air stripping tower stripping factor for VOC removal from groundwater Given dimensionless Henry's constant (H) = 0.1110; air flow rate (Q_a) = 1,600 m^3/day; water flow rate (Q_w) = 3,160 m^3/day, determine the stripping factor (R).

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for R:

   $$R = \dfrac{HQ_a}{Q_w}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.1110, air flow rate (Q_a) = 1,600 m^3/day, water flow rate (Q_w) = 3,160 m^3/day.

4. Step 4 — Substitute the given values:

   $$R = \dfrac{HQ_a}{Q_w}$$

5. Step 5 — Evaluate:

   $$R = 0.0562$$

6. Step 6 — Check: returning R = 0.0562 to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 0.1124 — kept a factor of two that cancels in the correct rearrangement.
• 0.0281 — dropped that same factor in the other direction.
• 0.0618 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping design for removing volatile organics from drinking water Given dimensionless Henry's constant (H) = 0.7380; water flow rate (Q_w) = 12,930 m^3/day; stripping factor (R) = 9.0700, determine the air flow rate (Q_a) in m^3/day.

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except Q_a is given, so isolate Q_a symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for Q_a:

   $$Q_{a} = \dfrac{RQ_w}{H}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.7380, water flow rate (Q_w) = 12,930 m^3/day, stripping factor (R) = 9.0700.

4. Step 4 — Substitute the given values:

   $$Q_{a} = \dfrac{RQ_w}{0.7380}$$

5. Step 5 — Evaluate:

   Q_{a} = 158909\ \text{m^3/day}

6. Step 6 — Check: returning Q_a = 158,909 m^3/day to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 317,819 — kept a factor of two that cancels in the correct rearrangement.
• 79,455 — dropped that same factor in the other direction.
• 174,800 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping stripping factor computed from air-to-water ratio Given dimensionless Henry's constant (H) = 0.4350; air flow rate (Q_a) = 56,400 m^3/day; stripping factor (R) = 12.0400, determine the water flow rate (Q_w) in m^3/day.

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except Q_w is given, so isolate Q_w symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for Q_w:

   $$Q_{w} = \dfrac{HQ_a}{R}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.4350, air flow rate (Q_a) = 56,400 m^3/day, stripping factor (R) = 12.0400.

4. Step 4 — Substitute the given values:

   $$Q_{w} = \dfrac{HQ_a}{12.0400}$$

5. Step 5 — Evaluate:

   Q_{w} = 2038\ \text{m^3/day}

6. Step 6 — Check: returning Q_w = 2,038 m^3/day to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 4,075 — kept a factor of two that cancels in the correct rearrangement.
• 1,019 — dropped that same factor in the other direction.
• 2,241 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping tower stripping factor for VOC removal from groundwater Given dimensionless Henry's constant (H) = 0.4160; air flow rate (Q_a) = 2,700 m^3/day; water flow rate (Q_w) = 1,210 m^3/day, determine the stripping factor (R).

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for R:

   $$R = \dfrac{HQ_a}{Q_w}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.4160, air flow rate (Q_a) = 2,700 m^3/day, water flow rate (Q_w) = 1,210 m^3/day.

4. Step 4 — Substitute the given values:

   $$R = \dfrac{HQ_a}{Q_w}$$

5. Step 5 — Evaluate:

   $$R = 0.9283$$

6. Step 6 — Check: returning R = 0.9283 to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 1.8565 — kept a factor of two that cancels in the correct rearrangement.
• 0.4641 — dropped that same factor in the other direction.
• 1.0211 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping design for removing volatile organics from drinking water Given dimensionless Henry's constant (H) = 0.5260; water flow rate (Q_w) = 6,070 m^3/day; stripping factor (R) = 11.7900, determine the air flow rate (Q_a) in m^3/day.

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except Q_a is given, so isolate Q_a symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for Q_a:

   $$Q_{a} = \dfrac{RQ_w}{H}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.5260, water flow rate (Q_w) = 6,070 m^3/day, stripping factor (R) = 11.7900.

4. Step 4 — Substitute the given values:

   $$Q_{a} = \dfrac{RQ_w}{0.5260}$$

5. Step 5 — Evaluate:

   Q_{a} = 136056\ \text{m^3/day}

6. Step 6 — Check: returning Q_a = 136,056 m^3/day to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 272,111 — kept a factor of two that cancels in the correct rearrangement.
• 68,028 — dropped that same factor in the other direction.
• 149,661 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping stripping factor computed from air-to-water ratio Given dimensionless Henry's constant (H) = 0.8240; air flow rate (Q_a) = 34,200 m^3/day; stripping factor (R) = 9.0400, determine the water flow rate (Q_w) in m^3/day.

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except Q_w is given, so isolate Q_w symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for Q_w:

   $$Q_{w} = \dfrac{HQ_a}{R}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.8240, air flow rate (Q_a) = 34,200 m^3/day, stripping factor (R) = 9.0400.

4. Step 4 — Substitute the given values:

   $$Q_{w} = \dfrac{HQ_a}{9.0400}$$

5. Step 5 — Evaluate:

   Q_{w} = 3117\ \text{m^3/day}

6. Step 6 — Check: returning Q_w = 3,117 m^3/day to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 6,235 — kept a factor of two that cancels in the correct rearrangement.
• 1,559 — dropped that same factor in the other direction.
• 3,429 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping tower stripping factor for VOC removal from groundwater Given dimensionless Henry's constant (H) = 0.1230; air flow rate (Q_a) = 53,400 m^3/day; water flow rate (Q_w) = 17,520 m^3/day, determine the stripping factor (R).

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for R:

   $$R = \dfrac{HQ_a}{Q_w}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.1230, air flow rate (Q_a) = 53,400 m^3/day, water flow rate (Q_w) = 17,520 m^3/day.

4. Step 4 — Substitute the given values:

   $$R = \dfrac{HQ_a}{Q_w}$$

5. Step 5 — Evaluate:

   $$R = 0.3749$$

6. Step 6 — Check: returning R = 0.3749 to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 0.7498 — kept a factor of two that cancels in the correct rearrangement.
• 0.1874 — dropped that same factor in the other direction.
• 0.4124 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping design for removing volatile organics from drinking water Given dimensionless Henry's constant (H) = 0.3610; water flow rate (Q_w) = 11,660 m^3/day; stripping factor (R) = 1.1100, determine the air flow rate (Q_a) in m^3/day.

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except Q_a is given, so isolate Q_a symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for Q_a:

   $$Q_{a} = \dfrac{RQ_w}{H}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.3610, water flow rate (Q_w) = 11,660 m^3/day, stripping factor (R) = 1.1100.

4. Step 4 — Substitute the given values:

   $$Q_{a} = \dfrac{RQ_w}{0.3610}$$

5. Step 5 — Evaluate:

   Q_{a} = 35852\ \text{m^3/day}

6. Step 6 — Check: returning Q_a = 35,852 m^3/day to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 71,704 — kept a factor of two that cancels in the correct rearrangement.
• 17,926 — dropped that same factor in the other direction.
• 39,437 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping stripping factor computed from air-to-water ratio Given dimensionless Henry's constant (H) = 0.2950; air flow rate (Q_a) = 28,700 m^3/day; stripping factor (R) = 17.5700, determine the water flow rate (Q_w) in m^3/day.

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except Q_w is given, so isolate Q_w symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for Q_w:

   $$Q_{w} = \dfrac{HQ_a}{R}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.2950, air flow rate (Q_a) = 28,700 m^3/day, stripping factor (R) = 17.5700.

4. Step 4 — Substitute the given values:

   $$Q_{w} = \dfrac{HQ_a}{17.5700}$$

5. Step 5 — Evaluate:

   Q_{w} = 481.9\ \text{m^3/day}

6. Step 6 — Check: returning Q_w = 481.9 m^3/day to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 963.7 — kept a factor of two that cancels in the correct rearrangement.
• 240.9 — dropped that same factor in the other direction.
• 530.1 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping

air stripping tower stripping factor for VOC removal from groundwater Given dimensionless Henry's constant (H) = 0.6310; air flow rate (Q_a) = 46,900 m^3/day; water flow rate (Q_w) = 17,400 m^3/day, determine the stripping factor (R).

Start with the thinking

• The governing relation printed in this handbook section is Air Stripping.
• Everything except R is given, so isolate R symbolically first — never rearrange after the numbers are in.
• Tabulate each given with its unit and confirm the units are consistent with the relation before substituting.
• Air stripping removes volatile contaminants from water by contacting it with air, characterized by the stripping factor.

Step-by-step solution

1. Step 1 — State the governing relation:

   $$R = \dfrac{H Q_a}{Q_w}$$

2. Step 2 — Rearrange symbolically for R:

   $$R = \dfrac{HQ_a}{Q_w}$$

3. Step 3 — List the givens: dimensionless Henry's constant (H) = 0.6310, air flow rate (Q_a) = 46,900 m^3/day, water flow rate (Q_w) = 17,400 m^3/day.

4. Step 4 — Substitute the given values:

   $$R = \dfrac{HQ_a}{Q_w}$$

5. Step 5 — Evaluate:

   $$R = 1.7008$$

6. Step 6 — Check: returning R = 1.7008 to

   $$R = \dfrac{H Q_a}{Q_w}$$

   reproduces the given quantities, and both sides carry the same units.

Why the other options are there

• 3.4016 — kept a factor of two that cancels in the correct rearrangement.
• 0.8504 — dropped that same factor in the other direction.
• 1.8709 — rounded an intermediate value before the final step.

Reference: FE Handbook — Air Stripping