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Cyclone Effective Number of Turns Approximation

Environmental Engineering · FE Reference Handbook section

Environmental Engineering
5 formulas
10 exam-style examples
~55 min
All Environmental Engineering lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • Cyclone Rao of Dimensions to Body Diameter
  • Dimension High Efficiency Conventional High Throughput

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
First-order BOD decay — solve for remaining BOD — Cyclone Effective Number of Turns Approximation

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 395.0 mg/L; rate constant (k) = 0.1400 1/day; time (t) = 7.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=395.0mg/Lultimate BOD (L_{0}) = 395.0 mg/L
  • rateconstant(k)=0.14001/dayrate constant (k) = 0.1400 1/day
  • time(t)=7.0000daytime (t) = 7.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=395.0mg/L,rateconstant(k)=0.14001/day,time(t)=7.0000dayList the givens: ultimate BOD (L_{0}) = 395.0 mg/L, rate constant (k) = 0.1400 1/day, time (t) = 7.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=148.2 mg/LLt = 148.2\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 148.2 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=148.2 mg/LLt = 148.2\ \text{mg/L}

Why the other options are there

  • 296.5 — kept a factor of two that cancels in the correct rearrangement.
  • 74.1239 — dropped that same factor in the other direction.
  • 163.1 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 2
First-order BOD decay — solve for ultimate BOD — Cyclone Effective Number of Turns Approximation (2)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.2700 1/day; time (t) = 1.5000 day; remaining BOD (Lt) = 210.3 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.27001/dayrate constant (k) = 0.2700 1/day
  • time(t)=1.5000daytime (t) = 1.5000 day
  • remainingBOD(Lt)=210.3mg/Lremaining BOD (Lt) = 210.3 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.27001/day,time(t)=1.5000day,remainingBOD(Lt)=210.3mg/LList the givens: rate constant (k) = 0.2700 1/day, time (t) = 1.5000 day, remaining BOD (Lt) = 210.3 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=315.3 mg/LL_{0} = 315.3\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 315.3 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=315.3 mg/LL_{0} = 315.3\ \text{mg/L}

Why the other options are there

  • 630.6 — kept a factor of two that cancels in the correct rearrangement.
  • 157.7 — dropped that same factor in the other direction.
  • 346.8 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 3
First-order BOD decay — solve for rate constant — Cyclone Effective Number of Turns Approximation (3)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 110.0 mg/L; time (t) = 6.0000 day; remaining BOD (Lt) = 249.2 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=110.0mg/Lultimate BOD (L_{0}) = 110.0 mg/L
  • time(t)=6.0000daytime (t) = 6.0000 day
  • remainingBOD(Lt)=249.2mg/Lremaining BOD (Lt) = 249.2 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=110.0mg/L,time(t)=6.0000day,remainingBOD(Lt)=249.2mg/LList the givens: ultimate BOD (L_{0}) = 110.0 mg/L, time (t) = 6.0000 day, remaining BOD (Lt) = 249.2 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−0.1363 1/dayk = -0.1363\ \text{1/day}
  6. Step 6 — Check: returning k = -0.1363 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−0.1363 1/dayk = -0.1363\ \text{1/day}

Why the other options are there

  • -0.2726 — kept a factor of two that cancels in the correct rearrangement.
  • -0.0681 — dropped that same factor in the other direction.
  • -0.1499 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 4
First-order BOD decay — solve for remaining BOD (case 2) — Cyclone Effective Number of Turns Approximation (4)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 370.0 mg/L; rate constant (k) = 0.2500 1/day; time (t) = 10.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=370.0mg/Lultimate BOD (L_{0}) = 370.0 mg/L
  • rateconstant(k)=0.25001/dayrate constant (k) = 0.2500 1/day
  • time(t)=10.0000daytime (t) = 10.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=370.0mg/L,rateconstant(k)=0.25001/day,time(t)=10.0000dayList the givens: ultimate BOD (L_{0}) = 370.0 mg/L, rate constant (k) = 0.2500 1/day, time (t) = 10.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=30.3714 mg/LLt = 30.3714\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 30.3714 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=30.3714 mg/LLt = 30.3714\ \text{mg/L}

Why the other options are there

  • 60.7429 — kept a factor of two that cancels in the correct rearrangement.
  • 15.1857 — dropped that same factor in the other direction.
  • 33.4086 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 5
First-order BOD decay — solve for ultimate BOD (case 2) — Cyclone Effective Number of Turns Approximation (5)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.3000 1/day; time (t) = 5.5000 day; remaining BOD (Lt) = 237.0 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.30001/dayrate constant (k) = 0.3000 1/day
  • time(t)=5.5000daytime (t) = 5.5000 day
  • remainingBOD(Lt)=237.0mg/Lremaining BOD (Lt) = 237.0 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.30001/day,time(t)=5.5000day,remainingBOD(Lt)=237.0mg/LList the givens: rate constant (k) = 0.3000 1/day, time (t) = 5.5000 day, remaining BOD (Lt) = 237.0 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=1234 mg/LL_{0} = 1234\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 1,234 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=1234 mg/LL_{0} = 1234\ \text{mg/L}

Why the other options are there

  • 2,468 — kept a factor of two that cancels in the correct rearrangement.
  • 617.0 — dropped that same factor in the other direction.
  • 1,357 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 6
First-order BOD decay — solve for rate constant (case 2) — Cyclone Effective Number of Turns Approximation (6)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 170.0 mg/L; time (t) = 8.0000 day; remaining BOD (Lt) = 28.7000 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=170.0mg/Lultimate BOD (L_{0}) = 170.0 mg/L
  • time(t)=8.0000daytime (t) = 8.0000 day
  • remainingBOD(Lt)=28.7000mg/Lremaining BOD (Lt) = 28.7000 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=170.0mg/L,time(t)=8.0000day,remainingBOD(Lt)=28.7000mg/LList the givens: ultimate BOD (L_{0}) = 170.0 mg/L, time (t) = 8.0000 day, remaining BOD (Lt) = 28.7000 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=0.2224 1/dayk = 0.2224\ \text{1/day}
  6. Step 6 — Check: returning k = 0.2224 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.2224 1/dayk = 0.2224\ \text{1/day}

Why the other options are there

  • 0.4447 — kept a factor of two that cancels in the correct rearrangement.
  • 0.1112 — dropped that same factor in the other direction.
  • 0.2446 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 7
First-order BOD decay — solve for remaining BOD (case 3) — Cyclone Effective Number of Turns Approximation (7)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 215.0 mg/L; rate constant (k) = 0.1500 1/day; time (t) = 4.5000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=215.0mg/Lultimate BOD (L_{0}) = 215.0 mg/L
  • rateconstant(k)=0.15001/dayrate constant (k) = 0.1500 1/day
  • time(t)=4.5000daytime (t) = 4.5000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=215.0mg/L,rateconstant(k)=0.15001/day,time(t)=4.5000dayList the givens: ultimate BOD (L_{0}) = 215.0 mg/L, rate constant (k) = 0.1500 1/day, time (t) = 4.5000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=109.5 mg/LLt = 109.5\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 109.5 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=109.5 mg/LLt = 109.5\ \text{mg/L}

Why the other options are there

  • 218.9 — kept a factor of two that cancels in the correct rearrangement.
  • 54.7343 — dropped that same factor in the other direction.
  • 120.4 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 8
First-order BOD decay — solve for ultimate BOD (case 3) — Cyclone Effective Number of Turns Approximation (8)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.2700 1/day; time (t) = 2.5000 day; remaining BOD (Lt) = 389.5 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.27001/dayrate constant (k) = 0.2700 1/day
  • time(t)=2.5000daytime (t) = 2.5000 day
  • remainingBOD(Lt)=389.5mg/Lremaining BOD (Lt) = 389.5 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.27001/day,time(t)=2.5000day,remainingBOD(Lt)=389.5mg/LList the givens: rate constant (k) = 0.2700 1/day, time (t) = 2.5000 day, remaining BOD (Lt) = 389.5 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=765.0 mg/LL_{0} = 765.0\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 765.0 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=765.0 mg/LL_{0} = 765.0\ \text{mg/L}

Why the other options are there

  • 1,530 — kept a factor of two that cancels in the correct rearrangement.
  • 382.5 — dropped that same factor in the other direction.
  • 841.5 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 9
First-order BOD decay — solve for rate constant (case 3) — Cyclone Effective Number of Turns Approximation (9)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 315.0 mg/L; time (t) = 2.0000 day; remaining BOD (Lt) = 127.4 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=315.0mg/Lultimate BOD (L_{0}) = 315.0 mg/L
  • time(t)=2.0000daytime (t) = 2.0000 day
  • remainingBOD(Lt)=127.4mg/Lremaining BOD (Lt) = 127.4 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=315.0mg/L,time(t)=2.0000day,remainingBOD(Lt)=127.4mg/LList the givens: ultimate BOD (L_{0}) = 315.0 mg/L, time (t) = 2.0000 day, remaining BOD (Lt) = 127.4 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=0.4526 1/dayk = 0.4526\ \text{1/day}
  6. Step 6 — Check: returning k = 0.4526 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.4526 1/dayk = 0.4526\ \text{1/day}

Why the other options are there

  • 0.9052 — kept a factor of two that cancels in the correct rearrangement.
  • 0.2263 — dropped that same factor in the other direction.
  • 0.4979 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

Example 10
First-order BOD decay — solve for remaining BOD (case 4) — Cyclone Effective Number of Turns Approximation (10)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 140.0 mg/L; rate constant (k) = 0.2800 1/day; time (t) = 7.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=140.0mg/Lultimate BOD (L_{0}) = 140.0 mg/L
  • rateconstant(k)=0.28001/dayrate constant (k) = 0.2800 1/day
  • time(t)=7.0000daytime (t) = 7.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=140.0mg/L,rateconstant(k)=0.28001/day,time(t)=7.0000dayList the givens: ultimate BOD (L_{0}) = 140.0 mg/L, rate constant (k) = 0.2800 1/day, time (t) = 7.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=19.7202 mg/LLt = 19.7202\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 19.7202 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=19.7202 mg/LLt = 19.7202\ \text{mg/L}

Why the other options are there

  • 39.4404 — kept a factor of two that cancels in the correct rearrangement.
  • 9.8601 — dropped that same factor in the other direction.
  • 21.6922 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → Cyclone Effective Number of Turns Approximation

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