — Check: returning Q_gas = 198,960,422 m^3/yr to

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Q_{gas} = 198960422\ \text{m^3/yr}

Why the other options are there

  • 397,920,844 — kept a factor of two that cancels in the correct rearrangement.
  • 99,480,211 — dropped that same factor in the other direction.
  • 218,856,464 — rounded an intermediate value before the final step.

Reference: FE Handbook — Landfill Gas Generation

Example 3
Steady-state mass balance — solve for concentration 1 — Gas Flux (3)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 18.0000 MGD; flow 2 (Q2) = 18.5000 MGD; concentration 2 (C2) = 15.0000 mg/L; blended concentration (C) = 31.2800 mg/L, determine the concentration 1 (C1) in mg/L.

Given

  • flow1(Q1)=18.0000MGDflow 1 (Q_{1}) = 18.0000 MGD
  • flow2(Q2)=18.5000MGDflow 2 (Q_{2}) = 18.5000 MGD
  • concentration2(C2)=15.0000mg/Lconcentration 2 (C_{2}) = 15.0000 mg/L
  • blendedconcentration(C)=31.2800mg/Lblended concentration (C) = 31.2800 mg/L

Find

concentration 1 (C1), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C1 is given, so isolate C1 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C1 stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 18.0000 MGD, flow 2 (Q2) = 18.5000 MGD, concentration 2 (C2) = 15.0000 mg/L, blended concentration (C) = 31.2800 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C1=48.0122 mg/LC_{1} = 48.0122\ \text{mg/L}
  6. Step 6 — Check: returning C1 = 48.0122 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C1=48.0122 mg/LC_{1} = 48.0122\ \text{mg/L}

Why the other options are there

  • 96.0244 — kept a factor of two that cancels in the correct rearrangement.
  • 24.0061 — dropped that same factor in the other direction.
  • 52.8134 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Gas Flux

Example 4
Landfill (gas/leachate) — solve for waste acceptance rate — Gas Flux (4)

landfill gas collection system sizing based on generation rate Given methane generation potential (L_0) = 98.0000 m^3/Mg; methane generation rate constant (k) = 0.0980 1/yr; time since landfill closure (c) = 0.1000 yr; time since waste placement (t) = 22.5000 yr; landfill gas generation rate (Q_gas) = 46,461,834 m^3/yr, determine the waste acceptance rate (R) in Mg/yr.

Given

  • methanegenerationpotential(L0)=98.0000m3/Mgmethane generation potential (L_0) = 98.0000 m^3/Mg
  • methanegenerationrateconstant(k)=0.09801/yrmethane generation rate constant (k) = 0.0980 1/yr
  • timesincelandfillclosure(c)=0.1000yrtime since landfill closure (c) = 0.1000 yr
  • timesincewasteplacement(t)=22.5000yrtime since waste placement (t) = 22.5000 yr
  • landfillgasgenerationrate(Qgas)=46,461,834m3/yrlandfill gas generation rate (Q_gas) = 46,461,834 m^3/yr

Find

waste acceptance rate (R), in Mg/yr

Start with the thinking

  • The governing relation printed in this handbook section is Landfill (gas/leachate).
  • Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Landfill gas and leachate generation models estimate methane production and leachate flow from decomposing municipal solid waste.
years after placementgas generation rateLandfill gas generation curve

Figure 4 — schematic for Landfill (gas/leachate) — solve for waste acceptance rate — Gas Flux (4)

Step-by-step solution

  1. Step 1 — State the governing relation:

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)
  2. Step 2 — Rearrange symbolically for R:

    R=QgaskL0(e−kc−e−kt)R = \dfrac{Q_{gas} k}{L_0\left(e^{-kc}-e^{-kt}\right)}
  3. Step 3 — List the givens: methane generation potential (L_0) = 98.0000 m^3/Mg, methane generation rate constant (k) = 0.0980 1/yr, time since landfill closure (c) = 0.1000 yr, time since waste placement (t) = 22.5000 yr, landfill gas generation rate (Q_gas) = 46,461,834 m^3/yr.

  4. Step 4 — Substitute the given values:

    R=464618340.0980L0\lef22.5000(e−k0.1000−e−k22.5000\righ22.5000)R = \dfrac{46461834 0.0980}{L_0\lef22.5000(e^{-k0.1000}-e^{-k22.5000}\righ22.5000)}
  5. Step 5 — Evaluate:

    R=52798 Mg/yrR = 52798\ \text{Mg/yr}
  6. Step 6 — Check: returning R = 52,798 Mg/yr to

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)

    reproduces the given quantities, and both sides carry the same units.

Answer:
R=52798 Mg/yrR = 52798\ \text{Mg/yr}

Why the other options are there

  • 105,595 — kept a factor of two that cancels in the correct rearrangement.
  • 26,399 — dropped that same factor in the other direction.
  • 58,077 — rounded an intermediate value before the final step.

Reference: FE Handbook — Landfill Gas Generation

Example 5
Steady-state mass balance — solve for blended concentration (case 2) — Gas Flux (5)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 18.0000 MGD; concentration 1 (C1) = 23.5000 mg/L; flow 2 (Q2) = 5.5000 MGD; concentration 2 (C2) = 41.0000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=18.0000MGDflow 1 (Q_{1}) = 18.0000 MGD
  • concentration1(C1)=23.5000mg/Lconcentration 1 (C_{1}) = 23.5000 mg/L
  • flow2(Q2)=5.5000MGDflow 2 (Q_{2}) = 5.5000 MGD
  • concentration2(C2)=41.0000mg/Lconcentration 2 (C_{2}) = 41.0000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 18.0000 MGD, concentration 1 (C1) = 23.5000 mg/L, flow 2 (Q2) = 5.5000 MGD, concentration 2 (C2) = 41.0000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=27.5957 mg/LC = 27.5957\ \text{mg/L}
  6. Step 6 — Check: returning C = 27.5957 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=27.5957 mg/LC = 27.5957\ \text{mg/L}

Why the other options are there

  • 55.1915 — kept a factor of two that cancels in the correct rearrangement.
  • 13.7979 — dropped that same factor in the other direction.
  • 30.3553 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Gas Flux

Example 6
Landfill (gas/leachate) — solve for methane generation potential — Gas Flux (6)

landfill gas generation model for a municipal solid waste landfill Given waste acceptance rate (R) = 14,500 Mg/yr; methane generation rate constant (k) = 0.0850 1/yr; time since landfill closure (c) = 0.6000 yr; time since waste placement (t) = 24.0000 yr; landfill gas generation rate (Q_gas) = 5,799,587 m^3/yr, determine the methane generation potential (L_0) in m^3/Mg.

Given

  • wasteacceptancerate(R)=14,500Mg/yrwaste acceptance rate (R) = 14,500 Mg/yr
  • methanegenerationrateconstant(k)=0.08501/yrmethane generation rate constant (k) = 0.0850 1/yr
  • timesincelandfillclosure(c)=0.6000yrtime since landfill closure (c) = 0.6000 yr
  • timesincewasteplacement(t)=24.0000yrtime since waste placement (t) = 24.0000 yr
  • landfillgasgenerationrate(Qgas)=5,799,587m3/yrlandfill gas generation rate (Q_gas) = 5,799,587 m^3/yr

Find

methane generation potential (L_0), in m^3/Mg

Start with the thinking

  • The governing relation printed in this handbook section is Landfill (gas/leachate).
  • Everything except L_0 is given, so isolate L_0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Landfill gas and leachate generation models estimate methane production and leachate flow from decomposing municipal solid waste.
years after placementgas generation rateLandfill gas generation curve

Figure 6 — schematic for Landfill (gas/leachate) — solve for methane generation potential — Gas Flux (6)

Step-by-step solution

  1. Step 1 — State the governing relation:

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)
  2. Step 2 — Rearrange symbolically for L_0:

    L0=QgaskR(e−kc−e−kt)L_{0} = \dfrac{Q_{gas} k}{R\left(e^{-kc}-e^{-kt}\right)}
  3. Step 3 — List the givens: waste acceptance rate (R) = 14,500 Mg/yr, methane generation rate constant (k) = 0.0850 1/yr, time since landfill closure (c) = 0.6000 yr, time since waste placement (t) = 24.0000 yr, landfill gas generation rate (Q_gas) = 5,799,587 m^3/yr.

  4. Step 4 — Substitute the given values:

    L0=57995870.085014500\lef24.0000(e−k0.6000−e−k24.0000\righ24.0000)L_{0} = \dfrac{5799587 0.0850}{14500\lef24.0000(e^{-k0.6000}-e^{-k24.0000}\righ24.0000)}
  5. Step 5 — Evaluate:

    L_{0} = 41.4478\ \text{m^3/Mg}
  6. Step 6 — Check: returning L_0 = 41.4478 m^3/Mg to

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)

    reproduces the given quantities, and both sides carry the same units.

Answer:
L_{0} = 41.4478\ \text{m^3/Mg}

Why the other options are there

  • 82.8957 — kept a factor of two that cancels in the correct rearrangement.
  • 20.7239 — dropped that same factor in the other direction.
  • 45.5926 — rounded an intermediate value before the final step.

Reference: FE Handbook — Landfill Gas Generation

Example 7
Steady-state mass balance — solve for concentration 1 (case 2) — Gas Flux (7)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 6.0000 MGD; flow 2 (Q2) = 8.5000 MGD; concentration 2 (C2) = 23.0000 mg/L; blended concentration (C) = 44.5400 mg/L, determine the concentration 1 (C1) in mg/L.

Given

  • flow1(Q1)=6.0000MGDflow 1 (Q_{1}) = 6.0000 MGD
  • flow2(Q2)=8.5000MGDflow 2 (Q_{2}) = 8.5000 MGD
  • concentration2(C2)=23.0000mg/Lconcentration 2 (C_{2}) = 23.0000 mg/L
  • blendedconcentration(C)=44.5400mg/Lblended concentration (C) = 44.5400 mg/L

Find

concentration 1 (C1), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C1 is given, so isolate C1 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C1 stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 6.0000 MGD, flow 2 (Q2) = 8.5000 MGD, concentration 2 (C2) = 23.0000 mg/L, blended concentration (C) = 44.5400 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C1=75.0550 mg/LC_{1} = 75.0550\ \text{mg/L}
  6. Step 6 — Check: returning C1 = 75.0550 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C1=75.0550 mg/LC_{1} = 75.0550\ \text{mg/L}

Why the other options are there

  • 150.1 — kept a factor of two that cancels in the correct rearrangement.
  • 37.5275 — dropped that same factor in the other direction.
  • 82.5605 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Gas Flux

Example 8
Landfill (gas/leachate) — solve for landfill gas generation rate (case 2) — Gas Flux (8)

landfill gas and leachate generation estimate for a closed cell Given methane generation potential (L_0) = 99.0000 m^3/Mg; waste acceptance rate (R) = 2,000 Mg/yr; methane generation rate constant (k) = 0.1180 1/yr; time since landfill closure (c) = 3.9000 yr; time since waste placement (t) = 34.5000 yr, determine the landfill gas generation rate (Q_gas) in m^3/yr.

Given

  • methanegenerationpotential(L0)=99.0000m3/Mgmethane generation potential (L_0) = 99.0000 m^3/Mg
  • wasteacceptancerate(R)=2,000Mg/yrwaste acceptance rate (R) = 2,000 Mg/yr
  • methanegenerationrateconstant(k)=0.11801/yrmethane generation rate constant (k) = 0.1180 1/yr
  • timesincelandfillclosure(c)=3.9000yrtime since landfill closure (c) = 3.9000 yr
  • timesincewasteplacement(t)=34.5000yrtime since waste placement (t) = 34.5000 yr

Find

landfill gas generation rate (Q_gas), in m^3/yr

Start with the thinking

  • The governing relation printed in this handbook section is Landfill (gas/leachate).
  • Everything except Q_gas is given, so isolate Q_gas symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Landfill gas and leachate generation models estimate methane production and leachate flow from decomposing municipal solid waste.
years after placementgas generation rateLandfill gas generation curve

Figure 8 — schematic for Landfill (gas/leachate) — solve for landfill gas generation rate (case 2) — Gas Flux (8)

Step-by-step solution

  1. Step 1 — State the governing relation:

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)
  2. Step 2 — Rearrange symbolically for Q_gas:

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0\dfrac{R}{k}\left(e^{-kc}-e^{-kt}\right)
  3. Step 3 — List the givens: methane generation potential (L_0) = 99.0000 m^3/Mg, waste acceptance rate (R) = 2,000 Mg/yr, methane generation rate constant (k) = 0.1180 1/yr, time since landfill closure (c) = 3.9000 yr, time since waste placement (t) = 34.5000 yr.

  4. Step 4 — Substitute the given values:

    Qgas=L020000.1180\lef34.5000(e−k3.9000−e−k34.5000\righ34.5000)Q_{gas} = L_0\dfrac{2000}{0.1180}\lef34.5000(e^{-k3.9000}-e^{-k34.5000}\righ34.5000)
  5. Step 5 — Evaluate:

    Q_{gas} = 1030434\ \text{m^3/yr}
  6. Step 6 — Check: returning Q_gas = 1,030,434 m^3/yr to

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)

    reproduces the given quantities, and both sides carry the same units.

Answer:
Q_{gas} = 1030434\ \text{m^3/yr}

Why the other options are there

  • 2,060,868 — kept a factor of two that cancels in the correct rearrangement.
  • 515,217 — dropped that same factor in the other direction.
  • 1,133,477 — rounded an intermediate value before the final step.

Reference: FE Handbook — Landfill Gas Generation

Example 9
Steady-state mass balance — solve for blended concentration (case 3) — Gas Flux (9)

A environmental engineering problem uses Steady-state mass balance. Given flow 1 (Q1) = 14.5000 MGD; concentration 1 (C1) = 48.5000 mg/L; flow 2 (Q2) = 19.0000 MGD; concentration 2 (C2) = 47.5000 mg/L, determine the blended concentration (C) in mg/L.

Given

  • flow1(Q1)=14.5000MGDflow 1 (Q_{1}) = 14.5000 MGD
  • concentration1(C1)=48.5000mg/Lconcentration 1 (C_{1}) = 48.5000 mg/L
  • flow2(Q2)=19.0000MGDflow 2 (Q_{2}) = 19.0000 MGD
  • concentration2(C2)=47.5000mg/Lconcentration 2 (C_{2}) = 47.5000 mg/L

Find

blended concentration (C), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is Steady-state mass balance.
  • Everything except C is given, so isolate C symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)
  2. Step 2 — Rearrange the relation so that C stands alone on the left-hand side.

  3. Step 3 — List the givens: flow 1 (Q1) = 14.5000 MGD, concentration 1 (C1) = 48.5000 mg/L, flow 2 (Q2) = 19.0000 MGD, concentration 2 (C2) = 47.5000 mg/L.

  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    C=47.9328 mg/LC = 47.9328\ \text{mg/L}
  6. Step 6 — Check: returning C = 47.9328 mg/L to

    C=(Q1C1+Q2C2)/(Q1+Q2)C = (Q_1 C_1 + Q_2 C_2) / (Q_1 + Q_2)

    reproduces the given quantities, and both sides carry the same units.

Answer:
C=47.9328 mg/LC = 47.9328\ \text{mg/L}

Why the other options are there

  • 95.8657 — kept a factor of two that cancels in the correct rearrangement.
  • 23.9664 — dropped that same factor in the other direction.
  • 52.7261 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Gas Flux

Example 10
Landfill (gas/leachate) — solve for waste acceptance rate (case 2) — Gas Flux (10)

landfill gas collection system sizing based on generation rate Given methane generation potential (L_0) = 134.0 m^3/Mg; methane generation rate constant (k) = 0.0300 1/yr; time since landfill closure (c) = 2.6000 yr; time since waste placement (t) = 20.0000 yr; landfill gas generation rate (Q_gas) = 26,716,531 m^3/yr, determine the waste acceptance rate (R) in Mg/yr.

Given

  • methanegenerationpotential(L0)=134.0m3/Mgmethane generation potential (L_0) = 134.0 m^3/Mg
  • methanegenerationrateconstant(k)=0.03001/yrmethane generation rate constant (k) = 0.0300 1/yr
  • timesincelandfillclosure(c)=2.6000yrtime since landfill closure (c) = 2.6000 yr
  • timesincewasteplacement(t)=20.0000yrtime since waste placement (t) = 20.0000 yr
  • landfillgasgenerationrate(Qgas)=26,716,531m3/yrlandfill gas generation rate (Q_gas) = 26,716,531 m^3/yr

Find

waste acceptance rate (R), in Mg/yr

Start with the thinking

  • The governing relation printed in this handbook section is Landfill (gas/leachate).
  • Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Landfill gas and leachate generation models estimate methane production and leachate flow from decomposing municipal solid waste.
years after placementgas generation rateLandfill gas generation curve

Figure 10 — schematic for Landfill (gas/leachate) — solve for waste acceptance rate (case 2) — Gas Flux (10)

Step-by-step solution

  1. Step 1 — State the governing relation:

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)
  2. Step 2 — Rearrange symbolically for R:

    R=QgaskL0(e−kc−e−kt)R = \dfrac{Q_{gas} k}{L_0\left(e^{-kc}-e^{-kt}\right)}
  3. Step 3 — List the givens: methane generation potential (L_0) = 134.0 m^3/Mg, methane generation rate constant (k) = 0.0300 1/yr, time since landfill closure (c) = 2.6000 yr, time since waste placement (t) = 20.0000 yr, landfill gas generation rate (Q_gas) = 26,716,531 m^3/yr.

  4. Step 4 — Substitute the given values:

    R=267165310.0300L0\lef20.0000(e−k2.6000−e−k20.0000\righ20.0000)R = \dfrac{26716531 0.0300}{L_0\lef20.0000(e^{-k2.6000}-e^{-k20.0000}\righ20.0000)}
  5. Step 5 — Evaluate:

    R=15901 Mg/yrR = 15901\ \text{Mg/yr}
  6. Step 6 — Check: returning R = 15,901 Mg/yr to

    Qgas=L0Rk(e−kc−e−kt)Q_{gas} = L_0 \dfrac{R}{k}\left(e^{-kc} - e^{-kt}\right)

    reproduces the given quantities, and both sides carry the same units.

Answer:
R=15901 Mg/yrR = 15901\ \text{Mg/yr}

Why the other options are there

  • 31,803 — kept a factor of two that cancels in the correct rearrangement.
  • 7,951 — dropped that same factor in the other direction.
  • 17,491 — rounded an intermediate value before the final step.

Reference: FE Handbook — Landfill Gas Generation

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