Skip to content

BOD Test Solution and Seeding Procedures

Environmental Engineering · FE Reference Handbook section

Environmental Engineering
8 formulas
10 exam-style examples
~60 min
All Environmental Engineering lectures

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • When the dilution of water is not seeded:
  • When the dilution of water is seeded:

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
First-order BOD decay — solve for remaining BOD — BOD Test Solution and Seeding Procedures

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 150.0 mg/L; rate constant (k) = 0.2800 1/day; time (t) = 8.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=150.0mg/Lultimate BOD (L_{0}) = 150.0 mg/L
  • rateconstant(k)=0.28001/dayrate constant (k) = 0.2800 1/day
  • time(t)=8.0000daytime (t) = 8.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=150.0mg/L,rateconstant(k)=0.28001/day,time(t)=8.0000dayList the givens: ultimate BOD (L_{0}) = 150.0 mg/L, rate constant (k) = 0.2800 1/day, time (t) = 8.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=15.9688 mg/LLt = 15.9688\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 15.9688 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=15.9688 mg/LLt = 15.9688\ \text{mg/L}

Why the other options are there

  • 31.9376 — kept a factor of two that cancels in the correct rearrangement.
  • 7.9844 — dropped that same factor in the other direction.
  • 17.5657 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 2
First-order BOD decay — solve for ultimate BOD — BOD Test Solution and Seeding Procedures (2)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.1700 1/day; time (t) = 8.0000 day; remaining BOD (Lt) = 40.4000 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.17001/dayrate constant (k) = 0.1700 1/day
  • time(t)=8.0000daytime (t) = 8.0000 day
  • remainingBOD(Lt)=40.4000mg/Lremaining BOD (Lt) = 40.4000 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.17001/day,time(t)=8.0000day,remainingBOD(Lt)=40.4000mg/LList the givens: rate constant (k) = 0.1700 1/day, time (t) = 8.0000 day, remaining BOD (Lt) = 40.4000 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=157.4 mg/LL_{0} = 157.4\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 157.4 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=157.4 mg/LL_{0} = 157.4\ \text{mg/L}

Why the other options are there

  • 314.8 — kept a factor of two that cancels in the correct rearrangement.
  • 78.7031 — dropped that same factor in the other direction.
  • 173.1 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 3
First-order BOD decay — solve for rate constant — BOD Test Solution and Seeding Procedures (3)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 215.0 mg/L; time (t) = 5.0000 day; remaining BOD (Lt) = 15.7000 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=215.0mg/Lultimate BOD (L_{0}) = 215.0 mg/L
  • time(t)=5.0000daytime (t) = 5.0000 day
  • remainingBOD(Lt)=15.7000mg/Lremaining BOD (Lt) = 15.7000 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=215.0mg/L,time(t)=5.0000day,remainingBOD(Lt)=15.7000mg/LList the givens: ultimate BOD (L_{0}) = 215.0 mg/L, time (t) = 5.0000 day, remaining BOD (Lt) = 15.7000 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=0.5234 1/dayk = 0.5234\ \text{1/day}
  6. Step 6 — Check: returning k = 0.5234 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.5234 1/dayk = 0.5234\ \text{1/day}

Why the other options are there

  • 1.0468 — kept a factor of two that cancels in the correct rearrangement.
  • 0.2617 — dropped that same factor in the other direction.
  • 0.5757 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 4
First-order BOD decay — solve for remaining BOD (case 2) — BOD Test Solution and Seeding Procedures (4)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 355.0 mg/L; rate constant (k) = 0.0600 1/day; time (t) = 8.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=355.0mg/Lultimate BOD (L_{0}) = 355.0 mg/L
  • rateconstant(k)=0.06001/dayrate constant (k) = 0.0600 1/day
  • time(t)=8.0000daytime (t) = 8.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=355.0mg/L,rateconstant(k)=0.06001/day,time(t)=8.0000dayList the givens: ultimate BOD (L_{0}) = 355.0 mg/L, rate constant (k) = 0.0600 1/day, time (t) = 8.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=219.7 mg/LLt = 219.7\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 219.7 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=219.7 mg/LLt = 219.7\ \text{mg/L}

Why the other options are there

  • 439.3 — kept a factor of two that cancels in the correct rearrangement.
  • 109.8 — dropped that same factor in the other direction.
  • 241.6 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 5
First-order BOD decay — solve for ultimate BOD (case 2) — BOD Test Solution and Seeding Procedures (5)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.1900 1/day; time (t) = 5.0000 day; remaining BOD (Lt) = 274.6 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.19001/dayrate constant (k) = 0.1900 1/day
  • time(t)=5.0000daytime (t) = 5.0000 day
  • remainingBOD(Lt)=274.6mg/Lremaining BOD (Lt) = 274.6 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.19001/day,time(t)=5.0000day,remainingBOD(Lt)=274.6mg/LList the givens: rate constant (k) = 0.1900 1/day, time (t) = 5.0000 day, remaining BOD (Lt) = 274.6 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=710.0 mg/LL_{0} = 710.0\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 710.0 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=710.0 mg/LL_{0} = 710.0\ \text{mg/L}

Why the other options are there

  • 1,420 — kept a factor of two that cancels in the correct rearrangement.
  • 355.0 — dropped that same factor in the other direction.
  • 781.0 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 6
First-order BOD decay — solve for rate constant (case 2) — BOD Test Solution and Seeding Procedures (6)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 205.0 mg/L; time (t) = 1.5000 day; remaining BOD (Lt) = 283.9 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=205.0mg/Lultimate BOD (L_{0}) = 205.0 mg/L
  • time(t)=1.5000daytime (t) = 1.5000 day
  • remainingBOD(Lt)=283.9mg/Lremaining BOD (Lt) = 283.9 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=205.0mg/L,time(t)=1.5000day,remainingBOD(Lt)=283.9mg/LList the givens: ultimate BOD (L_{0}) = 205.0 mg/L, time (t) = 1.5000 day, remaining BOD (Lt) = 283.9 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=−0.2171 1/dayk = -0.2171\ \text{1/day}
  6. Step 6 — Check: returning k = -0.2171 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=−0.2171 1/dayk = -0.2171\ \text{1/day}

Why the other options are there

  • -0.4341 — kept a factor of two that cancels in the correct rearrangement.
  • -0.1085 — dropped that same factor in the other direction.
  • -0.2388 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 7
First-order BOD decay — solve for remaining BOD (case 3) — BOD Test Solution and Seeding Procedures (7)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 220.0 mg/L; rate constant (k) = 0.1500 1/day; time (t) = 2.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=220.0mg/Lultimate BOD (L_{0}) = 220.0 mg/L
  • rateconstant(k)=0.15001/dayrate constant (k) = 0.1500 1/day
  • time(t)=2.0000daytime (t) = 2.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=220.0mg/L,rateconstant(k)=0.15001/day,time(t)=2.0000dayList the givens: ultimate BOD (L_{0}) = 220.0 mg/L, rate constant (k) = 0.1500 1/day, time (t) = 2.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=163.0 mg/LLt = 163.0\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 163.0 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=163.0 mg/LLt = 163.0\ \text{mg/L}

Why the other options are there

  • 326.0 — kept a factor of two that cancels in the correct rearrangement.
  • 81.4900 — dropped that same factor in the other direction.
  • 179.3 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 8
First-order BOD decay — solve for ultimate BOD (case 3) — BOD Test Solution and Seeding Procedures (8)

A environmental engineering problem uses First-order BOD decay. Given rate constant (k) = 0.2400 1/day; time (t) = 8.0000 day; remaining BOD (Lt) = 5.9000 mg/L, determine the ultimate BOD (L0) in mg/L.

Given

  • rateconstant(k)=0.24001/dayrate constant (k) = 0.2400 1/day
  • time(t)=8.0000daytime (t) = 8.0000 day
  • remainingBOD(Lt)=5.9000mg/Lremaining BOD (Lt) = 5.9000 mg/L

Find

ultimate BOD (L0), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except L0 is given, so isolate L0 symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that L0 stands alone on the left-hand side.

  3. Step 3

    Listthegivens:rateconstant(k)=0.24001/day,time(t)=8.0000day,remainingBOD(Lt)=5.9000mg/LList the givens: rate constant (k) = 0.2400 1/day, time (t) = 8.0000 day, remaining BOD (Lt) = 5.9000 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    L0=40.2437 mg/LL_{0} = 40.2437\ \text{mg/L}
  6. Step 6 — Check: returning L0 = 40.2437 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
L0=40.2437 mg/LL_{0} = 40.2437\ \text{mg/L}

Why the other options are there

  • 80.4873 — kept a factor of two that cancels in the correct rearrangement.
  • 20.1218 — dropped that same factor in the other direction.
  • 44.2680 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 9
First-order BOD decay — solve for rate constant (case 3) — BOD Test Solution and Seeding Procedures (9)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 140.0 mg/L; time (t) = 4.0000 day; remaining BOD (Lt) = 112.9 mg/L, determine the rate constant (k) in 1/day.

Given

  • ultimateBOD(L0)=140.0mg/Lultimate BOD (L_{0}) = 140.0 mg/L
  • time(t)=4.0000daytime (t) = 4.0000 day
  • remainingBOD(Lt)=112.9mg/Lremaining BOD (Lt) = 112.9 mg/L

Find

rate constant (k), in 1/day

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except k is given, so isolate k symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that k stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=140.0mg/L,time(t)=4.0000day,remainingBOD(Lt)=112.9mg/LList the givens: ultimate BOD (L_{0}) = 140.0 mg/L, time (t) = 4.0000 day, remaining BOD (Lt) = 112.9 mg/L
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    k=0.0538 1/dayk = 0.0538\ \text{1/day}
  6. Step 6 — Check: returning k = 0.0538 1/day to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
k=0.0538 1/dayk = 0.0538\ \text{1/day}

Why the other options are there

  • 0.1076 — kept a factor of two that cancels in the correct rearrangement.
  • 0.0269 — dropped that same factor in the other direction.
  • 0.0592 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

Example 10
First-order BOD decay — solve for remaining BOD (case 4) — BOD Test Solution and Seeding Procedures (10)

A environmental engineering problem uses First-order BOD decay. Given ultimate BOD (L0) = 355.0 mg/L; rate constant (k) = 0.2300 1/day; time (t) = 4.0000 day, determine the remaining BOD (Lt) in mg/L.

Given

  • ultimateBOD(L0)=355.0mg/Lultimate BOD (L_{0}) = 355.0 mg/L
  • rateconstant(k)=0.23001/dayrate constant (k) = 0.2300 1/day
  • time(t)=4.0000daytime (t) = 4.0000 day

Find

remaining BOD (Lt), in mg/L

Start with the thinking

  • The governing relation printed in this handbook section is First-order BOD decay.
  • Everything except Lt is given, so isolate Lt symbolically first — never rearrange after the numbers are in.
  • Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
  • Environmental Engineering items reward recognising the unknown before touching a calculator.

Step-by-step solution

  1. Step 1 — State the governing relation:

    Lt=L0e−ktL_t = L_0 e^{-k t}
  2. Step 2 — Rearrange the relation so that Lt stands alone on the left-hand side.

  3. Step 3

    Listthegivens:ultimateBOD(L0)=355.0mg/L,rateconstant(k)=0.23001/day,time(t)=4.0000dayList the givens: ultimate BOD (L_{0}) = 355.0 mg/L, rate constant (k) = 0.2300 1/day, time (t) = 4.0000 day
  4. Step 4 — Substitute the given values into the rearranged relation.

  5. Step 5 — Evaluate:

    Lt=141.5 mg/LLt = 141.5\ \text{mg/L}
  6. Step 6 — Check: returning Lt = 141.5 mg/L to

    Lt=L0e−ktL_t = L_0 e^{-k t}

    reproduces the given quantities, and both sides carry the same units.

Answer:
Lt=141.5 mg/LLt = 141.5\ \text{mg/L}

Why the other options are there

  • 282.9 — kept a factor of two that cancels in the correct rearrangement.
  • 70.7371 — dropped that same factor in the other direction.
  • 155.6 — rounded an intermediate value before the final step.

Reference: FE Reference Handbook — Environmental Engineering → BOD Test Solution and Seeding Procedures

© 2026 Dr. Steve Efe. Civil Engineering Capstone Studio. All rights reserved.