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Daughter Product Activity

Environmental Engineering · FE Reference Handbook section

Environmental Engineering
4 formulas
10 exam-style examples
~53 min
All Environmental Engineering lectures

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
First-order BOD decay — solve for remaining BOD — Daughter Product Activity

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 160.0 mg/L; rate constant (k) = 0.2700 1/day; time (t) = 7.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=160.0mg/Lultimate BOD (L_{0}) = 160.0 mg/L
  • rateconstant(k)=0.27001/dayrate constant (k) = 0.2700 1/day
  • time(t)=7.0000daytime (t) = 7.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=160.0mg/L,rateconstant(k)=0.27001/day,time(t)=7.0000dayList the givens: ultimate BOD (L_{0}) = 160.0 mg/L, rate constant (k) = 0.2700 1/day, time (t) = 7.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=24.1715 mg/LLt = 24.1715\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 24.1715 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=24.1715 mg/LLt = 24.1715\ \text{mg/L}

Why the other options are there

  • 48.3430 — kept a factor of two that cancels in the correct rearrangement.
  • 12.0857 — dropped that same factor in the other direction.
  • 26.5886 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 2
First-order BOD decay — solve for ultimate BOD — Daughter Product Activity (2)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.1700 1/day; time (t) = 3.5000 day; remaining BOD (Lt) = 301.8 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.17001/dayrate constant (k) = 0.1700 1/day
  • time(t)=3.5000daytime (t) = 3.5000 day
  • remainingBOD(Lt)=301.8mg/Lremaining BOD (Lt) = 301.8 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.17001/day,time(t)=3.5000day,remainingBOD(Lt)=301.8mg/LList the givens: rate constant (k) = 0.1700 1/day, time (t) = 3.5000 day, remaining BOD (Lt) = 301.8 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=547.2 mg/LL_{0} = 547.2\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 547.2 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=547.2 mg/LL_{0} = 547.2\ \text{mg/L}

Why the other options are there

  • 1,094 — kept a factor of two that cancels in the correct rearrangement.
  • 273.6 — dropped that same factor in the other direction.
  • 601.9 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 3
First-order BOD decay — solve for rate constant — Daughter Product Activity (3)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 300.0 mg/L; time (t) = 7.5000 day; remaining BOD (Lt) = 180.4 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=300.0mg/Lultimate BOD (L_{0}) = 300.0 mg/L
  • time(t)=7.5000daytime (t) = 7.5000 day
  • remainingBOD(Lt)=180.4mg/Lremaining BOD (Lt) = 180.4 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=300.0mg/L,time(t)=7.5000day,remainingBOD(Lt)=180.4mg/LList the givens: ultimate BOD (L_{0}) = 300.0 mg/L, time (t) = 7.5000 day, remaining BOD (Lt) = 180.4 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=0.0678 1/dayk = 0.0678\ \text{1/day}
  6. Step 6 — Check: returning k = 0.0678 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.0678 1/dayk = 0.0678\ \text{1/day}

Why the other options are there

  • 0.1356 — kept a factor of two that cancels in the correct rearrangement.
  • 0.0339 — dropped that same factor in the other direction.
  • 0.0746 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 4
First-order BOD decay — solve for remaining BOD (case 2) — Daughter Product Activity (4)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 275.0 mg/L; rate constant (k) = 0.2600 1/day; time (t) = 7.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=275.0mg/Lultimate BOD (L_{0}) = 275.0 mg/L
  • rateconstant(k)=0.26001/dayrate constant (k) = 0.2600 1/day
  • time(t)=7.0000daytime (t) = 7.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=275.0mg/L,rateconstant(k)=0.26001/day,time(t)=7.0000dayList the givens: ultimate BOD (L_{0}) = 275.0 mg/L, rate constant (k) = 0.2600 1/day, time (t) = 7.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=44.5571 mg/LLt = 44.5571\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 44.5571 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=44.5571 mg/LLt = 44.5571\ \text{mg/L}

Why the other options are there

  • 89.1142 — kept a factor of two that cancels in the correct rearrangement.
  • 22.2785 — dropped that same factor in the other direction.
  • 49.0128 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 5
First-order BOD decay — solve for ultimate BOD (case 2) — Daughter Product Activity (5)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.0500 1/day; time (t) = 7.5000 day; remaining BOD (Lt) = 279.7 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.05001/dayrate constant (k) = 0.0500 1/day
  • time(t)=7.5000daytime (t) = 7.5000 day
  • remainingBOD(Lt)=279.7mg/Lremaining BOD (Lt) = 279.7 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.05001/day,time(t)=7.5000day,remainingBOD(Lt)=279.7mg/LList the givens: rate constant (k) = 0.0500 1/day, time (t) = 7.5000 day, remaining BOD (Lt) = 279.7 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=407.0 mg/LL_{0} = 407.0\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 407.0 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=407.0 mg/LL_{0} = 407.0\ \text{mg/L}

Why the other options are there

  • 813.9 — kept a factor of two that cancels in the correct rearrangement.
  • 203.5 — dropped that same factor in the other direction.
  • 447.7 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 6
First-order BOD decay — solve for rate constant (case 2) — Daughter Product Activity (6)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 275.0 mg/L; time (t) = 3.0000 day; remaining BOD (Lt) = 374.5 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=275.0mg/Lultimate BOD (L_{0}) = 275.0 mg/L
  • time(t)=3.0000daytime (t) = 3.0000 day
  • remainingBOD(Lt)=374.5mg/Lremaining BOD (Lt) = 374.5 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=275.0mg/L,time(t)=3.0000day,remainingBOD(Lt)=374.5mg/LList the givens: ultimate BOD (L_{0}) = 275.0 mg/L, time (t) = 3.0000 day, remaining BOD (Lt) = 374.5 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−0.1029 1/dayk = -0.1029\ \text{1/day}
  6. Step 6 — Check: returning k = -0.1029 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−0.1029 1/dayk = -0.1029\ \text{1/day}

Why the other options are there

  • -0.2059 — kept a factor of two that cancels in the correct rearrangement.
  • -0.0515 — dropped that same factor in the other direction.
  • -0.1132 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 7
First-order BOD decay — solve for remaining BOD (case 3) — Daughter Product Activity (7)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 290.0 mg/L; rate constant (k) = 0.1800 1/day; time (t) = 4.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=290.0mg/Lultimate BOD (L_{0}) = 290.0 mg/L
  • rateconstant(k)=0.18001/dayrate constant (k) = 0.1800 1/day
  • time(t)=4.0000daytime (t) = 4.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=290.0mg/L,rateconstant(k)=0.18001/day,time(t)=4.0000dayList the givens: ultimate BOD (L_{0}) = 290.0 mg/L, rate constant (k) = 0.1800 1/day, time (t) = 4.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=141.2 mg/LLt = 141.2\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 141.2 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=141.2 mg/LLt = 141.2\ \text{mg/L}

Why the other options are there

  • 282.3 — kept a factor of two that cancels in the correct rearrangement.
  • 70.5791 — dropped that same factor in the other direction.
  • 155.3 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 8
First-order BOD decay — solve for ultimate BOD (case 3) — Daughter Product Activity (8)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.1200 1/day; time (t) = 7.0000 day; remaining BOD (Lt) = 12.4000 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.12001/dayrate constant (k) = 0.1200 1/day
  • time(t)=7.0000daytime (t) = 7.0000 day
  • remainingBOD(Lt)=12.4000mg/Lremaining BOD (Lt) = 12.4000 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.12001/day,time(t)=7.0000day,remainingBOD(Lt)=12.4000mg/LList the givens: rate constant (k) = 0.1200 1/day, time (t) = 7.0000 day, remaining BOD (Lt) = 12.4000 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=28.7230 mg/LL_{0} = 28.7230\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 28.7230 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=28.7230 mg/LL_{0} = 28.7230\ \text{mg/L}

Why the other options are there

  • 57.4459 — kept a factor of two that cancels in the correct rearrangement.
  • 14.3615 — dropped that same factor in the other direction.
  • 31.5952 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 9
First-order BOD decay — solve for rate constant (case 3) — Daughter Product Activity (9)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 250.0 mg/L; time (t) = 9.0000 day; remaining BOD (Lt) = 97.2000 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=250.0mg/Lultimate BOD (L_{0}) = 250.0 mg/L
  • time(t)=9.0000daytime (t) = 9.0000 day
  • remainingBOD(Lt)=97.2000mg/Lremaining BOD (Lt) = 97.2000 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=250.0mg/L,time(t)=9.0000day,remainingBOD(Lt)=97.2000mg/LList the givens: ultimate BOD (L_{0}) = 250.0 mg/L, time (t) = 9.0000 day, remaining BOD (Lt) = 97.2000 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=0.1050 1/dayk = 0.1050\ \text{1/day}
  6. Step 6 — Check: returning k = 0.1050 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.1050 1/dayk = 0.1050\ \text{1/day}

Why the other options are there

  • 0.2099 — kept a factor of two that cancels in the correct rearrangement.
  • 0.0525 — dropped that same factor in the other direction.
  • 0.1155 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

Example 10
First-order BOD decay — solve for remaining BOD (case 4) — Daughter Product Activity (10)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 380.0 mg/L; rate constant (k) = 0.0900 1/day; time (t) = 10.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=380.0mg/Lultimate BOD (L_{0}) = 380.0 mg/L
  • rateconstant(k)=0.09001/dayrate constant (k) = 0.0900 1/day
  • time(t)=10.0000daytime (t) = 10.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=380.0mg/L,rateconstant(k)=0.09001/day,time(t)=10.0000dayList the givens: ultimate BOD (L_{0}) = 380.0 mg/L, rate constant (k) = 0.0900 1/day, time (t) = 10.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=154.5 mg/LLt = 154.5\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 154.5 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=154.5 mg/LLt = 154.5\ \text{mg/L}

Why the other options are there

  • 309.0 — kept a factor of two that cancels in the correct rearrangement.
  • 77.2482 — dropped that same factor in the other direction.
  • 169.9 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Daughter Product Activity

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