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Breakeven Analysis

Engineering Economics · FE Reference Handbook section

Engineering Economics
0 formulas
10 exam-style examples
~45 min
All Engineering Economics lectures

Learning objectives

What you must be able to do before leaving this section.

This chapter section covers Breakeven Analysis within Engineering Economics. Read it the way you would read a textbook chapter: the theory first so the relations mean something, then every equation with its use and its trap, then 10 fully worked examples with the arithmetic shown line by line, and finally a self-check you should be able to answer without notes.

  • Explain, in your own words, what breakeven analysis describes physically and when it applies.
  • State every one of the 0 relations the handbook lists here and name each symbol with its unit.
  • Select the correct relation from the wording of an exam stem within 20 seconds.
  • Carry a complete solution from givens to a "most nearly" answer with the correct unit.
  • Recognise the distractors generated by the unit trap: i per period must match n periods.

Lecture

Why this section exists. Breakeven Analysis is the part of Engineering Economics that lets you connect an alternative being compared over a study period to a number you can defend. Before any equation is useful you must be able to picture the physical situation it describes; the schematic below is that picture.

How the theory is built. The handbook prints results, not derivations. Each relation in this section comes from one governing principle applied to the idealised system: state the principle, impose the stated assumptions, and the printed equation follows. Knowing which assumption each relation rests on is what lets you reject a wrong answer choice in seconds.

How it is examined. Items from this page are written as one cash-flow diagram converted with one factor. Roughly two thirds are direct substitution, one third require one intermediate quantity from a neighbouring relation, and a small number are conceptual — testing whether you know the assumption, not the arithmetic.

The habit that earns the points. Unit discipline. i per period must match n periods. Every relation below is dimensionally consistent only when that rule is honoured, and the distractor set is deliberately built from candidates who ignored it. Write the unit next to every number you substitute, every time.

How to study this page. Read the theory, then cover the formula cards and try to reproduce each relation from its description. Then work the examples with the solution hidden, revealing one line at a time. Finish with the self-check questions; if you cannot answer one, return to the matching formula card.

Three engineers in hard hats and safety vests reviewing drawings on a truck tailgate.

Photo 1. Where this shows up in practice: breakeven analysis.

Capstone Studio instructional photograph

period ncash flowCash-flow profileArrows up = receipts

Engineering Economics — Breakeven Analysis: reference schematic for orienting the symbols used in this section.

Theory, developed

Read this before the equations — it is what makes them memorable.

The physical situation

Every item from this section describes an alternative being compared over a study period. Sketch it before you compute — a labelled sketch with the givens on it converts a wordy stem into a solvable problem and exposes the quantity the examiner left out on purpose.

The governing principle

The 0 relations on this page are consequences of one principle applied to that idealised system. Identify which quantity is conserved, balanced, or defined, and the correct equation follows without memorisation.

Assumptions and limits of validity

Each printed relation carries silent assumptions — linearity, steady state, uniformity, small deformation, or standard conditions, depending on the subject. Conceptual exam items are written by violating exactly one of these, so read the sentence above the equation as carefully as the equation itself.

Solution procedure you should automate

1) Read the last sentence of the stem to identify the requested quantity. 2) Locate the relation on this page whose left-hand side is that quantity. 3) Tabulate the givens with units and mark the missing symbol. 4) If a symbol is missing, find the one relation that produces it. 5) Rearrange symbolically, substitute once, evaluate, and round only at the end.

Three engineers in hard hats and safety vests reviewing drawings on a truck tailgate.

Photo 2. Engineering Economics: the physical system the theory above idealises.

Capstone Studio instructional photograph

Handbook notes for this section

Definitions and conditions exactly as the handbook states them.

  • By altering the value of any one of the variables in a situation, holding all of the other values constant, it is possible to find a
  • value for that variable that makes the two alternatives equally economical. This value is the breakeven point.
  • Breakeven analysis is used to describe the percentage of capacity of operation for a manufacturing plant at which income will
  • just cover expenses.
  • The payback period is the period of time required for the profit or other benefits of an investment to equal the cost of the
  • investment.

Core formulas for this FE topic

Definitions, applicability, units, assumptions and worked examples for each relation.

This section is conceptual; there are no equations to memorise.

Worked exam-style examples

The four ways this section is written on the real exam — thoughts first, then equations, then substitution.

Example 1
Break-even production quantity — Breakeven Analysis

A precast plant has $41,000 fixed annual cost, $25.50 variable cost per unit, and sells units at $33.00. What annual output breaks even?

Given

  • Fixed = $41,000
  • v = $25.50/unit
  • p = $33.00/unit

Find

Break-even quantity Q

Start with the thinking

  • Break-even sets total revenue equal to total cost.
  • The contribution margin is p − v.

Step-by-step solution

  1. Balance

  2. Rearrange

  3. Contribution margin — p − v = $33.00 − $25.50 = $7.50/unit

  4. Substituting — Q = $41,000/$7.50 = 5,467 units/yr

Answer: Q ≈ 5,467 units per year

Why the other options are there

  • 1,242 units (variable cost ignored)
  • 1,608 units (price ignored)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 2
Rate of return on an equipment investment, before and after tax — Breakeven Analysis

A contractor invests $119,000 in equipment that returns $25,000 per year for 5 years with no salvage. Determine the rate of return, and estimate the after-tax return at a 35% tax rate on the net income.

Given

  • P = $119,000
  • A = $25,000/yr
  • n = 5 yr
  • Tax rate = 35%

Find

Before-tax rate of return and an after-tax estimate

Start with the thinking

  • The rate of return is the interest rate that makes present worth zero — solved by trial or by the calculator's IRR.
  • A quick after-tax screen scales the annual return by (1 − tax rate) and re-solves.

Step-by-step solution

  1. Formula

  2. Set up

  3. Solve for i

  4. After-tax cash flow — A_at = A(1 − t) = $25,000(1 − 0.35) = $16,250

  5. After-tax (P/A) required — 7.3231

  6. Solve again — i_at ≈ 0.01%

Answer: Before-tax ROR ≈ 1.66% per year

Why the other options are there

  • 5.0% (simple total return)
  • 21.0% (ignored the time value of money)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 3
Break-even production quantity — Breakeven Analysis (2)

A precast plant has $119,000 fixed annual cost, $10.00 variable cost per unit, and sells units at $23.00. What annual output breaks even?

Given

  • Fixed = $119,000
  • v = $10.00/unit
  • p = $23.00/unit

Find

Break-even quantity Q

Start with the thinking

  • Break-even sets total revenue equal to total cost.
  • The contribution margin is p − v.

Step-by-step solution

  1. Balance

  2. Rearrange

  3. Contribution margin — p − v = $23.00 − $10.00 = $13.00/unit

  4. Substituting — Q = $119,000/$13.00 = 9,154 units/yr

Answer: Q ≈ 9,154 units per year

Why the other options are there

  • 5,174 units (variable cost ignored)
  • 11,900 units (price ignored)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 4
Rate of return on an equipment investment, before and after tax — Breakeven Analysis (2)

A contractor invests $85,000 in equipment that returns $18,000 per year for 8 years with no salvage. Determine the rate of return, and estimate the after-tax return at a 27% tax rate on the net income.

Given

  • P = $85,000
  • A = $18,000/yr
  • n = 8 yr
  • Tax rate = 27%

Find

Before-tax rate of return and an after-tax estimate

Start with the thinking

  • The rate of return is the interest rate that makes present worth zero — solved by trial or by the calculator's IRR.
  • A quick after-tax screen scales the annual return by (1 − tax rate) and re-solves.

Step-by-step solution

  1. Formula

  2. Set up

  3. Solve for i

  4. After-tax cash flow — A_at = A(1 − t) = $18,000(1 − 0.27) = $13,140

  5. After-tax (P/A) required — 6.4688

  6. Solve again — i_at ≈ 4.98%

Answer: Before-tax ROR ≈ 13.47% per year

Why the other options are there

  • 69.4% (simple total return)
  • 21.2% (ignored the time value of money)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 5
Break-even production quantity — Breakeven Analysis (3)

A precast plant has $90,000 fixed annual cost, $17.00 variable cost per unit, and sells units at $32.50. What annual output breaks even?

Given

  • Fixed = $90,000
  • v = $17.00/unit
  • p = $32.50/unit

Find

Break-even quantity Q

Start with the thinking

  • Break-even sets total revenue equal to total cost.
  • The contribution margin is p − v.

Step-by-step solution

  1. Balance

  2. Rearrange

  3. Contribution margin — p − v = $32.50 − $17.00 = $15.50/unit

  4. Substituting — Q = $90,000/$15.50 = 5,806 units/yr

Answer: Q ≈ 5,806 units per year

Why the other options are there

  • 2,769 units (variable cost ignored)
  • 5,294 units (price ignored)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 6
Rate of return on an equipment investment, before and after tax — Breakeven Analysis (3)

A contractor invests $106,000 in equipment that returns $22,000 per year for 10 years with no salvage. Determine the rate of return, and estimate the after-tax return at a 32% tax rate on the net income.

Given

  • P = $106,000
  • A = $22,000/yr
  • n = 10 yr
  • Tax rate = 32%

Find

Before-tax rate of return and an after-tax estimate

Start with the thinking

  • The rate of return is the interest rate that makes present worth zero — solved by trial or by the calculator's IRR.
  • A quick after-tax screen scales the annual return by (1 − tax rate) and re-solves.

Step-by-step solution

  1. Formula

  2. Set up

  3. Solve for i

  4. After-tax cash flow — A_at = A(1 − t) = $22,000(1 − 0.32) = $14,960

  5. After-tax (P/A) required — 7.0856

  6. Solve again — i_at ≈ 6.81%

Answer: Before-tax ROR ≈ 16.08% per year

Why the other options are there

  • 107.5% (simple total return)
  • 20.8% (ignored the time value of money)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 7
Break-even production quantity — Breakeven Analysis (4)

A precast plant has $135,000 fixed annual cost, $9.00 variable cost per unit, and sells units at $20.00. What annual output breaks even?

Given

  • Fixed = $135,000
  • v = $9.00/unit
  • p = $20.00/unit

Find

Break-even quantity Q

Start with the thinking

  • Break-even sets total revenue equal to total cost.
  • The contribution margin is p − v.

Step-by-step solution

  1. Balance

  2. Rearrange

  3. Contribution margin — p − v = $20.00 − $9.00 = $11.00/unit

  4. Substituting — Q = $135,000/$11.00 = 12,273 units/yr

Answer: Q ≈ 12,273 units per year

Why the other options are there

  • 6,750 units (variable cost ignored)
  • 15,000 units (price ignored)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 8
Rate of return on an equipment investment, before and after tax — Breakeven Analysis (4)

A contractor invests $135,000 in equipment that returns $33,000 per year for 10 years with no salvage. Determine the rate of return, and estimate the after-tax return at a 31% tax rate on the net income.

Given

  • P = $135,000
  • A = $33,000/yr
  • n = 10 yr
  • Tax rate = 31%

Find

Before-tax rate of return and an after-tax estimate

Start with the thinking

  • The rate of return is the interest rate that makes present worth zero — solved by trial or by the calculator's IRR.
  • A quick after-tax screen scales the annual return by (1 − tax rate) and re-solves.

Step-by-step solution

  1. Formula

  2. Set up

  3. Solve for i

  4. After-tax cash flow — A_at = A(1 − t) = $33,000(1 − 0.31) = $22,770

  5. After-tax (P/A) required — 5.9289

  6. Solve again — i_at ≈ 10.84%

Answer: Before-tax ROR ≈ 20.73% per year

Why the other options are there

  • 144.4% (simple total return)
  • 24.4% (ignored the time value of money)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 9
Break-even production quantity — Breakeven Analysis (5)

A precast plant has $158,000 fixed annual cost, $24.50 variable cost per unit, and sells units at $43.00. What annual output breaks even?

Given

  • Fixed = $158,000
  • v = $24.50/unit
  • p = $43.00/unit

Find

Break-even quantity Q

Start with the thinking

  • Break-even sets total revenue equal to total cost.
  • The contribution margin is p − v.

Step-by-step solution

  1. Balance

  2. Rearrange

  3. Contribution margin — p − v = $43.00 − $24.50 = $18.50/unit

  4. Substituting — Q = $158,000/$18.50 = 8,541 units/yr

Answer: Q ≈ 8,541 units per year

Why the other options are there

  • 3,674 units (variable cost ignored)
  • 6,449 units (price ignored)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Example 10
Rate of return on an equipment investment, before and after tax — Breakeven Analysis (5)

A contractor invests $200,000 in equipment that returns $33,000 per year for 8 years with no salvage. Determine the rate of return, and estimate the after-tax return at a 25% tax rate on the net income.

Given

  • P = $200,000
  • A = $33,000/yr
  • n = 8 yr
  • Tax rate = 25%

Find

Before-tax rate of return and an after-tax estimate

Start with the thinking

  • The rate of return is the interest rate that makes present worth zero — solved by trial or by the calculator's IRR.
  • A quick after-tax screen scales the annual return by (1 − tax rate) and re-solves.

Step-by-step solution

  1. Formula

  2. Set up

  3. Solve for i

  4. After-tax cash flow — A_at = A(1 − t) = $33,000(1 − 0.25) = $24,750

  5. After-tax (P/A) required — 8.0808

  6. Solve again — i_at ≈ 0.01%

Answer: Before-tax ROR ≈ 6.62% per year

Why the other options are there

  • 32.0% (simple total return)
  • 16.5% (ignored the time value of money)

Reference: FE Reference Handbook — Engineering Economics → Breakeven Analysis

Self-check

Answer these without notes before moving on.

  1. Without looking, state the relation on this page whose left-hand side is the quantity most often requested, and name every symbol in it.
  2. Which assumption, if violated, makes the main relation of this section invalid?
  3. Given an alternative being compared over a study period, what is the first quantity you would compute, and why that one first?
  4. Which unit conversion in this subject most often produces a wrong answer choice, and what is its numerical factor?
  5. Rework Example 1 above from the givens alone, without reading the solution lines.

Chapter summary

  • Breakeven Analysis contains 0 relations; you must be able to find this page in under 15 seconds.
  • Exam style: one cash-flow diagram converted with one factor.
  • Unit rule: i per period must match n periods.
  • Work the 10 examples until the solution path, not the answer, is automatic.

Common traps in this section

  • i per period must match n periods
  • Answering the intermediate quantity instead of the quantity requested.
  • Rounding intermediate values before the final step.
  • Using a relation from an adjacent handbook section that shares a symbol.
  • Skipping the sketch — most lost points on this page start with a misread geometry.
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